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Question 1Linear algebra
Find det [[2,1],[3,4]].
- 5 Correct answer.
- 8
- 11
- -5
Explanation
For a 2 by 2 matrix [[a,b],[c,d]], the determinant is ad - bc. Here it is 2*4 - 1*3 = 5.
Question 2Linear algebra
For A = [[a,1],[2,3]], for which condition is A invertible?
- a = 2/3
- a != 2/3 Correct answer.
- a = 0
- a != 3/2
Explanation
A 2 by 2 matrix is invertible exactly when its determinant is nonzero. det A = 3a - 2, so A is invertible when a != 2/3.
Question 3Linear algebra
Compute [[1,2],[0,1]] times the column vector (3,4).
- (11,4) Correct answer.
- (3,7)
- (7,4)
- (11,7)
Explanation
The first component is 1*3 + 2*4 = 11, and the second is 0*3 + 1*4 = 4.
Question 4Linear algebra
What are the eigenvalues of the diagonal matrix diag(2,5)?
- 2 and 5 Correct answer.
- 0 and 7
- 10 and 1
- Only 2
Explanation
For a diagonal matrix, the eigenvalues are its diagonal entries. Therefore the eigenvalues are 2 and 5.
Question 5Linear algebra
What is the rank of [[1,2],[2,4]]?
- 0
- 1 Correct answer.
- 2
- 4
Explanation
The second row is 2 times the first row, so there is only one independent row. The rank is 1.
Question 6Linear algebra
Which pair is linearly independent in R^2?
- (1,0) and (0,1) Correct answer.
- (1,2) and (2,4)
- (0,0) and (1,1)
- (3,3) and (1,1)
Explanation
The vectors (1,0) and (0,1) are the standard basis vectors and neither is a scalar multiple of the other. They are linearly independent.
Question 7Linear algebra
Solve the system x + y = 3 and x - y = 1.
- x = 1, y = 2
- x = 2, y = 1 Correct answer.
- x = 3, y = 1
- x = 0, y = 3
Explanation
Adding the equations gives 2x = 4, so x = 2. Then y = 1 from x + y = 3.
Question 8Linear algebra
Find the determinant of an upper triangular 3 by 3 matrix with diagonal entries 2, 3, and 4.
- 9
- 24 Correct answer.
- 12
- 0
Explanation
The determinant of a triangular matrix is the product of its diagonal entries. Thus det = 2*3*4 = 24.
Question 9Linear algebra
A 3 by 2 matrix has rank 2. What can be concluded about its two columns?
- They are linearly independent Correct answer.
- They are both zero
- They are equal
- They span R^3
Explanation
Rank 2 means there are two independent columns. Since the matrix has exactly two columns, both columns are linearly independent.
Question 10Linear algebra
For which k are the rows of [[1,k],[2,6]] linearly dependent?
- k = 2
- k = 3 Correct answer.
- k = 6
- No value of k
Explanation
Rows are dependent when the determinant is zero: 1*6 - 2k = 0. Thus k = 3.
Question 11Linear algebra
Find the determinant of a triangular 3 by 3 matrix with diagonal entries 1, -2, and 5.
- -10 Correct answer.
- 10
- -6
- 0
Explanation
For a triangular matrix, the determinant is the product of diagonal entries: 1*(-2)*5 = -10.
Question 12Linear algebra
Rows r1=(1,0,1), r2=(0,1,1), r3=(1,1,2) form a 3 by 3 matrix. What is its rank?
- 1
- 2 Correct answer.
- 3
- 0
Explanation
The third row equals r1 + r2, while r1 and r2 are independent. Therefore the rank is 2.
Question 13Linear algebra
A square linear system Ax = b has a unique solution for every b exactly when:
- det A = 0
- det A != 0 Correct answer.
- rank A = 0
- A has a zero row
Explanation
A square matrix gives a unique solution for every right-hand side exactly when A is invertible. This is equivalent to det A != 0.
Question 14Linear algebra
Which statement is true for A = [[1,1],[0,1]]?
- A has two distinct eigenvalues
- A has eigenvalue 1 with algebraic multiplicity 2 Correct answer.
