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Question 1Engineering Materials and Their Properties
Which mechanical property of a metal allows it to be drawn into thin wires without fracture?
- Malleability
- Ductility Correct answer.
- Elasticity
- Brittleness
Explanation
Ductility is the ability of a material to undergo permanent deformation under tensile force, so it can be drawn into wires. Malleability is a similar property but refers to forming thin sheets by hammering or rolling. Brittle materials fracture without noticeable deformation, and elasticity is recovery after unloading.
Question 2Engineering Materials and Their Properties
In the production of engineering materials, pig iron is mainly obtained from which furnace?
- Bessemer converter
- Open-hearth furnace
- Electric arc furnace
- Blast furnace Correct answer.
Explanation
Pig iron is produced by reducing iron ore with coke and limestone in a blast furnace. The product contains a high percentage of carbon and is later refined into cast iron or steel. Bessemer, open-hearth and electric arc furnaces are steelmaking units.
Question 3Engineering Materials and Their Properties
Which of the following materials is classified as a non-ferrous metal?
- Stainless steel
- Mild steel
- Cast iron
- Aluminium Correct answer.
Explanation
Non-ferrous metals do not contain iron as the principal constituent; aluminium is a typical example. Cast iron, mild steel and stainless steel are ferrous materials because iron is their base element.
Question 4Engineering Materials and Their Properties
Which mechanical property is defined as the resistance of a material to permanent indentation?
- Toughness
- Hardness Correct answer.
- Creep
- Stiffness
Explanation
Hardness is the resistance offered by a surface to indentation, scratching or abrasion. Toughness is energy absorption before fracture, stiffness is resistance to elastic deformation, and creep is time-dependent deformation under sustained load.
Question 5Engineering Materials and Their Properties
Which cast iron contains carbon mainly as free graphite flakes and is widely used for machine tool beds because of its damping capacity?
- White cast iron
- Malleable cast iron
- Nodular cast iron
- Grey cast iron Correct answer.
Explanation
Grey cast iron contains carbon in the form of graphite flakes, which give it good vibration damping and machinability. White cast iron has carbon combined as cementite and is hard and brittle. Malleable cast iron is made by heat-treating white cast iron, while nodular cast iron contains spheroidal graphite.
Question 6Engineering Materials and Their Properties
The carbon content of ordinary mild steel is usually in the range of:
- 0.05–0.30% Correct answer.
- 0.60–1.00%
- 1.50–2.00%
- 2.50–4.00%
Explanation
Mild steel, also called low-carbon steel, contains about 0.05% to 0.30% carbon, which makes it ductile and weldable. Medium-carbon steels contain roughly 0.30–0.60% carbon, high-carbon steels about 0.60–1.00%, and cast irons generally above 2% carbon.
Question 7Engineering Materials and Their Properties
Which heat-treatment process involves heating steel above its critical temperature and then cooling it very slowly in the furnace?
- Normalising
- Annealing Correct answer.
- Quenching
- Tempering
Explanation
Annealing consists of heating steel to a suitable temperature above the critical range, holding it, and cooling slowly in the furnace. Slow cooling softens the steel, relieves internal stresses and improves machinability. Normalising cools in air, quenching uses a rapid cooling medium, and tempering is a reheating treatment after hardening.
Question 8Engineering Materials and Their Properties
Bronze is an alloy in which copper is the main metal and the principal alloying element is:
- Aluminium
- Nickel
- Zinc
- Tin Correct answer.
Explanation
Bronze is basically a copper–tin alloy, although small amounts of other elements may be added for specific properties. Brass, by contrast, is mainly a copper–zinc alloy. Copper–nickel and copper–aluminium alloys are known by their own specific names.
Question 9Engineering Materials and Their Properties
A shaft fails after many thousands of stress reversals. Which property should be specified to resist this type of failure?
- Impact toughness
- Creep resistance
- Surface hardness
- Fatigue strength Correct answer.
Explanation
Failure under repeated or alternating stresses is called fatigue, so the relevant design property is fatigue strength or fatigue limit. Creep resistance concerns slow deformation at high temperature, impact toughness concerns sudden loading, and surface hardness concerns indentation and wear.
