PJENL Actuario Aptitude Exam study materials
PJENL Actuario Aptitude Exam study resources

PJENL Actuario Aptitude Exam: Mathematics (Calculus and Linear Algebra)

PJENL Actuario Aptitude Exam · Work through your exam, one topic at a time.

All guide sections

Mathematics (Calculus and Linear Algebra)

Mathematics (Calculus and Linear Algebra)

This domain tests the calculus and linear-algebra tools used throughout actuarial work: differentiation, integration, series, matrix operations, and eigenvalues. Items are usually short but unforgiving of sign and boundary errors.

Core rules and concepts

  • Derivative rules: product, quotient, chain; d/dx ln x=1/x, d/dx e^{ax}=a e^{ax}.
  • Integration by parts ∫u dv=uv−∫v du; substitution reverses the chain rule.
  • Taylor expansion about a: f(a)+f′(a)(x−a)+f″(a)(x−a)²/2!+…
  • Matrix inverse exists iff det(A)≠0; (AB)^{-1}=B^{-1}A^{-1}.
  • Eigenvalues solve det(A−λI)=0; eigenvectors solve (A−λI)v=0.
  • A symmetric matrix is positive definite iff all leading principal minors are positive.
  • Ax=b has a unique solution when A is invertible; otherwise check consistency.

Worked example

For A=[[2,1],[1,2]], det(A−λI)=(2−λ)²−1=λ²−4λ+3=(λ−1)(λ−3). Eigenvalues are 1 and 3. For λ=1, (A−I)v=[[1,1],[1,1]]v=0 gives v=(1,−1). For λ=3, v=(1,1). Both eigenvalues are positive, so A is positive definite.

Traps that cost marks

  • Dropping the inner derivative in a chain-rule calculation.
  • Forgetting the constant or mis-substituting limits in a definite integral.
  • Assuming det(A+B)=det(A)+det(B).
  • Treating a repeated eigenvalue as automatically diagonalizable.
  • Reversing the order in (AB)^{-1}.