Hokkaido Entrance Math study materials
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Hokkaido Entrance Math practice questions

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Question 1Numbers and Algebraic Expressions

Calculate the value of (-6) + (+4) - (-3).

  1. 1 Correct answer.
  2. -5
  3. 13
  4. -7

Explanation

Subtracting a negative number becomes addition, so -(-3) = +3. The expression becomes -6 + 4 + 3. Computing left to right: -6 + 4 = -2, then -2 + 3 = 1.

Question 2Numbers and Algebraic Expressions

Calculate the value of 5 - 3 × (-2) + (-8) ÷ 2.

  1. 15
  2. -5
  3. -8
  4. 7 Correct answer.

Explanation

Multiplication and division come before addition and subtraction: -3 × (-2) = +6 and (-8) ÷ 2 = -4. The expression becomes 5 + 6 - 4 = 7.

Question 3Numbers and Algebraic Expressions

Calculate 3/4 + 5/6 - 1/2.

  1. 7/6
  2. 5/12
  3. 19/12
  4. 13/12 Correct answer.

Explanation

Use the common denominator 12: 3/4 = 9/12, 5/6 = 10/12, and 1/2 = 6/12. Then 9/12 + 10/12 - 6/12 = 13/12, which is already in simplest form.

Question 4Numbers and Algebraic Expressions

Evaluate the expression 2x - 3y when x = 4 and y = -2.

  1. -2
  2. -14
  3. 2
  4. 14 Correct answer.

Explanation

Substitute the values: 2(4) - 3(-2) = 8 + 6 = 14. The key step is that -3y with y = -2 gives -3 × (-2) = +6.

Question 5Numbers and Algebraic Expressions

Simplify the expression 3(2a - b) - 2(a - 3b).

  1. 4a + 5b
  2. 4a - 9b
  3. 4a
  4. 4a + 3b Correct answer.

Explanation

Distribute each factor: 3(2a - b) = 6a - 3b and -2(a - 3b) = -2a + 6b. Combining like terms gives (6a - 2a) + (-3b + 6b) = 4a + 3b.

Question 6Numbers and Algebraic Expressions

Expand (x + 3)(x + 5).

  1. x² + 8x + 8
  2. x² + 15x + 8
  3. x² + 2x + 15
  4. x² + 8x + 15 Correct answer.

Explanation

Using (x + a)(x + b) = x² + (a + b)x + ab with a = 3 and b = 5: the coefficient of x is 3 + 5 = 8 and the constant term is 3 × 5 = 15. The result is x² + 8x + 15.

Question 7Numbers and Algebraic Expressions

Factor the expression x² - 9.

  1. (x - 3)²
  2. (x + 3)²
  3. (x - 9)(x + 1)
  4. (x - 3)(x + 3) Correct answer.

Explanation

This is a difference of squares: x² - 9 = x² - 3². Applying a² - b² = (a + b)(a - b) gives (x + 3)(x - 3).

Question 8Numbers and Algebraic Expressions

Calculate √18 + √8 - √2.

  1. 4√2 Correct answer.
  2. 4
  3. 5√2
  4. 3√2

Explanation

Simplify each radical: √18 = 3√2, √8 = 2√2, and √2 stays as is. Then 3√2 + 2√2 - √2 = 4√2.

Question 9Numbers and Algebraic Expressions

Rewrite 6/√3 with a rationalized denominator.

  1. 6√3
  2. 2√3 Correct answer.
  3. √3/2
  4. 3√3

Explanation

Multiply numerator and denominator by √3: (6 × √3)/(√3 × √3) = 6√3/3. Dividing 6 by 3 gives 2√3.

Question 10Numbers and Algebraic Expressions

Expand and simplify (x + 4)² - (x - 4)².

  1. 8x
  2. 0
  3. 16x Correct answer.
  4. 32

Explanation

Expand each square: (x + 4)² = x² + 8x + 16 and (x - 4)² = x² - 8x + 16. Subtracting gives (x² + 8x + 16) - (x² - 8x + 16) = 16x, since the x² and constant terms cancel.

