In the number 47,382, what is the value of the digit 7?
- 70
- 7
- 7,000 Correct answer.
- 700
Explanation
The value of a digit depends on its place in the number. In 47,382 the digit 7 is in the thousands place, so its value is 7 × 1,000 = 7,000.
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The value of a digit depends on its place in the number. In 47,382 the digit 7 is in the thousands place, so its value is 7 × 1,000 = 7,000.
To round to the nearest hundred, look at the tens digit. The tens digit is 4, which is less than 5, so the hundreds digit stays 8 and the remaining digits become zero.
A factor divides the number exactly with no remainder. Since 36 ÷ 9 = 4, the number 9 is a factor of 36.
List the multiples of each number: 4, 8, 12, 16, … and 6, 12, 18, …. The smallest number appearing in both lists is 12.
Multiplying the numerator and denominator of a fraction by the same nonzero number gives an equivalent fraction. Multiplying both parts of 3/5 by 3 gives 9/15.
The decimal 0.75 means 75 hundredths, so it equals 75/100. Dividing the numerator and denominator by 25 gives 3/4.
Starting at −5 on the number line and moving 8 places to the right gives 3. Equivalently, 8 − 5 = 3 and the result is positive because 8 is larger in size than 5.
Multiplication is performed before addition unless brackets show otherwise. First compute 4 × 2 = 8, then add 3 to get 11.
To find a percentage of a quantity, write the percentage as a decimal and multiply. Here 0.15 × 240 = 36.
The ratio has 3 + 4 = 7 equal parts. One part is 84 ÷ 7 = 12, so the shares are 3 × 12 = 36 and 4 × 12 = 48. The smaller share is 36.
Rewrite the fractions with the common denominator 12: 2/3 = 8/12 and 1/4 = 3/12. Adding gives 8/12 + 3/12 = 11/12.
Multiply 6 by 4 to get 24, then place the decimal point so that the answer has two decimal places, because 0.6 and 0.4 each have one. Thus 0.6 × 0.4 = 0.24.
The common factors of 18 and 24 are 1, 2, 3, and 6, and the largest of these is 6. Prime factorisation gives 18 = 2 × 3² and 24 = 2³ × 3, so the HCF is 2 × 3 = 6.
Divide 72 repeatedly by prime numbers: 72 = 8 × 9 = 2³ × 3². Every factor in this product is prime and their product is 72.
In standard form a number is written as a value between 1 and 10 multiplied by a power of 10. Moving the decimal point 4 places to the right gives 4.5, so the power is −4.
A negative exponent means take the reciprocal of the corresponding positive power. Therefore 2⁻³ = 1/2³ = 1/8.
An increase of 15% means the new price is 115% of the old price. Thus 80 × 1.15 = 92 dirhams.
Since 7² = 49 and 8² = 64, the square root of 50 is greater than 7 but less than 8. Therefore √50 lies between 7 and 8.
Because 3 and 5 have no common factor other than 1, any number divisible by both must be divisible by their product, 3 × 5 = 15.
Divide the numerator by the denominator: 5 ÷ 8 = 0.625. This is a terminating decimal because the denominator 8 = 2³ contains only the prime factor 2.
When multiplying powers with the same base, add the exponents, and when dividing, subtract them. This gives 3^(4 + (−2) − 3) = 3⁻¹ = 1/3.
For two positive integers, the product of the numbers equals the product of their HCF and LCM. Thus the other number is (6 × 72) ÷ 18 = 432 ÷ 18 = 24.
After a 20% discount, the customer pays 80% of the original price. If 80% of the original price is 64, then the original price is 64 ÷ 0.8 = 80 dirhams.
Divide the numerical parts and subtract the exponents: 2.4 ÷ 8 = 0.3 and 10⁵ ÷ 10² = 10³. Thus the value is 0.3 × 10³ = 3 × 10².
An irrational number cannot be written as a fraction of two integers. Since 7 is not a perfect square, √7 is irrational, while √16 = 4, 0.25 = 1/4, and 22/7 are all rational.
The first two significant figures are 4 and 7. The next digit is 2, which is less than 5, so the 7 is not rounded up. Therefore the value is 0.047.
