I85PREP
⌘ K
SRMJEEE study materials
SRMJEEE study resources

SRMJEEE practice questions

One question at a time. Build your SRMJEEE understanding.

First 50 of 200 questions. Each one lists the choices, the correct answer, and an explanation. The checker at the top of this page saves progress in this browser when it is available.

Continue in the practice tool above to load more questions, 50 at a time.

Question 1Engineering & Technology (SRMJEEE undergraduate engineering admission)

A projectile is launched at 20 m/s at 30° above the horizontal on level ground. Taking g = 10 m/s², what is the maximum height reached?

  1. 5 m Correct answer.
  2. 15 m
  3. 20 m
  4. 10 m

Explanation

The vertical velocity component is 20·sin30° = 10 m/s. Maximum height is v_y²/(2g) = 100/20 = 5 m. Horizontal speed does not affect the peak height.

Question 2Engineering & Technology (SRMJEEE undergraduate engineering admission)

Which quantity is conserved for a body moving under a central force?

  1. Linear acceleration
  2. Linear momentum
  3. Kinetic energy
  4. Angular momentum Correct answer.

Explanation

A central force acts along the line joining the body to the force centre, so its torque about that centre is zero. Zero torque means angular momentum about the centre stays constant. Linear momentum changes because the force alters velocity direction.

Question 3Engineering & Technology (SRMJEEE undergraduate engineering admission)

For an ideal gas undergoing an isothermal reversible expansion, which statement is correct?

  1. Internal energy is constant and no work is done
  2. Internal energy is constant and work done equals heat absorbed Correct answer.
  3. Internal energy falls and work done equals heat absorbed
  4. Internal energy rises and heat absorbed is zero

Explanation

For an ideal gas, internal energy depends only on temperature, so an isothermal process keeps ΔU = 0. The first law then gives Q = W, meaning the heat absorbed equals the work done by the gas.

Question 4Engineering & Technology (SRMJEEE undergraduate engineering admission)

A wire of resistance R is stretched uniformly to twice its original length. Its new resistance is:

  1. R
  2. 4R Correct answer.
  3. R/2
  4. 2R

Explanation

Stretching keeps volume constant, so doubling length halves the cross-sectional area. Resistance R = ρL/A then scales by 2 × 2 = 4.

Question 5Engineering & Technology (SRMJEEE undergraduate engineering admission)

Two capacitors of 3 μF and 6 μF are connected in series across 18 V. What is the charge on each capacitor?

  1. 36 μC Correct answer.
  2. 18 μC
  3. 108 μC
  4. 54 μC

Explanation

Series capacitance is (3×6)/(3+6) = 2 μF. Charge is Q = CV = 2 μF × 18 V = 36 μC, and series capacitors carry equal charge.

Question 6Engineering & Technology (SRMJEEE undergraduate engineering admission)

A convex lens of focal length 15 cm forms a real image at 30 cm from the lens. Where is the object?

  1. 30 cm Correct answer.
  2. 15 cm
  3. 45 cm
  4. 10 cm

Explanation

Using 1/f = 1/v + 1/u with f = 15 cm and v = 30 cm gives 1/u = 1/15 − 1/30 = 1/30, so u = 30 cm. The object lies at twice the focal length, matching the image distance.

Question 7Engineering & Technology (SRMJEEE undergraduate engineering admission)

In the photoelectric effect, increasing the intensity of incident light above the threshold frequency increases:

  1. The threshold frequency of the metal
  2. The stopping potential
  3. The maximum kinetic energy of photoelectrons
  4. The number of photoelectrons emitted per second Correct answer.

Explanation

Intensity determines the number of photons arriving per second, so more electrons are ejected per second. The maximum kinetic energy and stopping potential depend on photon frequency, and threshold frequency is a property of the metal.

Question 8Engineering & Technology (SRMJEEE undergraduate engineering admission)

The de Broglie wavelength of an electron accelerated through a potential difference V is proportional to:

  1. V
  2. √V
  3. 1/V
  4. 1/√V Correct answer.

Explanation

Kinetic energy eV gives momentum p = √(2meV), and λ = h/p. Therefore λ is proportional to 1/√V. Higher accelerating voltage means shorter wavelength.

