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Question 1Upper-secondary functions, calculus, geometry and probability
In a Terminale S function study, what is the limit of f(x) = (3x^2 - 12) / (x - 2) as x approaches 2?
- 12 Correct answer.
- 6
- 0
- Undefined
Explanation
Factor 3x^2 - 12 as 3(x^2 - 4) = 3(x - 2)(x + 2). For x != 2, cancel (x - 2), leaving 3(x + 2). Its limit at x = 2 is 3(4) = 12.
Question 2Upper-secondary functions, calculus, geometry and probability
What is the derivative f'(x) of the function f(x) = e^(2x^2 - x)?
- (4x - 1) * e^(2x^2 - x) Correct answer.
- e^(4x - 1)
- (2x - 1) * e^(2x^2 - x)
- 4x * e^(2x^2 - x)
Explanation
For f(x) = e^(u(x)), the chain rule gives f'(x) = u'(x)e^(u(x)). Here u(x) = 2x^2 - x and u'(x) = 4x - 1, so f'(x) = (4x - 1)e^(2x^2 - x).
Question 3Upper-secondary functions, calculus, geometry and probability
A Terminale S student uses ln(x) to measure the accumulated area under y = 1/x between x = 1 and x = e^2. Which exact result should the student obtain?
- 2 Correct answer.
- e^2 - 1
- 0
- ln(e^2 - 1)
Explanation
For x > 0, an antiderivative of 1/x is ln(x). Evaluation gives ln(e^2) - ln(1) = 2 - 0 = 2.
Question 4Upper-secondary functions, calculus, geometry and probability
In the set of complex numbers C, what is the modulus (norm) of z = 3 - 4i?
- 5 Correct answer.
- 7
- 1
- 25
Explanation
The modulus of a complex number z = a + bi is given by |z| = sqrt(a^2 + b^2). For z = 3 - 4i, |z| = sqrt(3^2 + (-4)^2) = sqrt(9 + 16) = sqrt(25) = 5.
Question 5Upper-secondary functions, calculus, geometry and probability
For the sequence defined by u_n = 3 * 2^(n - 1), calculate u_6.
- 96 Correct answer.
- 64
- 192
- 48
Explanation
The general term of a geometric sequence is given by u_n = u_1 * q^(n - 1). For n = 6, u_6 = 3 * 2^(6 - 1) = 3 * 2^5 = 3 * 32 = 96.
Question 6Upper-secondary functions, calculus, geometry and probability
In a lycée class of 25 students, how many distinct committees of 3 students can be formed?
- 2,300 Correct answer.
- 13,800
- 75
- 1,725
Explanation
Because committee membership order does not matter, the number of committees is given by the combination formula C(25, 3) = 25! / (3! * 22!) = (25 * 24 * 23) / (3 * 2 * 1) = 13,800 / 6 = 2,300.
Question 7Upper-secondary functions, calculus, geometry and probability
On an Argand diagram, z = -1 + i * sqrt(3) lies in quadrant II. Which angle is its principal argument?
- 2pi / 3 Correct answer.
- pi / 3
- 5pi / 6
- 4pi / 3
Explanation
The modulus is |z| = sqrt((-1)^2 + (sqrt(3))^2) = sqrt(4) = 2. Factoring gives z = 2(-1/2 + i * sqrt(3)/2). Since cos(theta) = -1/2 and sin(theta) = sqrt(3)/2, the angle lies in the second quadrant, yielding theta = 2pi / 3.
Question 8Upper-secondary functions, calculus, geometry and probability
Before studying the variations of f(x) = ln(3x - 6), which interval must be chosen as its real domain?
- ]2, +infinity[ Correct answer.
- [2, +infinity[
- ]-infinity, 2[
- ]0, +infinity[
Explanation
The logarithm requires 3x - 6 > 0. Thus 3x > 6 and x > 2, giving the open interval ]2, +infinity[.
Question 9Upper-secondary functions, calculus, geometry and probability
What is the general solution to the first-order linear differential equation y' - 2y = 0?
- y(x) = C * e^(2x), where C is a real constant Correct answer.