Multiply (−3) by (−4) to get 12 because the product of two negative numbers is positive. Then divide 12 by (−2), which gives −6 because a positive divided by a negative is negative.
Let x = 0.444... . Then 10x = 4.444... . Subtracting gives 9x = 4, so x = 4/9. This fraction is already in simplest form.
Three-fifths of 60 is 36 red sweets, leaving 24 sweets. One-quarter of 24 is 6 blue sweets, so the remaining 24 − 6 = 18 sweets are green.
Write each surd with the largest square factor removed: √72 = √36 × √2 = 6√2, and √18 = √9 × √2 = 3√2. Adding like surds gives 6√2 + 3√2 = 9√2.
Multiply each bracket by its coefficient, taking care with the negative sign on the second bracket: 6x − 15 − 2x + 8. Then collect like terms: 6x − 2x = 4x and −15 + 8 = −7.
Subtract 3x from both sides to gather the unknown terms: 2x − 7 = 9. Then add 7 to both sides to get 2x = 16, and divide by the coefficient 2 to obtain x = 8.
Substitute x = −2 into every occurrence of x: (−2)² − 3(−2) + 1. Since (−2)² = 4 and −3(−2) = +6, the value is 4 + 6 + 1 = 11.
Gradient is the change in y divided by the change in x between two points on the line. Here the change in y is 11 − 3 = 8 and the change in x is 5 − 1 = 4, so the gradient is 8 ÷ 4 = 2.
The expression is a difference of two squares, since x² − 9 = x² − 3². A difference of squares factorises as (a − b)(a + b), giving (x − 3)(x + 3).
A rational function is undefined only where its denominator equals zero. Solving x − 4 = 0 gives x = 4, so every other real number is allowed.
Add 5 to both sides to undo the subtraction: y + 5 = 3x. Then divide both sides by 3 to isolate x, giving x = (y + 5)/3.
When multiplying powers with the same base, add the indices: 3 + (−5) = −2. So the expression equals 2⁻², and a negative index means the reciprocal of the positive power, giving 1/4.
Look for two numbers that multiply to +6 and add to −5; these are −2 and −3. Factorising gives (x − 2)(x − 3) = 0, and by the zero product rule x = 2 or x = 3.
Rearrange the second equation as x = y + 1 and substitute into the first: 2(y + 1) + 3y = 12. This simplifies to 5y = 10, so y = 2, and then x = 2 + 1 = 3. Checking: 2(3) + 3(2) = 12 and 3 − 2 = 1.
Write y = 4x − 7, then swap the roles of x and y to get x = 4y − 7. Solving for y: x + 7 = 4y, so y = (x + 7)/4.
The notation gf(x) means g applied to the output of f, so substitute f(x) into g. This gives g(x + 2) = 3(x + 2) = 3x + 6.
By the remainder theorem, dividing a polynomial P(x) by (x − a) leaves remainder P(a). Here P(2) = 8 − 8 + 4 = 4.
By the factor theorem, (x − a) is a factor exactly when P(a) = 0. Testing a = 3 gives 27 − 18 − 15 + 6 = 0, so (x − 3) is a factor.
The number of real roots is determined by the discriminant b² − 4ac. Here b² − 4ac = 16 − 28 = −12, and a negative discriminant means there are no real roots.
Halve the coefficient of x to get p = 3, then subtract the square of that number. So x² + 6x + 5 = (x + 3)² − 9 + 5 = (x + 3)² − 4.
Write both sides as powers of 2: 32 = 2⁵, so 2^(x + 1) = 2⁵. Since the bases are equal, the indices must be equal, giving x + 1 = 5 and hence x = 4.
log₂8 asks for the power of 2 that gives 8, which is 3, and log₂4 = 2. Adding the values gives 3 + 2 = 5.
Factorising gives (x − 3)(x + 2) ≤ 0, so the parabola crosses the x-axis at x = −2 and x = 3. The parabola opens upwards, so it is at or below zero between the roots: −2 ≤ x ≤ 3.
Replacing x with (x − 2) shifts the graph 2 units in the positive x direction, so it moves right. Adding 3 outside the bracket shifts the graph 3 units in the positive y direction, so it moves up.