Question 10Engineering Materials and Their Properties
Which of the following plastics is classified as a thermosetting material?
- Bakelite Correct answer.
- PVC
- Polyethylene
- Polystyrene
Explanation
Thermosetting plastics undergo irreversible cross-linking during curing, so they char rather than soften when reheated; Bakelite is a common phenolic thermosetting plastic. Polyethylene, PVC and polystyrene are thermoplastics that soften on heating and can be reshaped repeatedly.
Question 11Engineering Materials and Their Properties
The property of a metal that enables it to be hammered or rolled into thin sheets without cracking is known as:
- Malleability Correct answer.
- Ductility
- Toughness
- Elasticity
Explanation
Malleability is the property that allows a metal to be deformed in compression into thin sheets by hammering or rolling without cracking. Ductility involves tensile drawing into wire, elasticity is shape recovery, and toughness is energy absorption before fracture.
Question 12Engineering Materials and Their Properties
The ability of a material to absorb energy under sudden shock or impact loading without fracturing is called its:
- Creep resistance
- Hardness
- Stiffness
- Toughness Correct answer.
Explanation
Toughness is the ability of a material to absorb energy during impact or shock loading without fracturing. Hardness resists indentation, stiffness resists elastic deflection, and creep resistance limits slow deformation at high temperature.
Question 13Engineering Materials and Their Properties
The corrosion resistance of stainless steel is mainly due to the presence of which alloying element?
- Sulphur
- Manganese
- Nickel
- Chromium Correct answer.
Explanation
Chromium is the essential alloying element in stainless steel because it forms a thin, adherent passive oxide film on the surface that protects the metal from corrosion. Nickel improves toughness and some forms of corrosion resistance, but chromium is the element that makes steel stainless.
Question 14Engineering Materials and Their Properties
After a steel component has been hardened by quenching, it is usually given a tempering treatment in order to:
- convert the whole structure back to austenite
- increase the carbon content at the surface
- raise its hardness above the quenched value
- relieve internal stresses and reduce brittleness Correct answer.
Explanation
Quenching produces a hard but brittle martensitic structure with high internal stresses. Tempering reheats the steel to a temperature below the critical range to relieve those stresses and restore useful toughness while retaining adequate hardness.
Question 15Engineering Materials and Their Properties
Duralumin, widely used in aircraft structures, is an aluminium alloy whose principal alloying element is:
- Lead
- Silicon
- Copper Correct answer.
- Zinc
Explanation
Duralumin is an aluminium-copper alloy, typically containing about 3.5 to 4.5 percent copper with small additions of magnesium and manganese. Copper is its principal alloying element and gives the alloy the strength needed for aircraft structures after suitable heat treatment.
Question 16Engineering Materials and Their Properties
In cast iron, silicon is added mainly to:
- form hard cementite and make the iron brittle
- remove all carbon from the molten iron
- increase the sulphur content of the iron
- promote graphite formation and improve machinability Correct answer.
Explanation
Silicon is a powerful graphitising element in cast iron. It promotes the precipitation of carbon as graphite rather than cementite, which softens the iron and improves machinability, so silicon content is controlled carefully in grey cast iron.
Question 17Engineering Materials and Their Properties
A low-carbon steel gear is required to have a hard, wear-resistant surface and a tough core. The most suitable treatment is:
- Tempering
- Normalising
- Annealing
- Carburising Correct answer.
Explanation
Carburising is a case-hardening treatment in which low-carbon steel is heated in contact with a carbon-rich medium so that carbon diffuses into the surface. Subsequent quenching hardens the high-carbon case while the low-carbon core remains tough.
Question 18Engineering Materials and Their Properties
Babbit metal, widely used for plain bearings, is based mainly on which metal?
- Aluminium
- Tin Correct answer.
- Zinc
- Copper
Explanation
Tin-base Babbit metal is a low-friction bearing alloy containing mainly tin with antimony and copper. Its soft matrix with hard intermetallic particles gives good conformability and embeddability in plain bearings.
Question 19Engineering Materials and Their Properties
A fibre-reinforced plastic is preferred for boat hulls and sports equipment mainly because it provides:
- very low cost with easy sunlight decomposition
- complete resistance to every acid and solvent
- high strength-to-weight ratio and corrosion resistance Correct answer.
