ETA CETa study materials
ETA CETa study resources

12 V Linear Supply With Insufficient Rectifier Headroom

ETA CETa · Put your knowledge to work in context.

All case studies

12 V Linear Supply With Insufficient Rectifier Headroom

A technician is servicing a 12 V, 200 mA linear supply. The transformer secondary is 12.6 Vrms at 60 Hz, followed by a four-diode bridge using 1N4004 rectifiers and a 1000 µF/25 V electrolytic filter capacitor. The raw DC feeds a 7812 three-terminal regulator. The complaint is 120 Hz hum on the output and a filter capacitor that runs warm. Measured load current is 200 mA. Line voltage can sag 10% during a brownout. The technician has a 4700 µF/35 V capacitor on the shelf and considers swapping it in to reduce hum. The 7812 datasheet lists about 2 V dropout at 200 mA and requires at least 2.5 V headroom for guaranteed regulation. The 1N4004 has a 30 A non-repetitive surge rating and a 1 A average rating. The technician must decide whether the bigger capacitor alone solves the problem.

1. Calculate the peak, ripple, and minimum raw DC voltage at nominal line and at −10% line. Does the 7812 stay in regulation?

Read the worked answer

Secondary peak = 12.6 × 1.414 = 17.82 V. A bridge conducts two diodes in series, so subtract about 1.4 V: 16.42 V. Full-wave ripple is Vpp ≈ I/(2fC) = 0.200/(2 × 60 × 0.001) = 1.67 V. Minimum raw DC ≈ 16.42 − 1.67 = 14.75 V, average about 15.6 V. At nominal line the 7812 has only 14.75 − 12 = 2.75 V headroom, marginally above the 2.5 V minimum. At −10% line the secondary is 11.34 Vrms, peak = 16.03 V, minus 1.4 V gives 14.63 V, minus 1.67 V ripple gives 12.96 V minimum. The regulator needs at least 12 + 2.5 = 14.5 V, so it drops out and the output hums. The design is not worst-case valid; the transformer is undersized for a 7812 at 200 mA.

2. Evaluate the proposed 4700 µF replacement: does it fix dropout, and what new risk does it create for the 1N4004 bridge?

Read the worked answer

With 4700 µF, ripple = 0.200/(2 × 60 × 0.0047) = 0.355 Vpp. At nominal line, minimum = 16.42 − 0.355 = 16.07 V. At −10% line, 14.63 − 0.355 = 14.28 V. The 7812 still needs about 14.5 V, so a 10% brownout still violates dropout, though only slightly. The larger capacitor does not fix the fundamental lack of transformer voltage. It also increases turn-on inrush: the 1N4004 surge rating is 30 A for one cycle. With 4700 µF and a few tenths of an ohm of winding resistance, the first-cycle surge can approach or exceed 30 A, especially if line is applied near peak. Add a surge-limiting NTC or use diodes with a higher surge rating. The warm capacitor is likely ripple-current heating; verify the actual ripple-current rating at 120 Hz, not just capacitance and voltage.

3. Recommend a corrective action and explain why the original capacitor runs warm.

Read the worked answer

The best fix is a 15 Vrms secondary, which gives a peak of 21.2 V and a minimum of about 18.1 V after ripple, leaving ample headroom at −10% line. Alternatively, replace the 7812 with a low-dropout regulator rated for 200 mA and verify thermal dissipation; (V_in − 12) × 0.2 A is roughly 1.2–1.6 W, so a heatsink may be needed in a closed case. A 4700 µF capacitor helps ripple only after the voltage headroom is corrected; do not rely on it alone. The original capacitor runs warm because it carries the 200 mA load's ripple current, roughly 0.2 A rms, and because its 25 V rating is close to the 17.8 V peak. Check its ripple-current and temperature ratings, and add a 0.1 µF bypass at the regulator output.