Obstacle Clearance After V1: A Hot-Day Engine Failure at Plaisance
A twin-jet departs Plaisance (FIMP) RWY 14, TORA 3,040 m, aerodrome elevation 186 ft. Take-off weight 71,200 kg, OAT 31 °C, QNH 1010 hPa, wind calm. The departure has a close-in obstacle on the extended centreline: high ground with a mast, top 700 ft above aerodrome level, 4.5 nm beyond the end of the take-off distance available. The AFM gives a gross second-segment gradient of 4.2% for this weight, temperature and flap setting with the gear up, and the gradient decreases by about 0.10 percentage points per °C above 31 °C. For this exercise assume the net take-off flight path starts at 35 ft at the end of the TODA and continues as a straight line at the net gradient. At V1 (142 kt) the right engine fails after a bird strike and the crew continues the take-off. The aircraft has no fuel-jettison system; maximum landing weight is 66,300 kg.
1. Demonstrate whether the net take-off flight path clears the obstacle, and state the vertical margin.
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Net gradient
For a two-engine aeroplane the net take-off flight path is the gross gradient reduced by 0.8 percentage points:
4.2% − 0.8% = 3.4% net.
Height at the obstacle
4.5 nm = 4.5 × 6,076 = 27,342 ft horizontal.
Height gain = 0.034 × 27,342 = 930 ft.
Starting at 35 ft at the end of the TODA, the net path is at 35 + 930 = 965 ft above the take-off surface at the obstacle.
Margin
Obstacle top = 700 ft; required clearance = 35 ft, so the minimum acceptable net path height is 735 ft. Margin = 965 − 735 = 230 ft.
The departure is compliant, but the margin is only 230 ft - about 0.8% of gradient. That is the key operational point: at this weight and temperature the take-off is legal only because the numbers were checked; any change (weight, temperature, QNH, a later rotation, a slower flap retraction) erodes a small margin quickly.
2. At what OAT would this departure cease to be compliant at 71,200 kg, and what planning options would you use to restore the margin?
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Find the limiting gradient
The net path may not fall below 700 + 35 = 735 ft, i.e. a gain of 700 ft over 27,342 ft:
700 / 27,342 = 2.56% net → gross = 2.56 + 0.8 = 3.36%.
Temperature margin
Available gross at 31 °C = 4.2%; limiting gross = 3.36%. Difference = 0.84 percentage points.
At 0.10 percentage points per °C: 0.84 / 0.10 = 8.4 °C.
So the departure becomes non-compliant at approximately 39 °C, all else equal. Note how little is left: a 39 °C afternoon at Plaisance with a light wind is not unusual in the pre-cyclic season, and a lower QNH would reduce the margin further because the engine and the wing both see a higher pressure altitude.
Options to restore margin
- Reduce take-off weight (offload payload or fuel) - the most effective lever, since gradient improves with lower weight.
- Use a different flap setting or an improved-climb procedure, if approved in the AFM.
- Reduce the assumed temperature (more thrust) - but check the resulting V1 and accelerate-stop distance on the 3,040 m runway.
- Change departure runway, if terrain and wind allow, or negotiate a departure procedure with an early turn away from the obstacle.
What must not happen is dispatching on a calculation made at 31 °C and then departing at 38 °C because the wind was light and 'the aeroplane always climbs better than the book'.
3. After the engine failure the aircraft is airborne at 71,200 kg. Discuss the practical options for the return and landing.
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Flight path first
After the failure the priority is to fly the net flight path: hold V2 to the acceleration altitude, clean up, then either continue to the take-off alternate or enter the engine-out procedure. At 71.2 t and 31 °C the single-engine service ceiling is likely to be in the region of FL170–FL200, well above any terrain near Plaisance, so driftdown is not the constraint. The acceleration altitude must be chosen so as not to compromise obstacle clearance - it cannot simply be lowered to make the aeroplane clean up earlier.
Landing weight
Landing weight will be about 71,200 kg minus the fuel burnt in a short flight, perhaps 69,500–70,500 kg against an MLW of 66,300 kg. That is 3,000–4,000 kg overweight and the aircraft has no jettison system.
- Burning off 4,000 kg on one engine at low level would take roughly 2.5–3 hours. That is not a sensible trade against a contained engine failure on a serviceable airframe.
- The correct decision is to land overweight, with the following provisions: a long, stable approach with a low rate of descent at touchdown to limit the structural load; no autoland unless approved; minimum braking consistent with the runway length (3,040 m is ample, so brake energy can be kept low); fire and rescue services on standby; and an overweight-landing inspection entered in the technical log after the flight.
Weigh the risk: the flight risk is a damaged engine and a degraded climb capability on one engine; the landing risk is an overweight touchdown. A controlled overweight landing on a 3,040 m runway in good visibility is by far the smaller exposure.