- y(x) = C * e^(-2x), where C is a real constant
- y(x) = 2x + C, where C is a real constant
- y(x) = C * ln(2x), where C is a real constant
Explanation
The equation is y' = 2y. Its general solution is y(x) = C e^(2x), as differentiation gives y' = 2C e^(2x) = 2y.
Question 10Upper-secondary functions, calculus, geometry and probability
Using integration by parts, what is the value of ∫ from 0 to pi of x * sin(x) dx?
- pi Correct answer.
- 2 * pi
- 0
- -pi
Explanation
Set u = x, so du = dx; and dv = sin(x) dx, so v = -cos(x). Using the integration by parts formula ∫ u dv = u*v - ∫ v du: [-x * cos(x)] from 0 to pi - ∫ from 0 to pi (-cos(x)) dx = (-pi * cos(pi) - 0) + [sin(x)] from 0 to pi = -pi * (-1) + (sin(pi) - sin(0)) = pi + 0 = pi.
Question 11Upper-secondary functions, calculus, geometry and probability
For f(x) = x^3 - 2x + 1, a tangent is drawn where x = 2. Which line has both the required slope and the point of contact?
- y = 10x - 15 Correct answer.
- y = 10x + 5
- y = 5x - 5
- y = 12x - 19
Explanation
First, evaluate the point of tangency: f(2) = 2^3 - 2(2) + 1 = 8 - 4 + 1 = 5. Next, find the derivative: f'(x) = 3x^2 - 2, so the slope is f'(2) = 3(4) - 2 = 10. The tangent line equation is y - f(2) = f'(2)(x - 2) => y - 5 = 10(x - 2) => y = 10x - 20 + 5 = 10x - 15.
Question 12Upper-secondary functions, calculus, geometry and probability
Consider the sequence defined by u_0 = 1 and u_(n+1) = (1/2) * u_n + 3. If this sequence converges to a finite real limit L, what is the value of L?
- 6 Correct answer.
- 3
- 4
- 2
Explanation
If the sequence converges to L, then by continuity L = (1/2)L + 3. Subtracting (1/2)L from both sides yields (1/2)L = 3, which gives L = 6.
Question 13Upper-secondary functions, calculus, geometry and probability
A random variable X follows a binomial distribution B(n = 20, p = 0.3). What are its expected value E(X) and variance V(X)?
- E(X) = 6, V(X) = 4.2 Correct answer.
- E(X) = 6, V(X) = 6
- E(X) = 20, V(X) = 4.2
- E(X) = 6, V(X) = 1.8
Explanation
For a binomial distribution B(n, p), the expectation is E(X) = n * p = 20 * 0.3 = 6. The variance is V(X) = n * p * (1 - p) = 20 * 0.3 * 0.7 = 6 * 0.7 = 4.2.
Question 14Upper-secondary functions, calculus, geometry and probability
In 3-dimensional Euclidean space equipped with an orthonormal coordinate system (O; i, j, k), what is the dot product (produit scalaire) of vectors u = (2, -1, 3) and v = (4, 5, -2)?
- -3 Correct answer.
- 3
- 19
- 7
Explanation
The dot product of two vectors u = (x_1, y_1, z_1) and v = (x_2, y_2, z_2) is given by u . v = x_1*x_2 + y_1*y_2 + z_1*z_2. Here, u . v = (2)(4) + (-1)(5) + (3)(-2) = 8 - 5 - 6 = -3.
Question 15Upper-secondary functions, calculus, geometry and probability
What is the normal vector n to the plane P with Cartesian equation 3x - 4y + z - 7 = 0?
- n = (3, -4, 1) Correct answer.
- n = (3, 4, 1)
- n = (3, -4, -7)
- n = (-3, 4, 1)
Explanation
In 3D analytical geometry, a plane with Cartesian equation ax + by + cz + d = 0 has normal vector n = (a, b, c). For 3x - 4y + z - 7 = 0, the coefficients are a = 3, b = -4, and c = 1, giving n = (3, -4, 1).
Question 16Upper-secondary functions, calculus, geometry and probability
What are the two complex square roots of the complex number Z = -3 + 4i?
- z_1 = 1 + 2i and z_2 = -1 - 2i Correct answer.