- A is diagonal
- A has no real eigenvalues
Explanation
The characteristic polynomial is (lambda - 1)^2. Thus the only eigenvalue is 1, with algebraic multiplicity 2.
Question 15Linear algebra
Find the characteristic polynomial det(lambda I - A) for A = [[0,1],[-2,3]].
- lambda^2 + 3lambda + 2
- lambda^2 - 3lambda + 2 Correct answer.
- lambda^2 - 2lambda + 3
- lambda^2 + 2lambda - 3
Explanation
lambda I - A = [[lambda,-1],[2,lambda-3]]. Its determinant is lambda(lambda-3) + 2 = lambda^2 - 3lambda + 2.
Question 16Linear algebra
A 3 by 4 matrix has rank 2. What is the nullity of the associated linear map from R^4 to R^3?
- 1
- 2 Correct answer.
- 3
- 4
Explanation
By rank-nullity, nullity = number of columns - rank = 4 - 2 = 2.
Question 17Linear algebra
Are v1=(1,1,0), v2=(1,0,1), and v3=(0,1,1) linearly independent in R^3?
- Yes, because the determinant with these as columns is nonzero Correct answer.
- No, because there are three vectors
- No, because their entries sum to 2
- Yes, because each has two nonzero entries
Explanation
Using the vectors as columns gives determinant -2, which is nonzero. Therefore the three vectors are linearly independent.
Question 18Linear algebra
If A = diag(2, -1), what is A^2?
- diag(4,1) Correct answer.
- diag(2,1)
- diag(4,-1)
- diag(0,0)
Explanation
Squaring a diagonal matrix squares each diagonal entry. Thus A^2 = diag(2^2, (-1)^2) = diag(4,1).
Question 19Linear algebra
If B = P^(-1)AP, which quantity is always the same for A and B?
- Trace Correct answer.
- Every entry
- Every row sum
- Every column
Explanation
Similar matrices have the same trace, determinant, characteristic polynomial, and eigenvalues. Their individual entries, rows, and columns can change.
Question 20Linear algebra
A linear system Ax=b is consistent exactly when:
- rank(A) = rank([A|b]) Correct answer.
- rank(A) < rank([A|b])
- det A = 0 always
- b = 0 only
Explanation
The consistency criterion says Ax=b is consistent if and only if the coefficient matrix and augmented matrix have the same rank.
Question 21Linear algebra
The quadratic form q(x,y)=x^2+2xy+y^2 is:
- Positive definite
- Negative definite
- Positive semidefinite but not positive definite Correct answer.
- Indefinite
Explanation
q(x,y) = (x+y)^2, so it is always nonnegative. It equals 0 for nonzero vectors such as (1,-1), so it is not positive definite.
Question 22Linear algebra
Which describes the symmetric matrix [[2,1],[1,2]]?
- Positive definite Correct answer.
- Negative definite
- Singular
- Indefinite
Explanation
The leading principal minors are 2 and det = 3, both positive. Therefore the matrix is positive definite.
Question 23Linear algebra
A 2 by 2 matrix with two distinct eigenvalues is:
- Always diagonalizable over the field containing those eigenvalues Correct answer.
- Never diagonalizable
- Diagonalizable only if it is symmetric
- Always the identity matrix
Explanation
Distinct eigenvalues have linearly independent eigenvectors. A 2 by 2 matrix with two distinct eigenvalues therefore has an eigenbasis and is diagonalizable over that field.
Question 24Linear algebra
For an overdetermined least-squares problem Ax approximately equals b, the normal equations are:
- A^T A x = A^T b Correct answer.
- A A^T x = b
- A x = A^T b
- A^T x = b
Explanation
The least-squares residual is orthogonal to the column space of A, which gives A^T(b - Ax)=0. Rearranging yields A^T A x = A^T b.
Question 25Linear algebra
If A is 3 by 3 and det A = 4, what is det(2A)?
- 8
- 16
- 32 Correct answer.
- 4
Explanation
Multiplying a 3 by 3 matrix by scalar 2 multiplies the determinant by 2^3. Therefore det(2A)=8 det A = 32.
Question 26Linear algebra
For A = [[1,1],[0,1]], what is A^n for positive integer n?
- [[1,n],[0,1]] Correct answer.