Question 9Engineering & Technology (SRMJEEE undergraduate engineering admission)

Which set of quantum numbers is permissible for an electron in an atom?

  1. n = 3, l = 3, m = 0
  2. n = 3, l = 2, m = 3
  3. n = 2, l = 1, m = −1 Correct answer.
  4. n = 1, l = 1, m = 0

Explanation

The azimuthal quantum number must satisfy l ≤ n − 1, and the magnetic quantum number must satisfy −l ≤ m ≤ +l. For n = 2, l = 1, m = −1 all conditions hold.

Question 10Engineering & Technology (SRMJEEE undergraduate engineering admission)

Which molecule has a net dipole moment of zero despite containing polar bonds?

  1. HCl
  2. NH₃
  3. CO₂ Correct answer.
  4. H₂O

Explanation

CO₂ is linear, so the two C=O bond dipoles point in opposite directions and cancel. Water and ammonia are bent or pyramidal and retain a net dipole, while HCl is a simple polar diatomic.

Question 11Engineering & Technology (SRMJEEE undergraduate engineering admission)

What is the oxidation state of chromium in K₂Cr₂O₇?

  1. +7
  2. +3
  3. +4
  4. +6 Correct answer.

Explanation

Potassium contributes +2 and the seven oxygens contribute −14 overall. With two chromium atoms, 2x + 2 − 14 = 0 gives x = +6.

Question 12Engineering & Technology (SRMJEEE undergraduate engineering admission)

For the equilibrium N₂(g) + 3H₂(g) ⇌ 2NH₃(g), increasing the pressure at constant temperature will:

  1. Shift the equilibrium towards N₂ and H₂
  2. Change the value of the equilibrium constant
  3. Leave the equilibrium position unchanged
  4. Shift the equilibrium towards NH₃ Correct answer.

Explanation

Le Chatelier's principle predicts a shift towards the side with fewer gas molecules when pressure rises. Four moles of gas on the left become two on the right, so the forward reaction is favoured.

Question 13Engineering & Technology (SRMJEEE undergraduate engineering admission)

Which reagent converts a primary alcohol into a carboxylic acid in two effective oxidation stages?

  1. Acidified potassium dichromate(VI) under reflux Correct answer.
  2. Cold dilute NaOH
  3. Aqueous sodium chloride
  4. Sodium metal in ethanol

Explanation

Acidified dichromate(VI) is a strong oxidising agent that oxidises primary alcohols first to aldehydes and then to carboxylic acids under reflux. The other reagents do not oxidise the alcohol carbon.

Question 14Engineering & Technology (SRMJEEE undergraduate engineering admission)

The IUPAC name of CH₃–CH(CH₃)–CH₂–OH is:

  1. butan-1-ol
  2. 3-methylpropan-1-ol
  3. 2-methylpropan-2-ol
  4. 2-methylpropan-1-ol Correct answer.

Explanation

The longest chain containing the OH carbon has three carbons, so the parent is propan-1-ol. A methyl branch sits on carbon 2, giving 2-methylpropan-1-ol.

Question 15Engineering & Technology (SRMJEEE undergraduate engineering admission)

In a first-order reaction with rate constant k = 0.693 min⁻¹, what is the half-life?

  1. 1.0 min Correct answer.
  2. 1.44 min
  3. 0.693 min
  4. 2.0 min

Explanation

For a first-order reaction, t½ = 0.693/k. Substituting k = 0.693 min⁻¹ gives t½ = 1.0 min. Half-life is independent of initial concentration.

Question 16Engineering & Technology (SRMJEEE undergraduate engineering admission)

If A = [[1,2],[3,4]], what is the determinant of A?

  1. −2 Correct answer.
  2. 2
  3. 10
  4. −10

Explanation

For a 2×2 matrix [[a,b],[c,d]], the determinant is ad − bc. Here that is (1)(4) − (2)(3) = 4 − 6 = −2.

Question 17Engineering & Technology (SRMJEEE undergraduate engineering admission)

What is the value of ∫₀^{π/2} sin x dx?

  1. π/2
  2. 0
  3. 2
  4. 1 Correct answer.