- high electrical conductivity and magnetic permeability
Explanation
Fibre-reinforced plastics combine strong, stiff fibres with a lightweight polymer matrix, giving a high strength-to-weight ratio and good corrosion resistance. These properties make them suitable for boat hulls, sporting goods, and aerospace panels.
Question 20Engineering Materials and Their Properties
In plain carbon steel, an excessive amount of sulphur is undesirable because it:
- improves the weldability of steel
- increases the ductility of steel
- raises the electrical conductivity
- causes hot shortness and brittleness Correct answer.
Explanation
Sulphur forms iron sulphide films at grain boundaries, and these low-melting films cause hot shortness when steel is rolled or forged at high temperature. Manganese is therefore added to combine with sulphur and form harmless manganese sulphide inclusions.
Question 21Engineering Materials and Their Properties
The slope of the initial straight-line portion of a metal's stress-strain diagram is used to determine which property?
- Hardness
- Young's modulus Correct answer.
- Percentage elongation
- Izod impact strength
Explanation
In the initial linear region the metal obeys Hooke's law, and the slope of the stress-strain line is Young's modulus, also called the modulus of elasticity. This property indicates the stiffness or rigidity of the material, that is, its resistance to elastic deformation under load. Hardness, elongation and impact strength are separate properties measured by other tests.
Question 22Engineering Materials and Their Properties
Spheroidal graphite (SG) cast iron obtains its nodular graphite structure mainly because of the addition of which element to the molten iron?
- Sulphur
- Magnesium Correct answer.
- Silicon
- Phosphorus
Explanation
A small addition of magnesium, or sometimes cerium, to molten cast iron makes the graphite solidify as nodules rather than flakes. This nodular graphite interrupts the metal matrix far less than flakes do, so SG iron has higher strength and ductility than ordinary grey cast iron. Silicon promotes graphite formation but does not produce the spheroidal shape.
Question 23Engineering Materials and Their Properties
For turning a hard workpiece at very high speed, the cutting-tool tip becomes red hot. Which material is preferred for the tip because it retains hardness at such temperatures?
- Grey cast iron
- Tungsten carbide Correct answer.
- High-carbon steel
- Aluminium bronze
Explanation
Tungsten carbide is a cemented carbide made by bonding hard tungsten carbide particles with cobalt, and it retains high hardness even when the tool tip becomes red hot. This hot hardness allows much higher cutting speeds than plain high-carbon steel tools, which soften on heating. Grey cast iron and aluminium bronze do not have the combination of hardness and hot strength needed for cutting-tool tips.
Question 24Engineering Materials and Their Properties
In the iron-carbon equilibrium diagram, the eutectoid point of plain carbon steel is at about 0.8% carbon and 723°C. On slow cooling through this point, austenite transforms into which microconstituent?
- Ferrite
- Cementite
- Pearlite Correct answer.
- Martensite
Explanation
At the eutectoid point, austenite of about 0.8% carbon decomposes on slow cooling into pearlite, which is a lamellar mixture of ferrite and cementite. The alternating soft ferrite and hard cementite lamellae give pearlite its characteristic property balance. Martensite, by contrast, requires rapid quenching rather than slow cooling.
Question 25Engineering Drawing and Graphical Representation
On a drawing sheet laid out as per BIS conventions, where is the title block normally placed?
- At the centre of the drawing area
- At the bottom right corner of the sheet Correct answer.
- At the top left corner of the sheet
- Along the entire top edge of the sheet
Explanation
The title block records the drawing number, title, scale, date and other identification data. Standard practice places it at the bottom right corner so that the folded sheet shows the title panel on the outside. Any other position would interfere with the drawing space or with standard folding.
Question 26Engineering Drawing and Graphical Representation
What is the standard trimmed size of an A2 drawing sheet?
- 841 mm × 1189 mm
- 297 mm × 420 mm
- 594 mm × 841 mm
- 420 mm × 594 mm Correct answer.