Question 11Numbers and Algebraic Expressions

Factor the expression x² + 7x + 12.

  1. (x + 1)(x + 12)
  2. (x + 3)(x + 4) Correct answer.
  3. (x + 2)(x + 6)
  4. (x - 3)(x - 4)

Explanation

We need two numbers whose sum is 7 and whose product is 12. Those numbers are 3 and 4, so x² + 7x + 12 = (x + 3)(x + 4).

Question 12Numbers and Algebraic Expressions

Factor the expression 3x² - 12 completely.

  1. (3x - 4)(x + 3)
  2. 3(x - 2)²
  3. 3(x + 2)(x - 2) Correct answer.
  4. (3x + 2)(3x - 2)

Explanation

First factor out the common factor 3: 3x² - 12 = 3(x² - 4). Then x² - 4 is a difference of squares, giving 3(x + 2)(x - 2).

Question 13Numbers and Algebraic Expressions

Evaluate x² - 2xy + y² when x = 13 and y = 8.

  1. 25 Correct answer.
  2. -39
  3. 105
  4. 441

Explanation

The expression factors as (x - y)², so compute (13 - 8)² = 5² = 25. Recognizing the perfect-square form avoids the messy arithmetic of 169 - 208 + 64.

Question 14Numbers and Algebraic Expressions

Simplify (2/3)ab² × (-6a²b) ÷ (4ab³).

  1. -16a²
  2. a²
  3. -a²b³
  4. -a² Correct answer.

Explanation

Multiply the coefficients: (2/3) × (-6) ÷ 4 = -4 ÷ 4 = -1. For the variables, a × a² ÷ a = a² and b² × b ÷ b³ = b⁰ = 1, so the result is -a².

Question 15Numbers and Algebraic Expressions

Calculate (√5 + √3)(√5 - √3) + √18 ÷ √2.

  1. 2 + 3√2
  2. 8
  3. 3
  4. 5 Correct answer.

Explanation

The product is a difference of squares: (√5)² - (√3)² = 5 - 3 = 2. The division gives √(18/2) = √9 = 3, so the total is 2 + 3 = 5.

Question 16Numbers and Algebraic Expressions

Given x + y = 7 and xy = 10, find the value of x² + y².

  1. 29 Correct answer.
  2. 49
  3. 69
  4. 39

Explanation

Use the identity x² + y² = (x + y)² - 2xy. Substituting gives 7² - 2(10) = 49 - 20 = 29.

Question 17Numbers and Algebraic Expressions

Factor the expression x² - 5x - 36.

  1. (x + 9)(x - 4)
  2. (x - 9)(x + 4) Correct answer.
  3. (x - 12)(x + 3)
  4. (x - 6)(x + 6)

Explanation

We need two numbers with product -36 and sum -5. Those numbers are -9 and +4, so x² - 5x - 36 = (x - 9)(x + 4).

Question 18Numbers and Algebraic Expressions

Calculate (-1/2) + (2/3).

  1. 1/5
  2. 1/6 Correct answer.
  3. -1/6
  4. -7/6

Explanation

Convert to the common denominator 6: -1/2 = -3/6 and 2/3 = 4/6. Then -3/6 + 4/6 = 1/6.

Question 19Numbers and Algebraic Expressions

Simplify (x - 2)/3 + (x + 1)/4.

  1. (2x - 1)/7
  2. (7x - 5)/7
  3. (7x - 5)/12 Correct answer.
  4. (7x - 11)/12

Explanation

Use the common denominator 12: 4(x - 2)/12 + 3(x + 1)/12 = (4x - 8 + 3x + 3)/12. Combining like terms in the numerator gives (7x - 5)/12.

Question 20Numbers and Algebraic Expressions

Calculate √2 × √10 ÷ √5.

  1. √10
  2. 4
  3. 2√5
  4. 2 Correct answer.

Explanation

Combine under one root: √(2 × 10 ÷ 5) = √4 = 2. Equivalently, √2 × √10 = √20 = 2√5, and 2√5 ÷ √5 = 2.