Explanation

The antiderivative of sin x is −cos x. Evaluating from 0 to π/2 gives −cos(π/2) − (−cos 0) = 0 + 1 = 1.

Question 18Engineering & Technology (SRMJEEE undergraduate engineering admission)

The slope of the tangent to y = x³ − 3x at x = 2 is:

  1. 3
  2. 6
  3. 12
  4. 9 Correct answer.

Explanation

Differentiating gives dy/dx = 3x² − 3. At x = 2 this is 3(4) − 3 = 9. The slope of the tangent equals the derivative at that point.

Question 19Engineering & Technology (SRMJEEE undergraduate engineering admission)

A fair die is rolled twice. What is the probability that the sum of the two results is 7?

  1. 1/6 Correct answer.
  2. 1/12
  3. 1/9
  4. 5/36

Explanation

There are 36 equally likely ordered outcomes. Six of them sum to 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1). The probability is 6/36 = 1/6.

Question 20Engineering & Technology (SRMJEEE undergraduate engineering admission)

The value of lim(x→0) (sin 3x)/x is:

  1. 1
  2. 3 Correct answer.
  3. 0
  4. Does not exist

Explanation

Using the standard limit lim(t→0) sin t / t = 1, write (sin 3x)/x = 3·(sin 3x)/(3x). As x→0 the bracket tends to 1, so the limit is 3.

Question 21Engineering & Technology (SRMJEEE undergraduate engineering admission)

For the arithmetic progression 5, 9, 13, ..., what is the 20th term?

  1. 81 Correct answer.
  2. 77
  3. 89
  4. 85

Explanation

The first term is 5 and the common difference is 4. The nth term is a + (n−1)d = 5 + 19×4 = 81.

Question 22Engineering & Technology (SRMJEEE undergraduate engineering admission)

A body of mass 2 kg moves in a circle of radius 3 m at a constant speed of 4 m/s. What is the centripetal force?

  1. 24 N
  2. 32 N
  3. 8 N
  4. 10.7 N Correct answer.

Explanation

Centripetal force is mv²/r = 2 × 16 / 3 ≈ 10.7 N. The force points towards the centre and changes only the direction of velocity.

Question 23Engineering & Technology (SRMJEEE undergraduate engineering admission)

A Carnot engine operates between 500 K and 300 K. Its efficiency is:

  1. 80%
  2. 60%
  3. 40% Correct answer.
  4. 20%

Explanation

Carnot efficiency is 1 − T_cold/T_hot = 1 − 300/500 = 0.4, or 40%. It depends only on the absolute temperatures of the reservoirs.

Question 24Engineering & Technology (SRMJEEE undergraduate engineering admission)

A transistor is used in common-emitter configuration as an amplifier. Which statement about its current gain is correct?

  1. Current gain β is large and the output is 180° out of phase with the input Correct answer.
  2. Current gain α is less than 1 and the output is in phase
  3. Current gain β is small and the output is in phase with the input
  4. Current gain is zero because base current is zero

Explanation

In common-emitter mode the collector current is β times the base current, with β typically large. The collector voltage is inverted relative to the base input, giving a 180° phase shift.

Question 25Engineering & Technology (SRMJEEE undergraduate engineering admission)

A particle in a one-dimensional box of length L is in its ground state. Where is the probability density greatest?

  1. At x = L/4 and x = 3L/4
  2. It is uniform across the box
  3. At the centre x = L/2 Correct answer.
  4. At the walls x = 0 and x = L

Explanation

The ground-state wavefunction is proportional to sin(πx/L), so probability density is sin²(πx/L). This peaks at x = L/2 and vanishes at the walls.

Question 26Engineering & Technology (SRMJEEE undergraduate engineering admission)

A silicon diode is forward biased with a series resistor of 1 kΩ across a 5 V supply. Taking the diode's forward drop as 0.7 V, what current flows through the circuit?

  1. 4.3 mA Correct answer.
  2. 5.0 mA
  3. 0.5 mA
  4. 0.7 mA

Explanation

With the diode conducting, the resistor absorbs the supply voltage minus the diode drop, so the voltage across 1 kΩ is 5 − 0.7 = 4.3 V. Ohm's law then gives I = 4.3 V / 1000 Ω = 4.3 mA.