Explanation
In the ISO A-series, each size is obtained by halving the longer side of the previous size, so A0 is 841 mm × 1189 mm and A1 is 594 mm × 841 mm. Halving the 841 mm side of A1 gives the A2 sheet as 420 mm × 594 mm. This size is widely used for machine drawing sheets in the Higher Secondary practical work.
Question 27Engineering Drawing and Graphical Representation
In first-angle projection, how are the observer, the object and the plane of projection arranged?
- The object lies between the observer and the plane of projection Correct answer.
- The plane of projection lies between the observer and the object
- The observer lies between the object and the plane of projection
- The object and the plane of projection coincide with each other
Explanation
First-angle projection assumes that the object is placed between the observer and the plane of projection, so the plane is behind the object. The view is therefore projected through the object onto the plane. This is why in first-angle layout the top view appears below the front view and the left side view appears on the right.
Question 28Engineering Drawing and Graphical Representation
A drawing is prepared to a scale of 1:20. A line measures 35 mm on the drawing. What is its actual length?
- 175 mm
- 1400 mm
- 700 mm Correct answer.
- 70 mm
Explanation
A scale of 1:20 means one unit on the drawing represents twenty units of the real object. The actual length is therefore 35 mm × 20 = 700 mm, that is 0.7 m. Reducing scales with a representative fraction smaller than one are used when the object is too large to be drawn full size.
Question 29Engineering Drawing and Graphical Representation
In engineering drawing practice, hidden edges and hidden outlines are represented by which type of line?
- Long chain thin lines
- Short dashes of medium thickness Correct answer.
- Continuous thick lines
- Continuous thin wavy lines
Explanation
BIS line conventions reserve continuous thick lines for visible outlines and short dashed lines of medium thickness for edges that are hidden from the viewing direction. Long chain thin lines mark centre lines and pitch circles, while wavy lines are used for break lines. Keeping these conventions distinct prevents ambiguity in reading the drawing.
Question 30Engineering Drawing and Graphical Representation
In the aligned system of dimensioning, the dimension figures are placed:
- At the middle of the dimension line with the line broken
- Above the dimension line, readable from the bottom or right edge Correct answer.
- Outside the extension lines irrespective of the direction of the dimension line
- Below the dimension line and readable only from the top edge
Explanation
In the aligned system the figures are written above an unbroken dimension line and are oriented along it, so they can be read from the bottom or from the right-hand edge of the sheet. The unidirectional system instead keeps all figures horizontal and is read from the bottom only. Mixing the two systems on one drawing is not permitted.
Question 31Engineering Drawing and Graphical Representation
In the conventional representation of a screw thread, the root of an external thread is drawn as:
- A short dashed line
- A continuous thick line
- A continuous thin line Correct answer.
- A long chain line
Explanation
By convention the crest of the thread is drawn with a continuous thick line and the root with a continuous thin line, both parallel to the axis of the screw. For an internal thread the convention is reversed in terms of diameters but the root is still a thin line. Hatching in a sectional view is carried only up to the crest line.
Question 32Engineering Drawing and Graphical Representation
A cutting plane is stepped or bent so that it passes through a number of features that do not lie in one straight line. The resulting sectional view is called:
- A revolved section
- A half section
- A removed section
- An offset section Correct answer.
Explanation
An offset section uses a cutting plane bent at right angles to pass through holes, ribs or other features lying on different planes, and all of them are then shown in one section. A half section removes only one quarter of the object and is used for symmetrical parts. Revolved and removed sections describe where the sectional shape is drawn, not a stepped cutting plane.
Question 33Engineering Drawing and Graphical Representation
A line of true length 60 mm is to be drawn along an isometric axis. Taking the isometric scale as 0.816, what is its isometric length?
- 49.0 mm Correct answer.
- 30.6 mm
- 60.0 mm
- 73.5 mm
Explanation
In an isometric projection every true length is shortened along the axes by the isometric scale factor 0.816, so the drawn length is 60 mm × 0.816 = 48.96 mm, approximately 49.0 mm. In an isometric drawing, by contrast, full true lengths are measured along the axes and the drawing is larger than the projection. Candidates often confuse these two practices.
Question 34Engineering Drawing and Graphical Representation
In the hole-basis system of limits and fits, which of the following combinations gives a transition fit?
