BGCSE Chemistry 0570 study materials
BGCSE Chemistry 0570 study resources

BGCSE Chemistry 0570: Formulae, Equations and the Mole Concept

BGCSE Chemistry 0570 · Work through your exam, one topic at a time.

All guide sections

Formulae, Equations and the Mole Concept

Core ideas

A chemical formula shows the ratio of atoms in a compound. A word equation names reactants and products; a symbol equation uses formulas and must be balanced so atoms are conserved. State symbols (s), (l), (g), (aq) may be required.

The mole is the amount of substance containing 6.02 × 10²³ particles (Avogadro constant). Key relationships: mass = moles × molar mass; moles of gas = volume / 24 dm³ at room temperature and pressure; concentration = moles / volume in dm³. Relative formula mass is the sum of relative atomic masses in the formula. Percentage yield and empirical formula calculations are common.

Traps to watch

  • Always balance equations before using mole ratios; the coefficients give the reacting ratio.
  • Convert cm³ to dm³ by dividing by 1000.
  • Percentage yield is actual/theoretical × 100, not the reverse.
  • Empirical formula uses the simplest whole-number ratio, not molecular formula.

Rule of thumb

Use the mole triangle: cover what you want. mass = moles × Mr; moles = mass ÷ Mr; moles = concentration × volume (dm³).

Worked example

Calculate the mass of 0.25 mol of CaCO₃ (Mr = 100). Mass = 0.25 × 100 = 25 g.