Part-66 Module 5 study materials
Part-66 Module 5 study resources

Part-66 Module 5: Numbering Systems and Data Conversion

Part-66 Module 5 · Work through your exam, one topic at a time.

All guide sections

Numbering Systems and Data Conversion

Weighted positional notation

Each digit is multiplied by the base raised to its position. Binary is base 2, octal base 8, hexadecimal base 16. Because 8 = 2^3 and 16 = 2^4, one octal digit equals exactly three bits and one hex digit exactly four bits: group bits outwards from the radix point to convert. Memorise the sixteen hex digits and their 4-bit patterns.

Negative numbers and codes

Two's complement is standard: invert every bit, then add 1. It has one zero and makes subtraction the same operation as addition. For n bits the range is -2^(n-1) to +2^(n-1)-1, so 8 bits hold -128 to +127. One's complement and sign-and-magnitude are distractors. BCD stores one decimal digit per nibble, so 0x25 in BCD is twenty-five, not thirty-seven. Gray code changes one bit per step and suits position encoders. Odd parity, used on ARINC 429, makes the total count of 1s odd.

Conversion and sampling

An n-bit converter has 2^n steps and a resolution of full-scale range divided by 2^n. Sampling must exceed twice the highest signal frequency (Nyquist) or aliasing results.

Traps

Confusing resolution with accuracy, treating BCD as ordinary binary, and forgetting the sign when a two's complement value has its most significant bit set.

Worked example

Take 1011 0110. Unsigned it is 128+32+16+4+2 = 182. As two's complement it is negative: invert to 0100 1001 and add 1, giving 0100 1010 = 74, so the value is -74. In hex, 1011 = B and 0110 = 6, so the byte is 0xB6.