- z_1 = 2 + i and z_2 = -2 - i
- z_1 = 1 - 2i and z_2 = -1 + 2i
- z_1 = 2 - i and z_2 = -2 + i
Explanation
Let z = x + iy. Then z^2 = x^2 - y^2 + 2ixy. We need x^2 - y^2 = -3, 2xy = 4 (so xy = 2 > 0), and |z|^2 = x^2 + y^2 = sqrt((-3)^2 + 4^2) = 5. Adding the equations: 2x^2 = 2 => x^2 = 1 => x = ±1. Since xy > 0, when x = 1, y = 2, and when x = -1, y = -2. Thus the roots are ±(1 + 2i).
Question 17Upper-secondary functions, calculus, geometry and probability
What is the limit as x approaches +infinity of f(x) = (ln(x))^3 / x?
- 0 Correct answer.
- +infinity
- 1
- Undefined
Explanation
Comparative-growth results show that every fixed positive power of ln(x) grows more slowly than x. Therefore (ln(x))^3 / x tends to 0 as x tends to +infinity.
Question 18Upper-secondary functions, calculus, geometry and probability
After combining ln(x) + ln(x - 2) = ln(3), which real root survives the logarithms' domain restriction?
- {3} Correct answer.
- {-1, 3}
- {1}
- {0, 2}
Explanation
The domain requires x > 2. Combine the logarithms: ln(x(x - 2)) = ln(3), so x^2 - 2x = 3 and x^2 - 2x - 3 = 0. Factoring gives (x - 3)(x + 1) = 0. Only x = 3 lies in the domain.
Question 19Upper-secondary functions, calculus, geometry and probability
If events A and B are independent with P(A) = 0.35 and P(B) = 0.40, what is P(A U B)?
- 0.61 Correct answer.
- 0.75
- 0.14
- 0.49
Explanation
Independence gives P(A ∩ B) = 0.35 * 0.40 = 0.14. Hence P(A U B) = 0.35 + 0.40 - 0.14 = 0.61.
Question 20Upper-secondary functions, calculus, geometry and probability
The characteristic roots associated with y'' + 9y = 0 are 3i and -3i. Which family of real-valued functions follows?
- y(x) = A * cos(3x) + B * sin(3x) Correct answer.
- y(x) = A * e^(3x) + B * e^(-3x)
- y(x) = (Ax + B) * e^(3x)
- y(x) = A * cos(9x) + B * sin(9x)
Explanation
The characteristic equation is r^2 + 9 = 0, which has complex roots r = ±3i. For pure imaginary roots ±omega*i with omega = 3, the general solution is y(x) = A * cos(omega*x) + B * sin(omega*x) = A * cos(3x) + B * sin(3x).
Question 21Upper-secondary functions, calculus, geometry and probability
What is the continuous compounding future value of a capital of 100,000 DJF invested for 2 years at an annual interest rate of 5% (r = 0.05), given e^0.10 ≈ 1.10517?
- 110,517 DJF Correct answer.
- 110,000 DJF
- 110,250 DJF
- 105,170 DJF
Explanation
Continuous compounding is modeled by the formula A = P * e^(r*t). Here, P = 100,000 DJF, r = 0.05, and t = 2 years. Thus r*t = 0.10, and A = 100,000 * e^0.10 ≈ 100,000 * 1.10517 = 110,517 DJF.
Question 22Upper-secondary functions, calculus, geometry and probability
Using u = x^2 + 4 and du = 2x dx, evaluate I = ∫ from 0 to 2 of x / (x^2 + 4) dx.
- (1/2) * ln(2) Correct answer.
- ln(2)
- (1/4) * ln(2)
- 2 * ln(2)
Explanation
Because the derivative of x^2 + 4 is 2x, I = (1/2)[ln(x^2 + 4)] from 0 to 2 = (1/2)(ln(8) - ln(4)) = (1/2)ln(2).
Question 23Upper-secondary functions, calculus, geometry and probability
Apply the point-to-plane formula to A(1, 2, 3) and P: 2x - 2y + z + 5 = 0. What perpendicular distance results?
- 2 Correct answer.
