KSEAB II PUC Chemistry study materials
KSEAB II PUC Chemistry study resources

KSEAB II PUC Chemistry: Some Basic Concepts of Chemistry

KSEAB II PUC Chemistry · Work through your exam, one topic at a time.

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Some Basic Concepts of Chemistry

Domain 1: Some Basic Concepts of Chemistry

This domain tests how confidently you convert a laboratory observation into a number: moles, mass, volume, concentration, and stoichiometric ratio. KSEAB questions often combine significant figures with limiting-reagent reasoning and solution concentration.

Core rules

  • The mole is the link: n = m/M = N/N_A = V/22.4 L at STP for an ideal gas. Molar mass of a diatomic gas uses both atoms.
  • A balanced equation gives mole ratios, not mass ratios. Identify the limiting reagent by dividing moles by coefficient; the smallest quotient limits.
  • Molarity M = mol solute/L solution and changes with temperature; molality m = mol solute/kg solvent does not. Mole fraction and ppm are ratio based.
  • Significant figures: addition/subtraction keeps the least decimal places; multiplication/division keeps the least significant figures. Exact integers do not limit.
  • Laws of chemical combination and Avogadro's law support the mole-ratio interpretation.

Worked example

5.60 g Fe reacts with 3.65 g HCl: Fe + 2HCl -> FeCl2 + H2. n(Fe)=5.60/56.0=0.100 mol; n(HCl)=3.65/36.5=0.100 mol. HCl needs 0.200 mol for 0.100 mol Fe, so HCl is limiting. n(H2)=0.100/2=0.0500 mol; V=0.0500 x 22.4=1.12 L at STP. Mass is not the limiting test; mole/coefficient is.

Traps

  • Using 22.4 L mol^-1 at non-STP; convert T and P or use the ideal gas equation.
  • Forgetting diatomic molar masses (H2, O2, Cl2).
  • Treating molarity as mol/kg; molality is solvent-based.
  • Rounding intermediate values and losing significant-figure marks.
  • Assuming the reactant with smaller mass is limiting.