Tamil Nadu HSE First Year Basic Electrical Engineering study materials
Tamil Nadu HSE First Year Basic Electrical Engineering study resources

Tamil Nadu HSE First Year Basic Electrical Engineering: Resistance and Resistor Networks

Tamil Nadu HSE First Year Basic Electrical Engineering · Work through your exam, one topic at a time.

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Resistance and Resistor Networks

This domain tests the physical origin of resistance, the effect of temperature, and the reduction of series–parallel networks to a single equivalent resistance.

Resistance from dimensions

R = ρl/A, where ρ is resistivity in ohm-metre, l the length in metres and A the cross-section in m². Resistance rises with length and falls with area; resistivity is a property of the material, resistance is a property of the specimen.

Temperature effect

For metals, R_t = R_0(1 + αt), where α is the temperature coefficient (positive for copper, aluminium, tungsten). Carbon, electrolytes and semiconductors have negative α, so their resistance falls on heating.

Networks

  • Series: R_s = R1 + R2 + … ; the same current flows through each resistor.
  • Parallel: 1/R_p = 1/R1 + 1/R2 + … ; the same p.d. appears across each.
  • Two resistors in parallel: R_p = R1R2/(R1 + R2).

Worked example

A copper wire of length 100 m and area 1 mm² (1 × 10⁻⁶ m²) has ρ = 1.7 × 10⁻⁸ Ω m. R = ρl/A = (1.7 × 10⁻⁸ × 100)/(1 × 10⁻⁶) = 1.7 Ω. If a 6 Ω and a 3 Ω resistor are joined in parallel across this combination in series with 4 Ω, the parallel part is (6 × 3)/(6 + 3) = 2 Ω, total 6 Ω; at 12 V the supply current is 2 A and the p.d. across the parallel pair is 4 V.

Traps

  • Adding parallel resistances directly instead of adding conductances.
  • Forgetting to invert 1/R_p at the end of the calculation.
  • Substituting mm² into the formula without converting to m².
  • Believing ρ changes with length; it changes with material and temperature only.
  • Ignoring the power rating of a resistor when it is used in a network.