Question 21Linear Equations and Functions

Solve the equation 3x - 7 = 8.

  1. x = 5 Correct answer.
  2. x = 1/3
  3. x = 15
  4. x = 3

Explanation

Add 7 to both sides: 3x = 15. Then divide both sides by 3: x = 5.

Question 22Linear Equations and Functions

Solve the equation -2x = 14.

  1. x = 7
  2. x = -7 Correct answer.
  3. x = -12
  4. x = 28

Explanation

Divide both sides by -2: x = 14 ÷ (-2) = -7. Dividing a positive number by a negative number gives a negative result.

Question 23Linear Equations and Functions

Solve the simultaneous equations: x + y = 10 and x - y = 4.

  1. x = 3, y = 7
  2. x = 7, y = 3 Correct answer.
  3. x = 14, y = 6
  4. x = 6, y = 4

Explanation

Add the two equations to eliminate y: 2x = 14, so x = 7. Substitute into the first equation: 7 + y = 10, giving y = 3.

Question 24Linear Equations and Functions

Solve the equation x² = 25.

  1. x = 12.5
  2. x = 5 only
  3. x = 25
  4. x = 5 and x = -5 Correct answer.

Explanation

Taking the square root of both sides gives x = ±√25 = ±5. Both 5 and -5 satisfy the equation because (-5)² = 25 as well.

Question 25Linear Equations and Functions

Solve the equation x² - 5x + 6 = 0.

  1. x = -1 and x = -6
  2. x = 2 and x = 3 Correct answer.
  3. x = 1 and x = 6
  4. x = -2 and x = -3

Explanation

Factor the left side: x² - 5x + 6 = (x - 2)(x - 3). Setting each factor to zero gives x = 2 or x = 3.

Question 26Linear Equations and Functions

Solve the equation 5(x - 2) = 3x + 4.

  1. x = 7 Correct answer.
  2. x = -3
  3. x = 14
  4. x = 3

Explanation

Expand the left side: 5x - 10 = 3x + 4. Subtract 3x from both sides: 2x - 10 = 4, then add 10: 2x = 14, so x = 7.

Question 27Linear Equations and Functions

Solve the simultaneous equations: 2x + 3y = 12 and x - y = 1.

  1. x = 4, y = 2
  2. x = 5, y = 4
  3. x = 3, y = 2 Correct answer.
  4. x = 2, y = 3

Explanation

From the second equation, x = y + 1. Substitute into the first: 2(y + 1) + 3y = 12, so 5y + 2 = 12 and y = 2. Then x = 2 + 1 = 3.

Question 28Linear Equations and Functions

Solve the equation x² + 7x + 10 = 0.

  1. x = 2 and x = 5
  2. x = -2 and x = -5 Correct answer.
  3. x = -1 and x = -10
  4. x = 1 and x = 10

Explanation

Factor: x² + 7x + 10 = (x + 2)(x + 5). Setting each factor to zero gives x = -2 or x = -5.

Question 29Linear Equations and Functions

Solve the equation 2x² - 5x - 3 = 0.

  1. x = -3 and x = -1/2
  2. x = 3 and x = 1/2
  3. x = -3 and x = 1/2
  4. x = 3 and x = -1/2 Correct answer.

Explanation

The equation factors as (2x + 1)(x - 3) = 0, giving x = -1/2 or x = 3. Check with the quadratic formula: x = (5 ± √(25 + 24))/4 = (5 ± 7)/4, which gives 3 and -1/2.

Question 30Linear Equations and Functions

Solve the inequality 3x - 5 > 7.

  1. x > 12
  2. x > 2/3
  3. x > 4 Correct answer.
  4. x < 4

Explanation

Add 5 to both sides: 3x > 12. Dividing by 3 (a positive number, so the direction stays) gives x > 4.

Question 31Linear Equations and Functions

Solve the inequality 2 - 3x ≥ 8.

  1. x ≥ -2
  2. x ≤ 2
  3. x ≥ -10/3
  4. x ≤ -2 Correct answer.