Question 27Engineering & Technology (SRMJEEE undergraduate engineering admission)

In a common-emitter amplifier, the input signal is applied to the base and the output is taken from the collector. What is the phase relationship between input and output voltage?

  1. Output lags the input by 270°
  2. Output is in phase with the input
  3. Output leads the input by 90°
  4. Output is 180° out of phase with the input Correct answer.

Explanation

Raising the base voltage increases collector current, which increases the drop across the collector resistor and therefore lowers the collector voltage. This inversion makes the common-emitter stage a 180° phase shifter between base and collector signals.

Question 28Engineering & Technology (SRMJEEE undergraduate engineering admission)

A Zener diode rated 6.2 V and 0.5 W is used as a shunt regulator. What is the maximum permitted Zener current?

  1. About 12.4 mA
  2. About 80.6 mA Correct answer.
  3. About 62 mA
  4. About 3.1 mA

Explanation

The power rating sets the limit through P = V·I, so the maximum current is 0.5 W / 6.2 V ≈ 0.0806 A. That equals roughly 80.6 mA, beyond which the junction may overheat.

Question 29Engineering & Technology (SRMJEEE undergraduate engineering admission)

A BJT has β = 100 and base current 20 μA in the active region. What are the collector and emitter currents?

  1. 2 mA and 2.02 mA Correct answer.
  2. 0.2 mA and 0.22 mA
  3. 20 mA and 20.02 mA
  4. 2 mA and 1.98 mA

Explanation

Collector current is β times base current, giving 100 × 20 μA = 2 mA. The emitter current is the sum of collector and base currents, 2 mA + 0.02 mA = 2.02 mA.

Question 30Engineering & Technology (SRMJEEE undergraduate engineering admission)

A JK flip-flop has J = 1 and K = 1 and is clocked repeatedly. What does the output do?

  1. It is reset to 0 and stays there
  2. It toggles on every clock edge Correct answer.
  3. It holds its previous state
  4. It is set to 1 and stays there

Explanation

When both J and K are high the flip-flop enters toggle mode, so each active clock edge complements the stored output. This is the classic divide-by-two behaviour used in counters.

Question 31Engineering & Technology (SRMJEEE undergraduate engineering admission)

The hexadecimal number 2F is converted to binary. Which 8-bit pattern is correct?

  1. 0010 1111 Correct answer.
  2. 0001 1111
  3. 0010 1110
  4. 0011 1111

Explanation

Each hex digit maps to four bits: 2 becomes 0010 and F (decimal 15) becomes 1111. Concatenating them gives 0010 1111, which equals decimal 47.

Question 32Engineering & Technology (SRMJEEE undergraduate engineering admission)

In an 8085 microprocessor, what is the width of the address bus and how much memory can it directly address?

  1. 16 bits, addressing 64 KB Correct answer.
  2. 12 bits, addressing 4 KB
  3. 8 bits, addressing 256 bytes
  4. 20 bits, addressing 1 MB

Explanation

The 8085 uses a 16-line address bus (A0–A15), which allows 2^16 distinct addresses. That corresponds to 65,536 bytes, conventionally called 64 KB.

Question 33Engineering & Technology (SRMJEEE undergraduate engineering admission)

A 4-bit successive-approximation ADC has a 5 V reference. What is its resolution in volts per step?

  1. 1.25 V
  2. 0.156 V
  3. 0.625 V
  4. 0.3125 V Correct answer.

Explanation

Resolution equals the reference voltage divided by the number of levels, 2^4 = 16. Thus 5 V / 16 = 0.3125 V per least significant bit.

Question 34Engineering & Technology (SRMJEEE undergraduate engineering admission)

An op-amp is wired as a non-inverting amplifier with feedback resistor 90 kΩ and input resistor 10 kΩ. What is the closed-loop gain?

  1. 9
  2. 10 Correct answer.
  3. 11
  4. 0.1

Explanation

For the non-inverting configuration the gain is 1 + (Rf/R1), so here 1 + 90/10 = 10. The input signal appears at the inverting node, and the feedback network scales it up.

