Karnataka II PUC Physics (KSEAB) study materials
Karnataka II PUC Physics (KSEAB) study resources

Karnataka II PUC Physics (KSEAB): Atoms and Nuclei

Karnataka II PUC Physics (KSEAB) · Work through your exam, one topic at a time.

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Atoms and Nuclei

What is examined

Atoms and Nuclei tests the Rutherford model, Bohr's postulates, hydrogen energy levels and spectra, nuclear size, mass defect and binding energy, radioactivity and its decay laws, and fission and fusion.

Core rules

  • Bohr: electrons occupy stationary orbits with mvr = nh/2π; radiation occurs only on transitions, hν = E₂ − E₁.
  • Hydrogen: r_n = 0.529 n²/Z Å; E_n = −13.6 Z²/n² eV; velocity v_n ∝ Z/n. Ground-state energy −13.6 eV; ionisation energy 13.6 eV.
  • Series: Lyman (n → 1, UV), Balmer (n → 2, visible), Paschen (n → 3, IR). Hα (3 → 2) is 656 nm.
  • de Broglie's standing-wave condition explains quantisation: 2πr = nλ.
  • Nuclear radius R = R₀A^{1/3}, R₀ ≈ 1.2 fm; nuclear density is nearly constant.
  • Mass defect Δm; binding energy BE = Δm × 931.5 MeV u⁻¹. BE per nucleon peaks near Fe-56, so fusion of light nuclei and fission of heavy nuclei release energy.
  • Radioactive decay: N = N₀e^{−λt}; T½ = 0.693/λ; activity A = λN. Alpha emission: A − 4, Z − 2; beta-minus: Z + 1.

Worked example

Find the photon energy and wavelength for the transition n = 3 → n = 2 in hydrogen. E₃ = −13.6/9 = −1.51 eV; E₂ = −13.6/4 = −3.40 eV. ΔE = −1.51 − (−3.40) = 1.89 eV. λ = 1240/1.89 ≈ 656 nm. This is the red Hα line.

Traps

Forgetting that atomic energies are negative; using E = +13.6/n²; taking T½ = λ/0.693; and computing binding energy per nucleon without dividing by A.