- [[1,1],[0,n]]
- [[n,1],[0,n]]
- [[1,n^2],[0,1]]
Explanation
Write A = I + N where N = [[0,1],[0,0]] and N^2 = 0. Then (I+N)^n = I + nN = [[1,n],[0,1]].
Question 27Linear algebra
Why is A = [[2,1],[0,2]] not diagonalizable?
- It has no eigenvalues
- Its only eigenspace is one-dimensional Correct answer.
- Its determinant is zero
- It is symmetric
Explanation
The only eigenvalue is 2. Solving (A-2I)v=0 gives v2=0, so the eigenspace has dimension 1, not enough for a 2 by 2 eigenbasis.
Question 28Linear algebra
For M = [[1,a,0],[0,1,a],[a,0,1]], when is M singular over the real numbers?
- a = 0
- a = 1
- a = -1 Correct answer.
- All real a
Explanation
Expanding the determinant gives det M = 1 + a^3. Over the real numbers, this is zero exactly when a = -1.
Question 29Linear algebra
If A has full column rank n, what is true about A^T A?
- It is singular
- It is invertible Correct answer.
- It is the zero matrix
- It has rank 0
Explanation
For any nonzero x, x^T A^T A x = ||Ax||^2 > 0 because full column rank makes Ax nonzero. Thus A^T A is positive definite and invertible.
Question 30Linear algebra
The quadratic form 2x^2 + 4xy + 5y^2 has matrix [[2,2],[2,5]]. What is its definiteness?
- Positive definite Correct answer.
- Positive semidefinite only
- Indefinite
- Negative definite
Explanation
For the symmetric matrix, the leading principal minors are 2 and 2*5 - 2*2 = 6, both positive. Hence the form is positive definite.
Question 31Linear algebra
For the symmetric matrix [[2,1],[1,2]], which eigenvector corresponds to eigenvalue 3?
- (1,1) Correct answer.
- (1,-1)
- (0,1)
- (2,-1)
Explanation
Multiplying gives [[2,1],[1,2]](1,1) = (3,3) = 3(1,1). Thus (1,1) is an eigenvector for eigenvalue 3.
Question 32Linear algebra
For block upper triangular matrix [[A,B],[0,D]], with square A and D, what is its determinant?
- det(A) + det(D)
- det(A)det(D) Correct answer.
- det(B)
- 0 always
Explanation
A block triangular matrix has determinant equal to the product of the determinants of its diagonal blocks. The off-diagonal block B does not affect the determinant.
Question 33Multivariable calculus
For f(x,y) = x^2 + y^2, what is grad f at (1,-2)?
- (2,-4) Correct answer.
- (1,-2)
- (2,4)
- (-2,4)
Explanation
The gradient is (partial f/partial x, partial f/partial y) = (2x, 2y). At (1,-2), this is (2,-4).
Question 34Multivariable calculus
For f(x,y) = xy^2 + 3x, what is partial f/partial y at (2,1)?
- 2
- 4 Correct answer.
- 7
- 10
Explanation
Treat x as constant when differentiating with respect to y. partial f/partial y = 2xy, so at (2,1) the value is 4.
Question 35Multivariable calculus
If grad f = (1,2) and u = (3/5,4/5), what is the directional derivative in direction u?
- 7/5
- 11/5 Correct answer.
- 5
- 1
Explanation
The directional derivative is grad f dot u. Compute 1*(3/5) + 2*(4/5) = 3/5 + 8/5 = 11/5.
Question 36Multivariable calculus
Compute the double integral over 0 <= x <= 1, 0 <= y <= 2 of (x + y) dA.
- 2
- 3 Correct answer.
- 4
- 5
Explanation
Integrate with respect to y first: integral_0^2 (x+y) dy = 2x + 2. Then integral_0^1 (2x+2) dx = 1 + 2 = 3.
Question 37Multivariable calculus
Change the order of integration for integral_0^1 integral_0^x f(x,y) dy dx.
- integral_0^1 integral_y^1 f(x,y) dx dy Correct answer.