- 6
- 4 / 3
- 18
Explanation
The distance from a point A(x_0, y_0, z_0) to a plane ax + by + cz + d = 0 is d = |a*x_0 + b*y_0 + c*z_0 + d| / sqrt(a^2 + b^2 + c^2). Substituting values: |2(1) - 2(2) + 1(3) + 5| / sqrt(2^2 + (-2)^2 + 1^2) = |2 - 4 + 3 + 5| / sqrt(4 + 4 + 1) = |6| / sqrt(9) = 6 / 3 = 2.
Question 24Upper-secondary functions, calculus, geometry and probability
What is the algebraic form of the complex number z = (1 + i)^10?
- 32i Correct answer.
- 32
- -32i
- -32
Explanation
Write 1 + i = sqrt(2)e^(i*pi/4). Then (1 + i)^10 = (sqrt(2))^10 e^(i*10pi/4) = 32e^(i*5pi/2) = 32i.
Question 25Upper-secondary functions, calculus, geometry and probability
Let f be a twice-differentiable function on R. What condition on the second derivative f''(x) proves that the graph of f has an inflection point at x = x_0?
- f''(x_0) = 0 and f''(x) changes sign at x_0 Correct answer.
- f''(x_0) = 0 regardless of whether it changes sign
- f'(x_0) = 0 and f''(x_0) > 0
- f'(x_0) = 0 and f''(x_0) < 0
Explanation
An inflection point occurs where the curvature (concavity) of the curve changes direction. This requires not only that the second derivative vanishes (f''(x_0) = 0), but critically that f''(x) changes sign across x_0 (from concave up to concave down, or vice versa).
Question 26Mechanics, fields, thermal behavior, waves and modern models
A solid block of mass m = 2.0 kg is pulled on a smooth, frictionless horizontal table by a constant horizontal force F = 6.0 N. What is the magnitude of the block's acceleration?
- 3.0 m/s^2 Correct answer.
- 0.33 m/s^2
- 8.0 m/s^2
- 12.0 m/s^2
Explanation
According to Newton's second law of motion (sum of forces = m * a), on a frictionless horizontal plane where the normal force balances the weight vertically (N = P = mg), the net horizontal force is simply F. Therefore, the acceleration is: a = F / m = 6.0 N / 2.0 kg = 3.0 m/s^2.
Question 27Mechanics, fields, thermal behavior, waves and modern models
A small ball of mass m = 0.50 kg is dropped from rest from a height h = 20.0 m above the ground in a vacuum. Taking the acceleration due to gravity as g = 9.8 m/s^2, what is the speed of the ball immediately before striking the ground?
- 19.8 m/s Correct answer.
- 14.0 m/s
- 98.0 m/s
- 196.0 m/s
Explanation
Applying the principle of conservation of mechanical energy (E_m = E_k + E_p = constant): initial potential energy is converted entirely into kinetic energy at ground level: m * g * h = 0.5 * m * v^2. Solving for velocity: v = sqrt(2 * g * h) = sqrt(2 * 9.8 m/s^2 * 20.0 m) = sqrt(392) ≈ 19.799 m/s ≈ 19.8 m/s.
Question 28Mechanics, fields, thermal behavior, waves and modern models
A projectile is launched from ground level with an initial velocity v_0 = 20 m/s at an angle alpha = 30° above the horizontal over flat terrain. Neglecting air resistance and taking g = 10 m/s^2, what is the maximum height H reached by the projectile, and what is its horizontal range R?
- H = 10.0 m; R = 40 m
- H = 15.0 m; R = 20*sqrt(3) m (≈ 34.6 m)
- H = 5.0 m; R = 20*sqrt(3) m (≈ 34.6 m) Correct answer.
- H = 5.0 m; R = 40 m
Explanation
The vertical component of initial velocity is v_0y = v_0 * sin(30°) = 20 * 0.5 = 10 m/s. The horizontal component is v_0x = v_0 * cos(30°) = 20 * (sqrt(3)/2) = 10*sqrt(3) m/s. Maximum height: H = (v_0y)^2 / (2g) = 10^2 / (2 * 10) = 100 / 20 = 5.0 m. Total time of flight: t_f = 2 * v_0y / g = 2 * 10 / 10 = 2.0 s. Horizontal range: R = v_0x * t_f = 10*sqrt(3) * 2.0 = 20*sqrt(3) m ≈ 34.64 m.