Question 35Engineering & Technology (SRMJEEE undergraduate engineering admission)

A DC shunt motor draws 20 A from a 220 V supply and its armature resistance is 0.5 Ω. What is the back EMF?

  1. 210 V Correct answer.
  2. 230 V
  3. 220 V
  4. 200 V

Explanation

The armature voltage drop is I·Ra = 20 × 0.5 = 10 V. The back EMF is the supply voltage minus that drop, 220 − 10 = 210 V.

Question 36Engineering & Technology (SRMJEEE undergraduate engineering admission)

A three-phase induction motor runs at 1440 rpm when the supply frequency is 50 Hz and the machine has four poles. What is the slip?

  1. 4 percent Correct answer.
  2. 2 percent
  3. 10 percent
  4. 6 percent

Explanation

Synchronous speed is 120f/P = 120 × 50 / 4 = 1500 rpm. Slip equals (1500 − 1440)/1500 = 0.04, that is, 4 percent.

Question 37Engineering & Technology (SRMJEEE undergraduate engineering admission)

A single-phase transformer has 500 primary turns and 100 secondary turns, with 230 V applied to the primary. What is the secondary voltage at no load?

  1. 23 V
  2. 1150 V
  3. 230 V
  4. 46 V Correct answer.

Explanation

The turns ratio sets the voltage ratio, so Vs = Vp × (Ns/Np) = 230 × (100/500) = 46 V. The transformer is a step-down unit with a 5:1 ratio.

Question 38Engineering & Technology (SRMJEEE undergraduate engineering admission)

A balanced three-phase star-connected load has a phase impedance of 10 Ω and is supplied at 400 V line voltage. What is the phase current?

  1. About 13.3 A
  2. About 40 A
  3. About 23.1 A Correct answer.
  4. About 69.3 A

Explanation

In star connection the phase voltage is line voltage divided by √3, giving 400/1.732 ≈ 231 V. Dividing by the 10 Ω phase impedance yields about 23.1 A, which also equals the line current.

Question 39Engineering & Technology (SRMJEEE undergraduate engineering admission)

The voltage across a 100 μF capacitor changes at 50 V/s. What is the resulting capacitor current?

  1. 500 mA
  2. 50 mA
  3. 5 mA Correct answer.
  4. 0.5 mA

Explanation

For a capacitor, i = C·dv/dt. Substituting gives 100 × 10⁻⁶ F × 50 V/s = 5 × 10⁻³ A, which is 5 mA.

Question 40Engineering & Technology (SRMJEEE undergraduate engineering admission)

A coil of inductance 0.5 H carries a current that rises uniformly from 0 to 4 A in 0.2 s. What average EMF is induced in the coil?

  1. 10 V Correct answer.
  2. 40 V
  3. 0.4 V
  4. 2 V

Explanation

Faraday's law for self-induction gives |E| = L·(di/dt). Here di/dt = 4/0.2 = 20 A/s, so E = 0.5 × 20 = 10 V.

Question 41Engineering & Technology (SRMJEEE undergraduate engineering admission)

In a series RLC circuit at resonance, which statement about the impedance and current is correct?

  1. Impedance is minimum and current is maximum Correct answer.
  2. Current is zero because reactances cancel
  3. Impedance is purely capacitive
  4. Impedance is maximum and current is minimum

Explanation

At resonance the inductive and capacitive reactances are equal and opposite, so they cancel and leave only resistance. The impedance therefore falls to its lowest value R and the current reaches its largest value.

Question 42Engineering & Technology (SRMJEEE undergraduate engineering admission)

A strain gauge with gauge factor 2 is bonded to a steel member and experiences a strain of 500 microstrain. What fractional change in resistance occurs?

  1. 0.0005
  2. 0.01
  3. 0.002
  4. 0.001 Correct answer.

Explanation

The gauge factor relates fractional resistance change to strain by ΔR/R = G·ε. Thus 2 × 500 × 10⁻⁶ = 1 × 10⁻³, that is, 0.001.

Question 43Engineering & Technology (SRMJEEE undergraduate engineering admission)

A thermocouple is used to measure temperature and its output is fed to a high-impedance amplifier. Why is a high input impedance important here?