Explanation

Subtract 2 from both sides: -3x ≥ 6. Dividing by -3 reverses the inequality sign, giving x ≤ -2.

Question 32Linear Equations and Functions

A book is sold at a 20% discount for 960 yen. What was the original price?

  1. 1152 yen
  2. 1000 yen
  3. 768 yen
  4. 1200 yen Correct answer.

Explanation

Let the original price be x yen. After a 20% discount, 0.8x = 960, so x = 960 ÷ 0.8 = 1200 yen.

Question 33Linear Equations and Functions

A cyclist rides from town A to town B, 24 km apart, at 12 km/h, and returns along the same road at 8 km/h. How many hours does the round trip take?

  1. 6 hours
  2. 2.4 hours
  3. 4.8 hours
  4. 5 hours Correct answer.

Explanation

The outward trip takes 24 ÷ 12 = 2 hours and the return takes 24 ÷ 8 = 3 hours. The total is 2 + 3 = 5 hours.

Question 34Linear Equations and Functions

The sum of the digits of a two-digit number is 11. When the digits are reversed, the new number is 27 greater than the original. Find the original number.

  1. 74
  2. 56
  3. 38
  4. 47 Correct answer.

Explanation

Let the tens digit be a and the units digit be b. Then a + b = 11 and (10b + a) - (10a + b) = 27, which simplifies to 9(b - a) = 27, so b - a = 3. Solving the system gives a = 4 and b = 7, so the number is 47.

Question 35Linear Equations and Functions

How many grams of an 8% salt solution must be mixed with a 3% salt solution to make 500 g of a 5% salt solution?

  1. 250 g
  2. 300 g
  3. 100 g
  4. 200 g Correct answer.

Explanation

Let x be the grams of 8% solution; then (500 - x) is the grams of 3% solution. The salt equation is 0.08x + 0.03(500 - x) = 0.05 × 500 = 25, which gives 0.05x + 15 = 25, so x = 200 g.

Question 36Linear Equations and Functions

Solve the equation x² - 6x + 4 = 0.

  1. x = 3 ± 2√5
  2. x = 3 ± √5 Correct answer.
  3. x = 3 ± √20
  4. x = 6 ± √5

Explanation

Using the quadratic formula: x = (6 ± √(36 - 16))/2 = (6 ± √20)/2. Since √20 = 2√5, this simplifies to (6 ± 2√5)/2 = 3 ± √5.

Question 37Linear Equations and Functions

Solve the equation (x - 1)² = 2x - 1.

  1. x = 2 ± √2 Correct answer.
  2. x = 1 ± √2
  3. x = 4 ± 2√2
  4. x = 2 ± 2√2

Explanation

Expand the left side: x² - 2x + 1 = 2x - 1. Move everything to one side: x² - 4x + 2 = 0. The quadratic formula gives x = (4 ± √(16 - 8))/2 = (4 ± 2√2)/2 = 2 ± √2.

Question 38Linear Equations and Functions

A student has 1000 yen. After buying a 250-yen lunch, she wants to buy as many 90-yen notebooks as possible. What is the maximum number of notebooks she can buy?

  1. 10 notebooks
  2. 7 notebooks
  3. 9 notebooks
  4. 8 notebooks Correct answer.

Explanation

Let x be the number of notebooks. Then 250 + 90x ≤ 1000, so 90x ≤ 750 and x ≤ 8.33.... Since x must be a whole number, the maximum is 8 notebooks.

Question 39Linear Equations and Functions

For the direct proportion y = 3x, find the value of y when x = 4.

  1. 7
  2. 4/3
  3. 12 Correct answer.
  4. 81

Explanation

Substitute x = 4 into the equation: y = 3 × 4 = 12. In a direct proportion, y is simply the constant multiplied by x.

Question 40Linear Equations and Functions

y is inversely proportional to x, and y = 6 when x = 2. Find the equation relating x and y.

  1. y = 12/x Correct answer.
  2. y = 6/x
  3. y = 3x
  4. y = 8/x

Explanation

For inverse proportion y = a/x, the constant is a = xy = 2 × 6 = 12. So the equation is y = 12/x.

