GACE Middle Grades Mathematics (4-8) (704) study materials
GACE Middle Grades Mathematics (4-8) (704) study resources

GACE Middle Grades Mathematics (4-8) (704): Statistics and Probability

GACE Middle Grades Mathematics (4-8) (704) · Work through your exam, one topic at a time.

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Statistics and Probability

Statistics and Probability

This domain asks you to summarize data, judge how it was collected, and compute probabilities from a clearly defined sample space. Questions often hinge on interpretation: which measure of center is appropriate, what a graph does and does not show, and whether a probability should be conditional.

Core rules to hold

  • Center and spread: the mean is sensitive to outliers and skew; the median is resistant. Range, interquartile range (Q3 - Q1), and mean absolute deviation describe spread. A box plot displays the five-number summary: minimum, Q1, median, Q3, maximum.
  • Choosing a display: bar graphs compare categories, histograms and dot plots show distribution shape, box plots compare groups, scatterplots show association between two quantitative variables, and two-way tables support conditional reasoning.
  • Sampling: a random sample supports generalization to the population it was drawn from. Convenience samples, voluntary-response samples, and leading questions introduce bias that no amount of data cleaning removes.
  • Association: a line of best fit describes the direction and strength of a linear association. Correlation does not establish causation; a lurking variable may drive both.
  • Probability rules: probabilities lie between 0 and 1; P(not E) = 1 - P(E); for mutually exclusive events P(A or B) = P(A) + P(B); for independent events P(A and B) = P(A) times P(B); for dependent events multiply by the conditional probability.

Worked example

A bag holds 4 red and 6 blue marbles. Two are drawn without replacement. P(first red) = 4/10 = 2/5. Given that a red marble was removed, 3 red and 6 blue remain among 9 marbles, so P(second red given first red) = 3/9 = 1/3. Multiply: P(both red) = 2/5 times 1/3 = 2/15, about 0.133. The complement gives P(at least one blue) = 1 - 2/15 = 13/15. Drawing with replacement would instead give 4/10 times 4/10 = 4/25, a visibly different answer.

Traps that cost marks

  • Treating dependent draws as independent, or vice versa.
  • Confusing the probability of A and B with the probability of A or B.
  • Reading a median off a histogram by taking the tallest bar.
  • Claiming a sample is representative merely because it is large.
  • Interpreting a strong correlation as proof of cause and effect.