Module 3: Genetics - DNA, Gene Expression, Meiosis and Inheritance
Genetics traces the storage, replication and expression of information, chromosome behavior and inheritance probabilities. Use explicit organism, ploidy and dominance assumptions. Shared practice does not establish a current official module or paper format.
DNA structure and replication
Nucleotides: deoxyribose, phosphate, and a base - purines adenine and guanine, pyrimidines thymine and cytosine. Nucleotides link 3′–5′ by phosphodiester bonds into two antiparallel strands; A pairs with T by two hydrogen bonds, G with C by three. Replication is semi-conservative: helicase unwinds, each strand acts as a template, DNA polymerase adds nucleotides 5′→3′, the leading strand is continuous while the lagging strand forms Okazaki fragments joined by ligase. Meselson–Stahl's density-gradient experiment supports this.
Gene expression
The code is a triplet, degenerate, non-overlapping and (nearly) universal, with AUG the usual start and UAA/UAG/UGA stop codons in the standard code; alternative initiation and code exceptions exist. Transcription: RNA polymerase makes mRNA from the template strand; eukaryotic mRNA is spliced to remove introns. Translation: mRNA binds a ribosome, tRNA anticodons pair with codons, peptide bonds form between amino acids, and the polypeptide is released at a stop codon.
Meiosis and inheritance
Meiosis I separates homologous chromosomes and meiosis II separates sister chromatids. A standard diploid-cell model gives four haploid products, though not all become equivalent functional gametes. Crossing over and independent assortment can create variation. An Aa by Aa cross gives a 3:1 phenotype expectation only with complete dominance and suitable viability assumptions. Aa by aa gives a 1:1 expectation; AA by aa does not. Codominance and multiple alleles require different genotype-to-phenotype rules. In a conventional XY model, an X-linked locus can be hemizygous in males; sex-determination systems differ among organisms. A 9:3:3:1 expectation requires an AaBb by AaBb cross, independent assortment, complete dominance at both loci and the stated viability model. Nearby linked loci often yield excess parental combinations in an informative test cross.
Worked example
A supplied informative fly test cross gives 41 grey-normal, 39 ebony-vestigial, 10 grey-vestigial and 9 ebony-normal offspring. Under the stated parental-phase and viability assumptions, the parental total is 80 and recombinant total 19, suggesting linkage rather than a 1:1:1:1 model. The observed recombinant frequency is 19/99, about 19.2 percent. Treating this percentage as a map distance is a short-interval approximation; undetected multiple crossovers can make actual genetic distance larger. The observation estimates a frequency, not a universally exact physical distance or an assumption-free genetic map.
Traps that cost marks
Confusing the template strand with the coding strand. Saying DNA polymerase works 3′→5′. Giving genotype ratios where gamete or phenotype ratios are asked. Using a test cross with anything other than a homozygous recessive. Assuming independent assortment for linked genes. Forgetting that crossing over occurs in prophase I, not anaphase.