CLEP College Algebra study materials
CLEP College Algebra study resources

CLEP College Algebra: Functions and Their Properties

CLEP College Algebra · Work through your exam, one topic at a time.

All guide sections

Functions and Their Properties

What this domain tests

The Functions and their properties domain tests the function concept across algebraic and graphical representations: notation, domain and range, composition, inverses, transformations, and basic behavior of parent functions. CLEP College Algebra favors questions that combine two ideas, such as finding the domain of a composition.

Domain and range

  • The domain is the set of allowed inputs. Exclude values that make a denominator zero and, for even roots, values that make the radicand negative.
  • The range is the set of outputs. Use the graph, vertex, asymptotes, or end behavior to determine it.
  • Express domains and ranges in interval notation, using parentheses at excluded values and infinities.

Composition and inverses

  • $(f\circ g)(x)=f(g(x))$. Its domain requires $x$ in the domain of $g$ and $g(x)$ in the domain of $f$.
  • An inverse exists only for a one-to-one function; the horizontal line test detects whether each output has a unique input.
  • To find an inverse, swap $x$ and $y$ and solve for $y$. The domain and range of $f$ and $f^{-1}$ interchange, and $f(f^{-1}(x))=x$ on the appropriate domain.

Transformations and parent graphs

  • $y=f(x-h)+k$ shifts the graph $h$ units right and $k$ units up.
  • $y=af(x)$ stretches vertically when $|a|>1$ and compresses when $0<|a|<1$; negative $a$ reflects across the $x$-axis.
  • $y=f(-x)$ reflects across the $y$-axis. Apply transformations in a consistent order, handling horizontal shifts and scalings inside the argument carefully.

Worked example

Find the inverse of $f(x)=\frac{2x+1}{x-3}$.

Write $y=\frac{2x+1}{x-3}$ and swap: $x=\frac{2y+1}{y-3}$. Multiply: $x(y-3)=2y+1$, so $xy-3x=2y+1$. Collect $y$ terms: $xy-2y=3x+1$, hence $y(x-2)=3x+1$ and $y=\frac{3x+1}{x-2}$. Thus $f^{-1}(x)=\frac{3x+1}{x-2}$, with $x\ne2$. The original function excludes $x=3$ from its domain, and its inverse excludes $x=2$ from its domain, matching the range restriction.

Traps that cost marks

  • Assuming $f(g(x))=g(f(x))$; composition is generally not commutative.
  • Ignoring the inner function's domain when finding the domain of a composition.
  • Reading $f^{-1}(x)$ as $1/f(x)$ rather than as inverse notation.
  • Confusing horizontal and vertical line tests, or shifting a graph in the wrong direction.