Chemistry 30 Diploma case studies
Chemistry 30 Diploma · Put your knowledge to work in context.
Chemistry 30 Diploma is the provincial Grade 12 diploma examination written by students who have completed Chemistry 30 in Alberta. It is one of the diploma exams in the Grade 12 Diploma Examinations Program, which the province describes as having three main purposes: to certify the level of individual student achievement in selected Grade 12 courses, to ensure that provincewide standards of achievement are maintained, and to report individual and group results. The Chemistry 30 Diploma case studies are 5 cases and about 3,423 words.
1Coffee-Cup Calorimetry: Defending a Low Value for ΔH_neutralization
A student investigates the enthalpy of neutralization using a coffee-cup calorimeter. They combine 50.0 mL of 1.00 mol/L HCl(aq) with 50.0 mL of 1.00 mol/L NaOH(aq), both initially at 22.3 °C.
676 words, about 3 min2Tin–Silver Galvanic Cell: When the Voltmeter Disagrees with E°cell
Two students build a galvanic cell from a tin electrode in 1.00 mol/L Sn(NO₃)₂(aq) and a silver electrode in AgNO₃(aq), joined by a potassium nitrate salt bridge. The cell is kept in a dark cupboard.
661 words, about 3 min3Three Unlabelled Bottles: Identifying C₄ Compounds from Physical and Chemical Evidence
A laboratory receives three unlabelled bottles of colourless liquid. Bottle A (labelled C₄H₈O₂, Mr = 88) boils at 164 °C; its 0.10 mol/L aqueous solution has pH 2.9, and adding solid Na₂CO₃ produces vigorous bubbling.
691 words, about 3 min4Ammonia Buffer: Working Out How Much Acid It Can Really Absorb
A technician prepares 1.00 L of buffer solution containing 0.100 mol of NH₃ and 0.100 mol of NH₄Cl dissolved and made up to the mark with distilled water. For NH₄⁺, Ka = 5.6 × 10⁻¹⁰ (pKa = 9.25 at 25 °C).
680 words, about 3 min5Weak Acid HX: Settling a Dispute About the Approximation
A 0.150 mol/L solution of an unknown monoprotic weak acid, HX, has a measured pH of 2.62 at 25 °C. One student calculates Ka by substituting [HX] ≈ 0.150 mol/L directly into Ka = [H⁺]²/[HX] and obtains 3.8 × 10⁻⁵.
715 words, about 4 min