Kaoyan Mathematics II - independent mathematical foundations study materials
Kaoyan Mathematics II - independent mathematical foundations study resources

Kaoyan Mathematics II - independent mathematical foundations: Differential Equations

Kaoyan Mathematics II - independent mathematical foundations · Work through your exam, one topic at a time.

All guide sections

Differential Equations

Differential-equation practice develops the ability to classify an equation, choose the right solution method, and apply initial or boundary conditions without losing constants along the way.

First order

  • Separable: separate and integrate, then apply the initial condition before rearranging if possible.
  • Linear y' + P(x)y = Q(x): integrating factor μ = exp(∫P dx), giving (μy)' = μQ.
  • For continuously differentiable coefficients on a suitable simply connected domain, ∂M/∂y = ∂N/∂x gives exactness of M dx + N dy; find a potential F with F_x = M and F_y = N. Locally, check the corresponding neighborhood assumptions.
  • Equilibria of y' = f(y) occur where f(y) = 0; the sign of f between equilibria gives stability on the phase line.

Second order linear, constant coefficients

  • Homogeneous: solve ar² + br + c = 0. Distinct real roots give Ae^{r₁x} + Be^{r₂x}; a repeated root gives (A + Bx)e^{rx}; complex α ± iβ gives e^{αx}(A cos βx + B sin βx).
  • Particular integral by undetermined coefficients; if the trial duplicates a complementary solution, multiply by a power of x equal to the relevant characteristic-root multiplicity.
  • General solution = complementary + particular; apply initial conditions last.

Worked example

Solve y' − y = e^{2x}, y(0) = 3. Here P = −1, so μ = e^{−x}. Multiply through: e^{−x}y' − e^{−x}y = e^{x}, i.e. (e^{−x}y)' = e^{x}. Integrate: e^{−x}y = e^{x} + C, so y = e^{2x} + Ce^{x}. Apply y(0) = 3: 1 + C = 3, so C = 2 and y = e^{2x} + 2e^{x}. Check: y' = 2e^{2x} + 2e^{x}, so y' − y = e^{2x}. Consistent.

Traps that cost marks

  • Sign error in the integrating factor: for y' − y = Q, P = −1, not +1.
  • Forgetting the x multiplier in the repeated-root case or when the forcing term resonates.
  • Applying the initial condition to the complementary function only.
  • Dividing by a variable that could be zero and losing a singular solution.
  • Writing x where the characteristic variable r belongs.