RRB JE CBT 2 Electrical study materials
RRB JE CBT 2 Electrical study resources

RRB JE CBT 2 Electrical: Basic Electrical Engineering

RRB JE CBT 2 Electrical · Work through your exam, one topic at a time.

All guide sections

Basic Electrical Engineering

Basic Electrical Engineering is the foundational domain of RRB JE CBT 2. It tests circuit laws, network theorems, AC/DC fundamentals and electromagnetic induction, usually through short numericals and conceptual one-liners.

Circuit laws and network theorems

  • KCL: the algebraic sum of currents at a node is zero; KVL: the algebraic sum of voltages around a closed loop is zero.
  • Thevenin reduces a linear network to Vth in series with Rth; Norton uses In in parallel with Rn, with Rn = Rth and In = Vth/Rth.
  • Superposition applies to linear circuits and to voltages/currents, never directly to power.
  • Maximum power transfer to a resistive load occurs at RL = Rth, giving Pmax = Vth²/(4Rth).

AC/DC fundamentals and induction

  • RMS value of a sinusoid = peak/√2; average over a full cycle is zero.
  • XL = 2πfL and XC = 1/(2πfC); impedance combines resistance and reactance as a complex quantity.
  • Power triangle: P = VI cosφ, Q = VI sinφ, S = VI.
  • Faraday’s law gives e = −N dφ/dt; Lenz’s law fixes the induced EMF direction so as to oppose the change.

Worked example

A 12 V source feeds a 4 Ω series resistor and a 6 Ω shunt resistor; a load is connected across the 6 Ω resistor. Remove the load: Vth = 12 × 6/(4 + 6) = 7.2 V, and Rth = 4 || 6 = 2.4 Ω. For maximum power transfer, RL = 2.4 Ω and Pmax = 7.2²/(4 × 2.4) = 51.84/9.6 = 5.4 W.

Traps that cost marks

Mixing RMS with average for a rectified wave, applying superposition to power, ignoring dependent sources when finding Rth, and forgetting that a 6 Ω shunt changes the open-circuit voltage are common errors.