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The Sealed Vessel and the Shifting Equilibrium

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The Sealed Vessel and the Shifting Equilibrium

A 2.0 L rigid steel vessel at 700 K is charged with 0.40 mol H2, 0.40 mol I2, and 1.20 mol HI. The reaction H2(g) + I2(g) ⇌ 2 HI(g) has Kc = 54.3 at 700 K. A technician argues that because there are equal moles of gas on each side, adding more HI can never change the equilibrium position, and therefore the vessel is already at equilibrium. A second technician measures the pressure and notes it is higher than expected for 2.0 mol of gas and suspects a leak of H2 through a valve seal. The vessel is then compressed to 1.0 L with a piston while temperature is held at 700 K.

1. Determine whether the initial mixture is at equilibrium and, if not, the direction in which it must shift.

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Compute the reaction quotient with concentrations.

  • [H2] = [I2] = 0.40/2.0 = 0.200 M
  • [HI] = 1.20/2.0 = 0.600 M
  • Qc = [HI]²/([H2][I2]) = (0.600)²/(0.200 × 0.200) = 0.360/0.0400 = 9.0

Qc = 9.0 < Kc = 54.3, so the system is not at equilibrium; it must shift toward products (right) to raise Qc to 54.3.

The technician's claim is wrong: equal moles of gas on each side means pressure/volume changes do not shift this equilibrium, but adding or removing a species still changes Qc, so composition changes do shift it.

2. Predict the effect of compressing to 1.0 L at constant temperature, and explain whether the leak hypothesis is consistent with the equal-moles argument.

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Compression: Δn_gas = 2 − 2 = 0, so Kc is unchanged and the equilibrium position is unaffected by volume change. All concentrations double, but Qc = (2[HI])²/((2[H2])(2[I2])) = Qc, so no shift occurs. Only the rate of both forward and reverse reactions increases.

Leak hypothesis: If H2 leaks, [H2] falls, Qc = [HI]²/([H2][I2]) rises, and the system shifts left, consuming HI and producing more H2 and I2. This is fully consistent - the equal-moles rule only protects against pressure/volume changes, not against removal of a component. The technician conflated the two effects. A pressure lower than expected for the stated moles supports a leak, but the composition shift would partly offset the mole loss.