HSC Maths Ext 2 flashcards
HSC Maths Ext 2 · Build recall with a focused review session.
33 cards. Read the term and the definition here. The deck at the top of this page is optional.
- Proof by contradiction
- Assume the negation of the statement you want to prove, then derive a logical impossibility with a known truth. Concluding the original statement follows is valid because the negation cannot hold.
- Contrapositive equivalence
- The statement 'if P then Q' is logically equivalent to 'if not Q then not P'. Proving the contrapositive therefore proves the original implication, and this differs from assuming the negation.
- Disproof by counterexample
- A universal statement claims something for all cases. One valid case where the hypothesis holds but the conclusion fails is enough to disprove it; no general argument is needed.
- Irrationality of square root two
- Assume sqrt(2) equals a fraction a/b in lowest terms. Squaring gives 2b^2 = a^2, so a is even; writing a = 2c forces b even too, contradicting lowest terms.
- Dot product formula
- For vectors a and b, the dot product equals |a||b|cos(theta) and also the sum of componentwise products. It is zero exactly when the vectors are perpendicular, since cos(90 degrees) is zero.
- Cross product magnitude
- The magnitude of a cross b equals |a||b|sin(theta), the area of the parallelogram spanned by a and b. The cross product vector is perpendicular to both a and b by the right-hand rule.
- Vector equation of a line
- A line is written r = a + t d, where a is the position vector of one point on the line, d is a direction vector, and t is a real parameter taking every value.
- Distance from point to plane
- For a plane with unit normal n through point A, the perpendicular distance from point P is the absolute value of (P - A) dot n. Without a unit normal, divide by the magnitude of n.
- Scalar triple product
- The quantity a dot (b cross c) equals the signed volume of the parallelepiped with edges a, b and c. It is zero exactly when the three vectors are coplanar.
- Euler form of complex numbers
- Every complex number can be written r e^(i theta), where r is its modulus and theta its argument. Products multiply moduli and add arguments; quotients divide moduli and subtract arguments.
- De Moivre's theorem
- For any integer n, (cos theta + i sin theta)^n equals cos(n theta) + i sin(n theta). It converts powers of complex numbers into trigonometric multiples of the argument and vice versa.
- Roots of unity
- The n solutions of z^n = 1 are e^(2 pi i k/n) for k from zero to n minus one. They lie equally spaced on the unit circle and their sum is zero.
- Conjugate root theorem
- If a polynomial has real coefficients and z is a root, then the conjugate of z is also a root. Non-real roots therefore occur in conjugate pairs, allowing real factorisation into quadratics.
- Perpendicular bisector locus
- The set of points z satisfying |z - a| = |z - b| is the perpendicular bisector of the segment joining the points a and b in the complex plane, because both distances are equal.
- Derivative of arctangent
- The derivative of arctan x is 1/(1 + x^2) for all real x. This standard result underlies the integral of 1/(x^2 + a^2), which equals (1/a) arctan(x/a).
- Integration by parts
- The rule integral of u dv equals uv minus the integral of v du. Choosing u as the logarithmic or inverse trigonometric factor first usually simplifies the remaining integral.
- Trigonometric substitution
- For radicals, substitute x = a sin theta for a^2 - x^2, x = a tan theta for a^2 + x^2, and x = a sec theta for x^2 - a^2. Convert back using a right triangle.
- Parametric second derivative
- For parametric curves, dy/dx equals (dy/dt) divided by (dx/dt). The second derivative is the t-derivative of dy/dx, then divided again by dx/dt; it is not dy'/dx'.
- Volume of revolution
- Rotating y = f(x) about the x-axis between a and b gives volume pi times the integral of y squared dx. The shell method uses 2 pi times the integral of x y dx.
- Simple harmonic motion
- Motion satisfying acceleration equals minus omega squared times displacement. The solution is x = A cos(omega t + phi), with period 2 pi/omega and maximum speed A omega at the centre.
- Variable acceleration identity
- Acceleration equals the time derivative of velocity, and also velocity times the displacement derivative of velocity. The second form is used when acceleration is given as a function of position.
- Resisted motion
- When resistance is proportional to speed, the equation m dv/dt = -kv gives exponential decay of speed. For resistance proportional to speed squared, integrate 1/v^2 instead.
- Projectile range
- For projection speed v at angle theta over level ground with no air resistance, the horizontal range is v squared times sin(2 theta) divided by g, maximised at 45 degrees.
- Geometric series sum
- A geometric series with first term a and ratio r has partial sum a(r^n - 1)/(r - 1) for r not equal to 1. It converges to a/(1 - r) exactly when |r| < 1.
- Sum of squares formula
- The sum of k squared from k = 1 to n equals n(n + 1)(2n + 1)/6. Together with the sum of k and sum of k cubed, it evaluates polynomial series term by term.
- Telescoping series
- Writing each term as a difference f(k) minus f(k + 1) makes intermediate terms cancel in the partial sum. The sum then reduces to the first term minus the limiting last term.
- Ratio test
- For a series with positive terms, compute the limit of the ratio of consecutive terms. A limit below 1 gives convergence, above 1 gives divergence, and equal to 1 is inconclusive.
- General term of binomial expansion
- In the expansion of (a + b)^n, the term containing b^k is C(n, k) a^(n-k) b^k. Setting exponents equal to a target value solves for k and hence the coefficient.
- Pascal's identity
- The binomial coefficient C(n, k) equals C(n-1, k-1) + C(n-1, k). This identity generates Pascal's triangle, where each interior entry is the sum of the two above it.
- Sum of binomial coefficients
- Setting both terms to 1 in the binomial theorem gives the sum of C(n, k) from k = 0 to n equal to 2^n. Setting one term to -1 gives an alternating sum of zero.
- Greatest binomial coefficient
- Consecutive coefficients have ratio (n - k)/(k + 1). The coefficients increase while this ratio exceeds 1 and decrease afterwards, locating the largest term in the expansion.
- Principle of mathematical induction
- If a statement holds for a base integer and holding for n = k always implies holding for n = k + 1, then it holds for every integer at or beyond the base.
- Inductive step for sums
- Assume the sum formula holds for k terms. Then add the next term to both sides and simplify algebraically until the expression matches the formula with k replaced by k + 1.