  1. The thermocouple has low output voltage and cannot supply significant current Correct answer.
  2. High impedance increases the Seebeck coefficient
  3. The thermocouple output is a current signal requiring a low load
  4. High impedance filters high-frequency noise

Explanation

A thermocouple produces only millivolts and has appreciable source resistance, so drawing current would load it and cause measurement error. A high-impedance input ensures negligible loading and preserves the open-circuit EMF.

Question 44Engineering & Technology (SRMJEEE undergraduate engineering admission)

A 3-bit flash ADC compares the input against a set of reference levels. How many comparators does it require?

  1. 3
  2. 7 Correct answer.
  3. 4
  4. 8

Explanation

An n-bit flash converter needs 2^n − 1 comparators to define the transition levels. For n = 3 that is 8 − 1 = 7 comparators.

Question 45Engineering & Technology (SRMJEEE undergraduate engineering admission)

A DC series motor is connected to a mechanical load that suddenly increases. What happens to its speed and armature current?

  1. Both speed and current fall
  2. Speed falls and armature current rises Correct answer.
  3. Speed rises and armature current falls
  4. Both speed and current rise

Explanation

A heavier load slows the rotor, reducing back EMF and allowing more armature current to flow. The increased current produces the larger torque needed to carry the load at the new lower speed.

Question 46Engineering & Technology (SRMJEEE undergraduate engineering admission)

An ideal transformer is rated 1 kVA at 200 V on the primary. If the secondary delivers its rated current at 50 V, what is that current?

  1. 20 A Correct answer.
  2. 0.05 A
  3. 50 A
  4. 5 A

Explanation

The rated primary current is 1000 VA / 200 V = 5 A, and the turns ratio is 200/50 = 4. The secondary current is therefore 5 A × 4 = 20 A, consistent with 1000 VA / 50 V.

Question 47Engineering & Technology (SRMJEEE undergraduate engineering admission)

A CMOS logic gate draws essentially no static current but dissipates power during switching. What is the dominant cause of this dynamic power loss?

  1. Resistive heating in the output transistors
  2. Inductive kickback from the supply rails
  3. Leakage through reverse-biased junctions
  4. Charging and discharging load capacitance Correct answer.

Explanation

Each switching transition must charge or discharge the capacitance at the gate output through the transistors. The energy stored and dumped in the capacitance each cycle, multiplied by switching frequency, accounts for most CMOS dynamic power.

Question 48Engineering & Technology (SRMJEEE undergraduate engineering admission)

A 555 timer is wired as an astable multivibrator with R1 = 10 kΩ, R2 = 10 kΩ and C = 1 μF. Which expression gives the output frequency?

  1. 1.44 / ((R1 + 2R2)·C) Correct answer.
  2. 1.44 / (R1·C)
  3. (R1 + R2) / (1.44·C)
  4. 1 / (2π√(R1·R2·C))

Explanation

In the standard astable configuration the capacitor charges through R1 + R2 and discharges through R2, giving a period of 0.693(R1 + 2R2)C. The frequency is therefore 1.44 divided by (R1 + 2R2)C.

Question 49Engineering & Technology (SRMJEEE undergraduate engineering admission)

A 4-bit R-2R ladder DAC uses a 2.5 V reference. What is the output voltage when only the most significant bit is set to 1?

  1. 0.625 V
  2. 1.25 V Correct answer.
  3. 0.3125 V
  4. 2.5 V

Explanation

In an R-2R ladder each bit contributes a binary-weighted fraction of the reference. The most significant bit of a 4-bit converter contributes half the reference, giving 2.5/2 = 1.25 V.

Question 50Engineering & Technology (SRMJEEE undergraduate engineering admission)

A moving-coil ammeter has a full-scale deflection of 1 mA and a coil resistance of 100 Ω. What shunt resistance is needed to extend its range to 10 mA?

  1. About 900 Ω
  2. About 11.1 Ω Correct answer.
  3. About 1 Ω
  4. About 100 Ω

Explanation

At full-scale 10 mA, 1 mA passes through the meter and the remaining 9 mA must pass through the shunt. The shunt therefore carries nine times the coil current at the same voltage, so it must be 100/9 ≈ 11.1 Ω.