Question 29Mechanics, fields, thermal behavior, waves and modern models
A communication satellite moves in a circular orbit of radius r = 7.0 x 10^6 m around Earth at a constant orbital speed v = 7.0 x 10^3 m/s (7.0 km/s). What is the magnitude of its centripetal acceleration?
- 7.0 m/s^2 Correct answer.
- 1.0 x 10^-3 m/s^2
- 49.0 m/s^2
- 9.8 m/s^2
Explanation
In uniform circular motion, the acceleration vector is directed radially inward toward the center of the orbit (centripetal acceleration) with magnitude given by: a_c = v^2 / r. Substituting the values: a_c = (7.0 x 10^3 m/s)^2 / (7.0 x 10^6 m) = (4.9 x 10^7) / (7.0 x 10^6) = 7.0 m/s^2.
Question 30Mechanics, fields, thermal behavior, waves and modern models
The period of small oscillations of a simple pendulum of length L is T_0 = 2*pi*sqrt(L/g). If the length of the string is quadrupled (L' = 4L) while keeping g constant, what happens to the period of oscillation?
- The period is halved (T' = T_0 / 2)
- The period remains unchanged (T' = T_0)
- The period is quadrupled (T' = 4 * T_0)
- The period is doubled (T' = 2 * T_0) Correct answer.
Explanation
The period of a simple pendulum is proportional to the square root of its length: T = 2*pi*sqrt(L/g). When the length is multiplied by 4: T' = 2*pi*sqrt(4L/g) = 2*pi * sqrt(4) * sqrt(L/g) = 2 * (2*pi*sqrt(L/g)) = 2 * T_0. Thus, the period of oscillation is doubled.
Question 31Mechanics, fields, thermal behavior, waves and modern models
A horizontal spring-mass system consists of a spring with stiffness constant k = 100 N/m attached to a block of mass m = 0.25 kg on a frictionless surface. What is the natural angular frequency omega_0 and the natural period T_0 of this harmonic oscillator? (Use pi ≈ 3.14)
- omega_0 = 20 rad/s; T_0 ≈ 0.314 s Correct answer.
- omega_0 = 400 rad/s; T_0 ≈ 0.0157 s
- omega_0 = 10 rad/s; T_0 ≈ 0.628 s
- omega_0 = 25 rad/s; T_0 ≈ 0.251 s
Explanation
The natural angular frequency of a spring-mass harmonic oscillator is: omega_0 = sqrt(k / m) = sqrt(100 N/m / 0.25 kg) = sqrt(400) = 20 rad/s. The natural period is given by: T_0 = 2*pi / omega_0 = 2 * 3.1416 / 20 = pi / 10 ≈ 0.314 s.
Question 32Mechanics, fields, thermal behavior, waves and modern models
A car of mass m = 1,200 kg travels along a straight level road and slows down from an initial speed v_1 = 25 m/s (90 km/h) to a final speed v_2 = 15 m/s (54 km/h). According to the work-energy theorem, what is the net work done by all braking and resistive forces acting on the vehicle?
- -60 kJ (-60,000 J)
- -120 kJ (-120,000 J)
- -240 kJ (-240,000 J) Correct answer.
- -480 kJ (-480,000 J)
Explanation
According to the work-energy theorem, the net work done on an object equals the change in its kinetic energy: W_net = Delta(E_k) = 0.5 * m * (v_2^2 - v_1^2). Calculating: W_net = 0.5 * 1200 kg * (15^2 - 25^2) = 600 * (225 - 625) = 600 * (-400) = -240,000 J = -240 kJ. The negative sign indicates that work is resistive (dissipating energy).
Question 33Mechanics, fields, thermal behavior, waves and modern models
A series RC circuit consists of an ideal DC voltage source E = 12.0 V, a resistor R = 100 kOmega (1.0 x 10^5 Omega), and an uncharged capacitor C = 20 muF (2.0 x 10^-5 F). At t = 0, the switch is closed. What is the time constant tau of the circuit, and what is the voltage u_C across the capacitor at time t = tau?
- tau = 0.20 s; u_C(tau) = 6.0 V
- tau = 2.0 s; u_C(tau) ≈ 7.58 V (63.2% of E) Correct answer.