Question 41Linear Equations and Functions

What is the slope of the line y = -2x + 5?

  1. -2 Correct answer.
  2. 2
  3. -5
  4. 5

Explanation

In the form y = ax + b, the slope is a, the coefficient of x. Here a = -2, so the slope is -2; the 5 is the y-intercept.

Question 42Quadratic Functions and Equations

For the function y = 2x², find the value of y when x = 3.

  1. 18 Correct answer.
  2. 12
  3. 6
  4. 36

Explanation

Substitute x = 3: y = 2 × 3² = 2 × 9 = 18. Note that the square applies to x before multiplying by 2.

Question 43Linear Equations and Functions

The point (2, 6) lies on the graph of y = ax. Find the value of a.

  1. 12
  2. 4
  3. 3 Correct answer.
  4. 1/3

Explanation

Substitute x = 2 and y = 6: 6 = 2a, so a = 3. The constant of proportionality is always y ÷ x.

Question 44Linear Equations and Functions

A line has slope 2 and passes through the point (0, -3). Find the equation of the line.

  1. y = -3x + 2
  2. y = 2x - 3 Correct answer.
  3. y = 3x - 2
  4. y = 2x + 3

Explanation

A line with slope 2 has the form y = 2x + b. Since the point (0, -3) is on the y-axis, the y-intercept is -3, so the equation is y = 2x - 3.

Question 45Linear Equations and Functions

Find the equation of the line passing through the points (1, 3) and (3, 9).

  1. y = 3x Correct answer.
  2. y = 3x + 1
  3. y = 2x + 1
  4. y = 6x - 3

Explanation

The slope is (9 - 3)/(3 - 1) = 6/2 = 3. Using y = 3x + b with the point (1, 3): 3 = 3(1) + b, so b = 0. The equation is y = 3x.

Question 46Linear Equations and Functions

Find the coordinates of the intersection point of the lines y = 2x + 1 and y = -x + 7.

  1. (3, 4)
  2. (2, 5) Correct answer.
  3. (2, 3)
  4. (5, 2)

Explanation

Set the expressions equal: 2x + 1 = -x + 7, so 3x = 6 and x = 2. Substituting into y = 2x + 1 gives y = 5, so the intersection is (2, 5).

Question 47Linear Equations and Functions

y is inversely proportional to x, and y = 4 when x = 6. Find the value of y when x = 8.

  1. 16/3
  2. 2
  3. 12
  4. 3 Correct answer.

Explanation

The constant of proportionality is a = xy = 6 × 4 = 24, so y = 24/x. When x = 8, y = 24 ÷ 8 = 3.

Question 48Quadratic Functions and Equations

For the function y = x², find the rate of change (average rate) as x increases from 1 to 4.

  1. 4
  2. 3
  3. 15/4
  4. 5 Correct answer.

Explanation

The rate of change is (change in y) ÷ (change in x) = (16 - 1)/(4 - 1) = 15/3 = 5. For y = ax² this equals a(sum of the x-values) = 1 + 4 = 5.

Question 49Quadratic Functions and Equations

For the function y = (1/2)x² with domain -2 ≤ x ≤ 4, find the range of y.

  1. 2 ≤ y ≤ 8
  2. -2 ≤ y ≤ 8
  3. 0 ≤ y ≤ 8 Correct answer.
  4. 0 ≤ y ≤ 2

Explanation

Since the domain includes x = 0, the minimum value is y = 0 at the vertex. The maximum occurs at the endpoint farthest from 0: at x = 4, y = (1/2)(16) = 8. So the range is 0 ≤ y ≤ 8.

Question 50Linear Equations and Functions

The line y = x + 2 meets the x-axis and y-axis at two points. Find the area of the triangle these two points form with the origin.

  1. 1
  2. 2 Correct answer.
  3. 4
  4. 8

Explanation

The y-intercept is (0, 2) and the x-intercept is found from 0 = x + 2, giving (-2, 0). The triangle has legs of length 2 along each axis, so its area is (1/2) × 2 × 2 = 2.