- H7/g6
- H7/p6
- H7/h6
- H7/k6 Correct answer.
Explanation
In the hole-basis system the hole deviation is fixed as H, so the type of fit depends on the shaft letter. Shafts g and h always give clearance fits, shaft k gives a transition fit that may be either clearance or interference, and shaft p gives an interference fit. Hence H7/k6 is the transition fit among the choices given.
Question 35Engineering Drawing and Graphical Representation
A cone is cut by a plane that is parallel to exactly one generator and does not pass through the vertex. Which conic section is produced?
- Ellipse
- Circle
- Hyperbola
- Parabola Correct answer.
Explanation
A conic section is classified by the angle that the cutting plane makes with the axis of the cone. When the plane is parallel to exactly one generator, the resulting curve has eccentricity equal to one and is a parabola. An ellipse requires the plane to cut all generators, while a hyperbola requires the plane to be parallel to the axis or steeper than a generator.
Question 36Engineering Drawing and Graphical Representation
The curve traced by a point on the circumference of a circle that rolls without slipping along a straight line is called a:
- Helix
- Involute
- Epicycloid
- Cycloid Correct answer.
Explanation
A cycloid is generated by a point on the circumference of a circle that rolls without slipping along a straight line. The rolling circle is called the generating circle, and the straight line is the base line. This definition distinguishes it from involute and helix curves.
Question 37Engineering Drawing and Graphical Representation
In a finished engineering drawing, the centre line used to show the axis of symmetry of a symmetrical part is drawn as which type of line?
- Continuous thin line
- Chain thin line Correct answer.
- Dashed thin line
- Continuous thick line
Explanation
Axes and lines of symmetry are shown by a chain thin line made of long and short dashes. Visible outlines use continuous thick lines, while hidden edges use dashed thin lines. Continuous thin lines are reserved for dimension lines and projection lines.
Question 38Engineering Drawing and Graphical Representation
A front view and top view of a machine block are to be arranged in first-angle projection. Where must the top view be placed relative to the front view?
- To the left of the front view
- To the right of the front view
- Below the front view Correct answer.
- Above the front view
Explanation
In first-angle projection the object lies between the observer and the plane of projection. The top view is therefore projected onto the plane below the object and is placed below the front view on the sheet. This is the reverse of third-angle placement.
Question 39Engineering Drawing and Graphical Representation
In a sectional view, the cut surface of a component is generally indicated by hatching lines drawn at what angle to the principal outlines?
- 30 degrees
- 45 degrees Correct answer.
- 60 degrees
- 90 degrees
Explanation
Cut surfaces in a sectional view are shown by evenly spaced thin section lines. These hatching lines are conventionally drawn at 45 degrees to the principal outlines of the part. The angle may be varied only to suit adjacent parts or special features.
Question 40Engineering Drawing and Graphical Representation
The development of the lateral surface of a right circular cone is a sector. The radius of this sector is equal to which dimension of the cone?
- Slant height Correct answer.
- Base circumference
- Vertical height
- Base radius
Explanation
When the lateral surface of a right circular cone is developed, it forms a sector of a circle. The radius of that sector equals the slant height of the cone, because every generator from apex to base is a slant height. The arc length of the sector equals the circumference of the cone base.
Question 41Engineering Drawing and Graphical Representation
When the front view and top view of an object are already drawn, which construction is used to transfer depths and obtain the side view?
- A 45-degree miter line Correct answer.
- A T-square edge
- A 30-degree set square line
- A 60-degree set square line
Explanation
A 45-degree miter line is drawn at the intersection of horizontal and vertical projection paths. It transfers depths from the top view to the side view while preserving alignment with the front view. Set squares and T-squares help draw the line, but the construction itself is the miter line.
Question 42Engineering Drawing and Graphical Representation
In welding representation, which symbol is used to indicate a fillet weld?
- A square
- A right-angled triangle Correct answer.
- A circle
- The letter V
Explanation
The fillet weld symbol is a right-angled triangle placed on the reference line of a welding symbol. The vertical leg of the triangle is drawn on the left side of the symbol. A V symbol denotes a single-V butt weld, while a circle indicates an all-around weld.