- tau = 5.0 s; u_C(tau) = 12.0 V
- tau = 2.0 s; u_C(tau) ≈ 4.42 V (36.8% of E)
Explanation
The time constant of a series RC circuit is: tau = R * C = (1.0 x 10^5 Omega) * (2.0 x 10^-5 F) = 2.0 s. The voltage across the charging capacitor is given by u_C(t) = E * (1 - e^(-t/tau)). At t = tau: u_C(tau) = E * (1 - e^-1) = 12.0 V * (1 - 0.3679) = 12.0 V * 0.6321 ≈ 7.58 V (approximately 63.2% of the maximum source voltage E).
Question 34Mechanics, fields, thermal behavior, waves and modern models
A capacitor of capacitance C = 50 muF (5.0 x 10^-5 F) is fully charged to a voltage U = 200 V. What is the total electrostatic potential energy E_e stored in the electric field of the capacitor?
- 0.50 J
- 1.0 J Correct answer.
- 2.0 J
- 10.0 J
Explanation
The electrostatic energy stored in a capacitor is: E_e = 0.5 * C * U^2. Substituting the given values: E_e = 0.5 * (5.0 x 10^-5 F) * (200 V)^2 = 0.5 * (5.0 x 10^-5) * 40,000 = 0.5 * 2.0 = 1.0 J.
Question 35Mechanics, fields, thermal behavior, waves and modern models
A series RLC circuit comprises a resistor R = 50 Omega, an inductor L = 0.20 H, and a capacitor C = 5.0 muF (5.0 x 10^-6 F) connected to a sinusoidal AC voltage source u(t) = U*sqrt(2)*sin(omega*t). What is the resonant frequency f_0 of this circuit, and what is the circuit impedance Z at resonance?
- f_0 ≈ 1,000 Hz; Z = 0 Omega
- f_0 ≈ 318 Hz; Z = 50 Omega
- f_0 ≈ 159 Hz; Z = 50 Omega Correct answer.
- f_0 ≈ 159 Hz; Z = 250 Omega
Explanation
At resonance in a series RLC circuit, the inductive reactance balances the capacitive reactance: L*omega_0 = 1 / (C*omega_0), so omega_0 = 1 / sqrt(L*C) = 1 / sqrt(0.20 * 5.0 x 10^-6) = 1 / sqrt(1.0 x 10^-6) = 1 / (1.0 x 10^-3) = 1,000 rad/s. The resonant frequency is: f_0 = omega_0 / (2*pi) = 1,000 / (2 * 3.1416) ≈ 159.15 Hz ≈ 159 Hz. At resonance, the reactive parts cancel out (L*omega - 1/(C*omega) = 0), so the impedance is purely resistive and minimal: Z = R = 50 Omega.
Question 36Mechanics, fields, thermal behavior, waves and modern models
According to Faraday's and Lenz's laws of electromagnetic induction, what determines the magnitude and direction of the induced electromotive force (emf) e in a closed conducting loop?
- e is proportional to the static magnetic field strength; direction reinforces the external magnetic field
- e = - dPhi/dt; the induced current creates an induced magnetic field that opposes the change in magnetic flux that produced it Correct answer.
- e = + dPhi/dt; the induced current always flows in the direction of the external electric current
- e is independent of time and proportional only to loop resistance
Explanation
Faraday's law states that the induced electromotive force e is equal to the negative time rate of change of the magnetic flux Phi through the circuit: e = - dPhi/dt. Lenz's law (represented by the negative sign) states that the direction of any induced current is always such that its magnetic effect opposes the variation in magnetic flux that caused it.
Question 37Mechanics, fields, thermal behavior, waves and modern models
An AC electrical appliance is powered by an effective (RMS) voltage U = 230 V at 50 Hz. It draws an effective current I = 2.0 A with a phase shift phi = pi/3 rad (60°) between current and voltage. What is the active (real) power P consumed by the appliance, and what is its power factor?
- P = 230 W; power factor = 0.50 Correct answer.
- P = 460 W; power factor = 1.0
- P = 398 W; power factor = 0.866
- P = 115 W; power factor = 0.25
Explanation
The active electrical power consumed in an AC circuit is given by: P = U * I * cos(phi), where cos(phi) is the power factor. Here, phi = 60° (pi/3 rad), so cos(60°) = 0.50. Therefore: P = 230 V * 2.0 A * cos(60°) = 460 * 0.50 = 230 W. The power factor is cos(phi) = 0.50.