- integral_0^1 integral_0^y f(x,y) dx dy
- integral_0^x integral_0^1 f(x,y) dx dy
- integral_0^1 integral_0^1 f(x,y) dx dy
Explanation
The region is 0 <= y <= x <= 1. For a fixed y between 0 and 1, x runs from y to 1, giving integral_0^1 integral_y^1 f(x,y) dx dy.
Question 38Multivariable calculus
For z = x^2 y + sin y, what is partial z/partial x at (2,0)?
- 0 Correct answer.
- 4
- 1
- 5
Explanation
Treat y as constant. partial z/partial x = 2xy, and at (2,0) this equals 0.
Question 39Multivariable calculus
Use differentials to approximate the change in z = x^2 y at (1,2) when dx = 0.1 and dy = 0.2.
- 0.2
- 0.4
- 0.6 Correct answer.
- 0.8
Explanation
dz = z_x dx + z_y dy = (2xy)dx + (x^2)dy. At (1,2), dz = 4(0.1) + 1(0.2) = 0.6.
Question 40Multivariable calculus
For f(x,y)=x^2+xy+y^2, what is grad f at (1,1)?
- (2,2)
- (3,3) Correct answer.
- (1,1)
- (3,2)
Explanation
f_x = 2x + y and f_y = x + 2y. At (1,1), both components equal 3, so grad f = (3,3).
Question 41Multivariable calculus
What type of critical point does f(x,y)=x^2+y^2 have at (0,0)?
- Strict local minimum Correct answer.
- Strict local maximum
- Saddle point
- Not a critical point
Explanation
The function is nonnegative everywhere and equals 0 only at (0,0). Therefore the origin is a strict local minimum.
Question 42Multivariable calculus
Maximize xy subject to x + y = 10 with x > 0 and y > 0. What is the maximum value?
- 10
- 20
- 25 Correct answer.
- 50
Explanation
With fixed sum 10, the product xy is maximized at x = y = 5. The maximum is 25.
Question 43Multivariable calculus
Compute integral_0^1 integral_0^x x y dy dx.
- 1/4
- 1/8 Correct answer.
- 1/6
- 1/12
Explanation
For fixed x, integral_0^x x y dy = x*(x^2/2)=x^3/2. Then integral_0^1 x^3/2 dx = 1/8.
Question 44Multivariable calculus
Find the minimum of x^2 + y^2 subject to x + 2y = 5.
- 1
- 5 Correct answer.
- 25
- sqrt(5)
Explanation
The closest point on the line to the origin is parallel to the normal vector (1,2). Setting (x,y)=t(1,2) and x+2y=5 gives t=1, so (x,y)=(1,2) and the minimum value is 5.
Question 45Multivariable calculus
What type of critical point does f(x,y)=x^2-y^2 have at (0,0)?
- Strict local minimum
- Strict local maximum
- Saddle point Correct answer.
- No critical point
Explanation
The gradient is zero at the origin. Along the x-axis f=x^2 is positive, while along the y-axis f=-y^2 is negative, so the origin is a saddle point.
Question 46Limits and differential calculus
For f(x) = x^3 - 2x + 1, what is f'(2)?
- 8
- 10 Correct answer.
- 11
- 5
Explanation
Differentiate first: f'(x) = 3x^2 - 2. Substituting x = 2 gives 12 - 2 = 10.
Question 47Limits and differential calculus
What is the second derivative of e^(2x) at x = 0?
- 2
- 4 Correct answer.
- 1
- 0
Explanation
The first derivative is 2e^(2x), and the second derivative is 4e^(2x). At x = 0 this equals 4.
Question 48Limits and differential calculus
What is d/dx ln x at x = 1?
- 0
- 1 Correct answer.
- e
- -1
Explanation
The derivative of ln x is 1/x. At x = 1, the derivative equals 1.
Question 49Limits and differential calculus
Where does f(x) = x^2 + 4x have its critical point?
- x = -4
- x = -2 Correct answer.
- x = 0
- x = 2
Explanation
The derivative is f'(x) = 2x + 4. Setting it equal to zero gives x = -2.
Question 50Limits and differential calculus
What is the slope of the tangent line to y = x^2 at x = 3?
- 3
- 6 Correct answer.
- 9
- 12
Explanation
The slope is the derivative y' = 2x. At x = 3, the slope is 6.