CHSE Odisha Elective Chemistry study materials
CHSE Odisha Elective Chemistry study resources

CHSE Odisha Elective Chemistry: Electrochemistry

CHSE Odisha Elective Chemistry · Work through your exam, one topic at a time.

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Electrochemistry

Electrochemistry

This domain tests galvanic cells, the Nernst equation, conductance, electrolysis and corrosion.

Core rules

  • E°cell = E°cathode − E°anode; a positive E°cell means ΔG° is negative and K>1.
  • ΔG° = −nFE° = −RT ln K; at 298 K, E° = (0.059 V/n) log K.
  • Nernst equation: E = E° − (0.059/n) log Q at 298 K.
  • Λm = 1000κ/M; Λm increases on dilution while κ decreases.
  • Kohlrausch law: Λ°m of a weak electrolyte equals the sum of limiting ionic conductivities.
  • Faraday: Q=It; moles deposited = Q/(nF).

Worked example Zn|Zn²⁺(0.10 M)||Cu²⁺(0.010 M)|Cu, E°=1.10 V, n=2. Q=[Zn²⁺]/[Cu²⁺]=0.10/0.010=10. E=1.10 − (0.059/2)log10 = 1.10 − 0.0295 = 1.07 V. Increasing Zn²⁺ or decreasing Cu²⁺ lowers the emf, as Le Chatelier predicts.

Traps

  • Reversing the anode sign or using E°oxidation instead of reduction.
  • Using 0.059 V outside 298 K; use 2.303RT/F otherwise.
  • Conductivity units: κ in S cm⁻¹, Λm in S cm² mol⁻¹.
  • In electrolysis, the product depends on electrode material and overpotential, not just E°.