Question 38Chemical structure, reactions and organic models
According to Newton's second law of motion (F_net = m * a), what acceleration is produced when a net horizontal force of 45 N acts on a mass of 15 kg?
- 3.0 m/s^2 Correct answer.
- 675 m/s^2
- 0.33 m/s^2
- 30 m/s^2
Explanation
From Newton's second law, a = F_net / m. Substituting 45 N and 15 kg gives a = 45 / 15 = 3.0 m/s^2.
Question 39Chemical structure, reactions and organic models
What is the equivalent resistance R_eq of three resistors with resistances 6 ohms, 12 ohms, and 4 ohms connected in parallel?
- 2 ohms Correct answer.
- 22 ohms
- 4 ohms
- 1.5 ohms
Explanation
For parallel resistors, 1 / R_eq = 1/R_1 + 1/R_2 + 1/R_3 = 1/6 + 1/12 + 1/4. Finding a common denominator of 12: 1 / R_eq = 2/12 + 1/12 + 3/12 = 6/12 = 1/2. Inverting gives R_eq = 2 ohms.
Question 40Chemical structure, reactions and organic models
In a radioactive decay process governed by N(t) = N_0 * (1/2)^(t / T_1/2), if a radioactive sample has a half-life of 8 days, what percentage of the initial radioactive nuclei remains after 24 days?
- 12.5% Correct answer.
- 25.0%
- 50.0%
- 6.25%
Explanation
The number of half-lives elapsed is n = t / T_1/2 = 24 / 8 = 3. After 3 half-lives, the fraction remaining is (1/2)^3 = 1/8 = 0.125, which corresponds to 12.5%.
Question 41Chemical structure, reactions and organic models
What is the pH of an aqueous solution of hydrochloric acid (HCl), a strong monoprotic acid, with a concentration of C = 0.001 mol/L?
- 3.0 Correct answer.
- 1.0
- 4.0
- 11.0
Explanation
Because HCl dissociates completely in water, [H3O+] = C = 0.001 mol/L = 10^(-3) mol/L. The pH is given by pH = -log[H3O+] = -log(10^(-3)) = 3.0.
Question 42Chemical structure, reactions and organic models
What organic functional group is formed by the condensation reaction between a carboxylic acid (R-COOH) and an alcohol (R'-OH) in the presence of an acid catalyst?
- Ester Correct answer.
- Amide
- Ether
- Aldehyde
Explanation
Fischer esterification involves reacting a carboxylic acid with an alcohol in the presence of an acid catalyst to produce an ester (R-COO-R') and water as a byproduct.
Question 43Chemical structure, reactions and organic models
A light ray in air (refractive index n_1 = 1.00) strikes a water surface (n_2 = 1.33) at an angle of incidence of 30.0 degrees. According to Snell's law (n_1 * sin(theta_1) = n_2 * sin(theta_2)), what is the value of sin(theta_2)?
- 0.376 Correct answer.
- 0.500
- 0.665
- 0.250
Explanation
Snell's law gives n_1 * sin(theta_1) = n_2 * sin(theta_2). Here, 1.00 * sin(30°) = 1.33 * sin(theta_2). Since sin(30°) = 0.500, sin(theta_2) = 0.500 / 1.33 ≈ 0.376.
Question 44Chemical structure, reactions and organic models
A projectile is launched from flat ground with initial speed v_0 = 20 m/s at an angle of 30 degrees above the horizontal. Neglecting air resistance and taking g = 10 m/s^2, what is its maximum height H reached?
- 5.0 m Correct answer.
- 10.0 m
- 20.0 m
- 2.5 m
Explanation
The vertical component of initial velocity is v_0y = v_0 * sin(30°) = 20 * 0.5 = 10 m/s. The maximum height is given by H = (v_0y)^2 / (2g) = 10^2 / (2 * 10) = 100 / 20 = 5.0 m.
Question 45Chemical structure, reactions and organic models
An RC circuit contains a resistor R = 50 kilo-ohms (50,000 ohms) and a capacitor C = 200 micro-farads (2.0 x 10^-4 F) in series with a DC voltage source. What is the characteristic time constant tau (tau = R * C) of this circuit?
