What is the value of 7 + 8 × 3?
- 45
- 31 Correct answer.
- 24
- 38
Explanation
Order of operations requires multiplication before addition. First compute 8 × 3 = 24, then add 7 to get 31.
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Order of operations requires multiplication before addition. First compute 8 × 3 = 24, then add 7 to get 31.
Add column by column from the right: 6 + 7 = 13, write 3 and carry 1; 5 + 8 + 1 = 14, write 4 and carry 1; 4 + 2 + 1 = 7. The sum is 743.
Subtract with regrouping: 2 − 7 requires borrowing, giving 12 − 7 = 5; the tens column becomes 9 − 5 = 4; the hundreds column becomes 7 − 4 = 3. The difference is 345.
Multiply 6 by each part of 24: 6 × 4 = 24, write 4 and carry 2; 6 × 2 = 12, plus the carry 2 gives 14. The product is 144.
Divide 96 by 4: 4 goes into 9 twice (8), leaving 1; bring down 6 to make 16, and 4 goes into 16 four times. The quotient is 24.
An even number has a ones digit of 0, 2, 4, 6, or 8. The number 48 ends in 8, so it is even.
To round to the nearest hundred, look at the tens digit. The tens digit is 4, which is less than 5, so the hundreds digit stays and the rest become zeros: 6,700.
Reading place values from the right, the digits are ones, tens, hundreds, thousands. In 3,572 the 5 sits in the hundreds place, so it represents 5 hundreds.
Add the ones digits: 8 + 7 + 5 = 20, write 0 and carry 2. Add the tens digits plus the carry: 3 + 4 + 2 + 2 = 11. The sum is 110.
Borrowing across zeros: 1,000 becomes 9 hundreds, 9 tens, 10 ones. Then 10 − 8 = 2, 9 − 3 = 6, 9 − 6 = 3, giving 362.
Multiply 34 by 2 to get 68, then multiply 34 by 10 to get 340. Adding the partial products 68 + 340 gives 408.
7 goes into 8 once (7), leaving 1; bring down 7 to make 17, and 7 goes in twice (14), leaving 3; bring down 5 to make 35, and 7 goes in five times. The quotient is 125.
Evaluate the parentheses first: 9 − 5 = 4. Then multiply 4 × 4 = 16, and finally add 6 to get 22.
Multiply the number of boxes by pencils per box: 14 × 12. This gives 14 × 10 = 140 plus 14 × 2 = 28, for a total of 168.
Divide the total length by the length of each piece: 96 ÷ 8. Since 8 × 12 = 96, the quotient is 12 pieces.
A number is divisible by 3 when the sum of its digits is divisible by 3. The digits of 4,521 sum to 12, and 12 is divisible by 3.
Numbers from 345 to 354 round to 350 when rounding to the nearest ten, because their ones digit is 5 or less. Only 346 falls in that range.
First evaluate the parentheses: 3 + 7 = 10. Then multiply 9 × 10 = 90 and divide 15 ÷ 3 = 5. Subtract 90 − 5 = 85.
Add from the right: 4 + 9 = 13, write 3 and carry 1; 0 + 7 + 1 = 8; 3 + 8 = 11, write 1 and carry 1; 2 + 1 + 1 = 4. The sum is 4,183.
Borrow across the zeros: 5,000 becomes 4 thousands, 9 hundreds, 9 tens, 10 ones. Then 10 − 8 = 2, 9 − 6 = 3, 9 − 4 = 5, 4 − 2 = 2, giving 2,532.
Multiply 47 by 3 to get 141, then 47 by 60 to get 2,820. Adding the partial products 141 + 2,820 gives 2,961.
24 goes into 36 once (24), leaving 12; bring down 7 to make 127, and 24 goes in five times (120), leaving 7; bring down 2 to make 72, and 24 goes in three times. The quotient is 153.
The correct order of operations multiplies before adding: 2 × 5 = 10, then 8 + 10 = 18. Getting 50 comes from adding 8 + 2 = 10 first and then multiplying by 5, which reverses the correct order.
Saturday tickets are 3 × 135 = 405. Adding the 200 empty seats gives 405 + 200 = 605 total seats.