Question 43Engineering Drawing and Graphical Representation
A circle of 40 mm diameter lies in the top face of a cube and is drawn in isometric projection. The major axis of the resulting isometric ellipse is approximately:
- 56.6 mm
- 40.0 mm
- 48.8 mm Correct answer.
- 28.4 mm
Explanation
In isometric projection, a circle in a principal plane becomes an ellipse. The major axis of this ellipse is approximately 1.22 times the true diameter, so for 40 mm it is 1.22 times 40, which equals 48.8 mm. The minor axis would be about 0.71 times 40, which equals 28.4 mm.
Question 44Engineering Drawing and Graphical Representation
A square pyramid has a base side of 40 mm and an axis of 50 mm. It rests on its base on HP and is cut by a plane parallel to HP at 20 mm above the base. What is the true shape of the section?
- A rectangle of 40 mm by 24 mm
- A square of 40 mm side
- A square of 24 mm side Correct answer.
- A square of 20 mm side
Explanation
A section plane parallel to the base cuts the pyramid in a square that is similar to the base. At 20 mm above the base, the distance from the apex is 30 mm out of the 50 mm axis, so the linear scale is 30/50, which equals 0.6. The section side is therefore 40 times 0.6, which equals 24 mm.
Question 45Engineering Drawing and Graphical Representation
Which of the following is drawn using a continuous thin line in a finished engineering drawing?
- Hidden outlines of the object
- Dimension and extension lines Correct answer.
- Visible outlines of the object
- Centre lines of symmetrical parts
Explanation
Continuous thin lines are used for dimension lines, extension lines, leader lines and hatching. Visible outlines require continuous thick lines, hidden outlines require dashed lines, and centre lines require chain thin lines.
Question 46Engineering Drawing and Graphical Representation
In engineering drawing, a diagonal scale is constructed mainly to read which of the following?
- One unit only
- Angles in degrees
- Isometric lengths and angles
- Three units with fractions Correct answer.
Explanation
A diagonal scale is based on the principle of similar triangles, and it subdivides the smallest division into ten equal parts. It is therefore used to read three consecutive units, such as metres, decimetres and centimetres, together with fractions of the smallest unit.
Question 47Engineering Drawing and Graphical Representation
A half sectional view is best suited for which type of component?
- A symmetrical object with one quarter removed Correct answer.
- A completely irregular casting with no symmetry
- A thin sheet-metal part with no internal features
- A long solid shaft having no hollow portion
Explanation
A half sectional view is used for a symmetrical object: one quarter of the object is imagined to be removed so that one half of the view shows the section and the other half shows the exterior. This gives both internal and external details in a single view.
Question 48Engineering Drawing and Graphical Representation
A right circular cone of base diameter 60 mm and axis length 70 mm rests on its base on the HP. A plane parallel to the HP cuts the cone 30 mm above the base. What is the true shape and size of the section?
- An ellipse with major axis 60.0 mm
- A circle of diameter 34.3 mm Correct answer.
- A circle of diameter 30.0 mm
- A circle of diameter 60.0 mm
Explanation
A section plane parallel to the base of a cone produces a circle. The radius decreases linearly from 30 mm at the base to 0 at the 70 mm apex, so at 30 mm above the base the radius is 30 × (70 − 30)/70 = 17.14 mm; the diameter is therefore about 34.3 mm.
Question 49Applied Mechanics and Strength of Materials
The SI unit of stress in a mechanical member is:
- N/m
- N·m
- kg/m^3
- N/m^2 Correct answer.
Explanation
Stress is defined as internal resisting force per unit area, so its SI unit is the pascal, equal to one newton per square metre (N/m^2). The other units describe moment, distributed load and density respectively.
Question 50Applied Mechanics and Strength of Materials
Within the elastic limit, Hooke's law for a material states that:
- strain is directly proportional to the square of stress
- strain is inversely proportional to stress
- stress is independent of strain
- stress is directly proportional to strain Correct answer.
Explanation
Hooke's law states that within the elastic limit the stress produced is directly proportional to the strain. The constant of proportionality is the modulus of elasticity of the material.