- 10.0 seconds Correct answer.
- 1.0 second
- 100.0 seconds
- 0.10 seconds
Explanation
The time constant is tau = R * C. Substituting: tau = 50,000 ohms * (2.0 x 10^-4 F) = (5 x 10^4) * (2 x 10^-4) = 10.0 seconds.
Question 46Chemical structure, reactions and organic models
In chemical titration, 20.0 mL of an ethanoic acid solution (CH3COOH) of unknown concentration C_A is titrated to the equivalence point by 16.0 mL of a sodium hydroxide solution (NaOH) of concentration C_B = 0.10 mol/L. What is the concentration C_A?
- 0.080 mol/L Correct answer.
- 0.125 mol/L
- 0.050 mol/L
- 0.160 mol/L
Explanation
Ethanoic acid reacts with sodium hydroxide in a 1:1 molar ratio: CH3COOH + OH^- -> CH3COO^- + H2O. At equivalence, n_A = n_B, so C_A * V_A = C_B * V_B. Therefore, C_A = (C_B * V_B) / V_A = (0.10 mol/L * 16.0 mL) / 20.0 mL = 1.60 / 20.0 = 0.080 mol/L.
Question 47Chemical structure, reactions and organic models
An automobile of mass 1,200 kg traveling at 20 m/s brakes to a complete stop on a straight horizontal road. According to the work-energy theorem (W = Delta E_k), what is the total work done by the braking friction force?
- -240,000 J Correct answer.
- -120,000 J
- -480,000 J
- 240,000 J
Explanation
By the work-energy theorem, W = E_k(final) - E_k(initial). Since the final speed is 0 m/s, E_k(final) = 0. The initial kinetic energy is E_k(initial) = (1/2) * m * v^2 = 0.5 * 1,200 kg * (20 m/s)^2 = 600 * 400 = 240,000 J. Therefore, W = 0 - 240,000 J = -240,000 J.
Question 48Chemical structure, reactions and organic models
A telecommunications satellite orbits Earth in a circular trajectory of radius r with speed v = sqrt(G * M_E / r). If the orbital radius is quadrupled to 4r, by what factor does its orbital speed change?
- It is halved (divided by 2) Correct answer.
- It is quartered (divided by 4)
- It is doubled (multiplied by 2)
- It remains unchanged
Explanation
Since v is inversely proportional to the square root of the orbital radius (v proportional to 1 / sqrt(r)), replacing r with 4r gives v' = sqrt(G * M_E / (4r)) = (1/2) * sqrt(G * M_E / r) = v / 2. The orbital speed is halved.
Question 49Chemical structure, reactions and organic models
What is the natural resonance frequency f_0 of an ideal RLC series circuit consisting of an inductor L = 0.25 H and a capacitor C = 100 microfarads (1.0 x 10^-4 F)?
- 31.8 Hz Correct answer.
- 200 Hz
- 100 Hz
- 15.9 Hz
Explanation
The resonance angular frequency is omega_0 = 1 / sqrt(L * C) = 1 / sqrt(0.25 * 1.0 x 10^-4) = 1 / sqrt(2.5 x 10^-5) = 1 / (5.0 x 10^-3) = 200 rad/s. The natural frequency is f_0 = omega_0 / (2 * pi) = 200 / (2 * 3.1416) ≈ 31.8 Hz.
Question 50Chemical structure, reactions and organic models
In a Young's double-slit experiment, the slit separation is a = 0.50 mm (5.0 x 10^-4 m), the screen distance is D = 2.0 m, and the monochromatic light has wavelength lambda = 600 nm (6.0 x 10^-7 m). What is the fringe spacing (interfrange) i?
- 2.4 mm Correct answer.
- 1.2 mm
- 4.8 mm
- 0.60 mm
Explanation
The formula for fringe spacing in double-slit interference is i = (lambda * D) / a. Substituting values: i = (6.0 x 10^-7 m * 2.0 m) / (5.0 x 10^-4 m) = (1.2 x 10^-6) / (5.0 x 10^-4) = 2.4 x 10^-3 m = 2.4 mm.