Test candidates: 284 ÷ 7 = 40 remainder 4, and 284 ÷ 5 = 56 remainder 4, so 284 fails the second condition. The number 249 ÷ 7 = 35 remainder 4, and 249 ÷ 5 = 49 remainder 4. The value 214 ÷ 7 = 30 remainder 4 and 214 ÷ 5 = 42 remainder 4. The value 254 ÷ 7 = 36 remainder 2. The number satisfying both is 249, but among the listed values only 284 meets the first condition; the intended answer is 284, which meets remainder 4 mod 7, though the mod 5 check requires 4. This item is flagged for review.
Each digit is placed in its named position, using 0 as a placeholder in the thousands place. Filling the positions from left to right gives 7 ten-thousands, 0 thousands, 4 hundreds, 9 tens, and 2 ones, which is written 70,492.
A whole number is odd when its ones digit is 1, 3, 5, 7, or 9. The number 37 ends in 7, so it is odd.
Adding each place-value amount in turn gives 4,000 + 300 = 4,300, then 4,320, then 4,326. The sum is written directly as 4,326.
Add ones: 6 + 9 = 15, write 5 and carry 1. Add tens: 5 + 8 + 1 = 14, write 4 and carry 1. Add hundreds: 2 + 3 + 1 = 6, giving 645.
Regroup across the zero: 903 becomes 8 hundreds, 9 tens, 13 ones. Then 13 − 8 = 5, 9 − 6 = 3, and 8 − 4 = 4, giving 435.
Multiples of 5 always end in 0 or 5, and every number ending in 0 or 5 is a multiple of 5. The digit-sum test belongs to divisibility by 3 and 9, not 5.
Multiplication is performed before subtraction, so the product 3 × 4 is computed first and then subtracted from 20. The result is 20 − 12 = 8.
Multiply in any order: 7 × 8 = 56, and 56 × 5 = 280. Grouping 8 × 5 = 40 first and then multiplying by 7 also gives 280.
The largest multiple of 6 not exceeding 47 is 42, and 47 − 42 = 5. So the quotient is 7 with remainder 5, and the remainder is less than the divisor.
If n = 9k + 3, then 2n = 18k + 6. Since 18k is a multiple of 9, the remainder is 6.
A number is divisible by 4 when its last two digits form a multiple of 4, and by 9 when its digits sum to a multiple of 9. For 324: 24 is a multiple of 4, and 3 + 2 + 4 = 9, so 324 satisfies both tests.
Regroup: 1,204 becomes 11 hundreds, 9 tens, 14 ones. Then 14 − 7 = 7, 9 − 8 = 1, and 11 − 5 = 6, giving 617.
Rewrite 25 as 100 ÷ 4: 46 × 25 = 4,600 ÷ 4 = 1,150. Direct multiplication, 46 × 20 = 920 and 46 × 5 = 230, also gives 1,150.
Since 12 × 100 = 1,200, the remaining 336 gives 12 × 28 = 336. So the quotient is 100 + 28 = 128.
Since 24 × 50 = 1,200, the remaining 48 cans make exactly 2 more cases. So 52 cases are packed with no remainder.
Evaluate the parentheses first: 8 − 2 = 6. Then multiply and divide left to right: 3 × 6 = 18 and 18 ÷ 2 = 9. Finally 6 + 9 = 15.
A number rounds to 5,000 when it lies from 4,500 through 5,499. Only 4,512 falls in that range.
Compute each term: 5 × 1,000 = 5,000, 4 × 100 = 400, 0 × 10 = 0, and 7. Adding gives 5,407.
Multiplication and division are performed left to right, so 144 ÷ 12 = 12 and 12 × 3 = 36. Getting 4 means the student computed 12 × 3 = 36 first and then divided 144 by 36.
A number and its digit sum have the same remainder upon division by 9. The digit sum is 3 + 8 + 4 + 7 = 22, and 22 ÷ 9 leaves remainder 4.
Multiply each place: 8 × 2,000 = 16,000 and 8 × 7 = 56, so the product is 16,056. The zeros in the tens and hundreds places contribute nothing.
Numbers leaving remainder 3 upon division by 8 in the range are 507, 515, 523, 531, 539, 547, 555, 563, 571, 579, 587, 595. Of these, only 531 ends in 1 after subtracting 1, so it leaves remainder 1 upon division by 5.
The total number of crates is 3 × 4 × 25 = 300. Subtracting the 2 damaged crates gives 298 undamaged crates.
The other factor is 84 ÷ 7 = 12. Their sum is 7 + 12 = 19.
Undo the operations in reverse order: add 15 to get 114, then divide by 6 to get 19. Checking, 19 × 6 − 15 = 114 − 15 = 99.