QC Sec 4 Science & Tech study materials
QC Sec 4 Science & Tech study resources

QC Sec 4 Science & Tech: Technology Systems and Applied Problem Solving

QC Sec 4 Science & Tech · Work through your exam, one topic at a time.

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Technology Systems and Applied Problem Solving

This domain tests applied problem solving in technological systems: describing a system by its inputs, processes and outputs, applying the design process against a set of specifications, and calculating quantities such as gear ratios, mechanical advantage or scale on a technical drawing.

Systems thinking

  • Inputs - energy, material and information entering the system.
  • Process - the transformation, which is the function.
  • Outputs - the intended product plus by-products such as heat, noise or waste.
  • Feedback - a signal from the output that adjusts the process; a thermostat is the standard example.
  • Systems contain subsystems: a bicycle includes a transmission subsystem and a braking subsystem.

The design process

Specifications define the problem through function, constraints and criteria. Constraints are non-negotiable limits (budget, maximum mass, safety standard, supply voltage); criteria are optimised (durability, cost, ease of use). The cycle runs: define, research, sketch or prototype, test, evaluate against the specifications, improve. A technical drawing is a communication, so it needs a scale, a title block, dimensions in millimetres and a legend.

Mechanisms

  • Gear train: ratio = teeth on driven gear ÷ teeth on driver gear. The driven gear turns more slowly by that factor, with proportionally greater torque.
  • Pulley systems: a movable pulley halves the effort force but doubles the rope length pulled.
  • The trade-off is universal: force and speed cannot both be gained.
  • Efficiency = useful output energy ÷ input energy, and is always below 100 % because of friction and heat.

Worked example

A 12-tooth driver gear on a motor spins at 120 rpm and meshes with a 36-tooth driven gear. Ratio = 36 ÷ 12 = 3. Output speed = 120 ÷ 3 = 40 rpm. The output torque is roughly three times the motor torque minus friction losses, so the system trades speed for force. That is well matched to lifting a heavy load slowly.

Traps

  • Inverting the gear ratio by multiplying when you should divide.
  • Forgetting that real machines lose energy, so output work is less than input work.
  • Confusing a constraint with a criterion, or proposing a solution that violates a stated constraint.
  • Reading a technical drawing without checking its scale and units.
  • Describing what a device is instead of what it does; always state the function first.