CHSE Odisha Elective Mathematics study materials
CHSE Odisha Elective Mathematics study resources

CHSE Odisha Elective Mathematics common mistakes

CHSE Odisha Elective Mathematics · Understand the traps and how to avoid them.

Mistake 1

Simplifies sin⁻¹(sin 5π/6) to 5π/6, or tan⁻¹(tan 3π/4) to 3π/4, without checking the principal-value range.

The identity sin⁻¹(sin x)=x is true only when x lies in [-π/2, π/2]; candidates memorize the identity and apply it to any angle, ignoring that inverse trigonometric functions return a unique principal value.

What to do instead

Before simplifying, write the range of the inverse function. For sin⁻¹(sin θ), reduce θ to an angle α in [-π/2, π/2] with the same sine (e.g. 5π/6 gives π/6); for cos⁻¹ use [0, π]; for tan⁻¹ use (-π/2, π/2). Check the quadrant and sign explicitly.

Mistake 2

Writes |2A|=2|A| for a 3×3 matrix A, or expands (A+B)² as A²+2AB+B².

Determinant is multilinear in rows and columns, so a scalar multiplying every entry of an n×n matrix contributes kⁿ; matrix multiplication is not commutative, so cross terms AB and BA cannot be merged.

What to do instead

State the order n before using |kA|=kⁿ|A|. For matrix algebra, keep AB and BA separate unless commutativity is given; use (A+B)²=A²+AB+BA+B². Check determinant row-operation effects: swapping rows changes sign, adding a multiple leaves it unchanged.

Mistake 3

Computes ∫₀² x/(x²−1) dx by directly applying ln|x²−1|/2 and substituting 0 and 2, even though x=1 lies inside the interval.

The integrand is undefined at x=1, so the integral is improper; a blind antiderivative hides the singularity and can produce a finite-looking but invalid answer.

What to do instead

Before integrating a definite integral, check continuity on the whole interval. Split at x=1 and write two limits; if either limit diverges, state that the integral diverges. For ordinary integrals, include +C and use ln|x| where appropriate.

Mistake 4

Tests continuity at x=a by calculating only f(a), or by finding left- and right-hand limits but not comparing them with f(a).

Continuity requires all three pieces: the two-sided limit exists and equals the function value; many candidates treat continuity as a one-sided or value-only condition.

What to do instead

Write the definition lim_{x→a⁻} f(x)=lim_{x→a⁺} f(x)=f(a). Compute both one-sided limits, state whether they are equal, and then check equality with f(a). For piecewise functions, evaluate the correct branch at the boundary.

Mistake 5

Uses ⁿP_r instead of ⁿC_r when forming a committee, or adds separate cases for 'at least one' without using the complement.

The candidate matches a formula to words like 'select' or 'arrange' without deciding whether order matters; 'at least one' is often much shorter as total minus none.

What to do instead

First decide whether order matters: selection → ⁿC_r, arrangement → ⁿP_r. For 'at least one', compute 1 − P(none) or total − none. For identical objects, divide by factorials of repeats; for circular arrangements, fix one object and arrange the rest.

Mistake 6

Finds stationary points of a continuous function on [a,b], evaluates f only at those points, and calls the largest value the maximum.

On a closed interval the absolute maximum or minimum can occur at an endpoint; the second derivative test can also be inconclusive when f''=0.

What to do instead

List all critical points in (a,b) plus the endpoints a and b. Evaluate f at every listed point and compare. Use the first-derivative sign change for local extrema; if f''=0, fall back to sign change or a table.

Mistake 7

Solves dy/dx = x, writes y=x²/2, and omits the arbitrary constant; or solves a second-order equation with only one constant.

Integration introduces one constant per integration, and the order of a differential equation equals the number of independent arbitrary constants in its general solution.

What to do instead

Integrate step by step and add +C after each integration. Count constants: first order → one, second order → two. Use initial conditions only after writing the general solution; when dividing by a variable, check for lost singular solutions.

Mistake 8

Finds the angle between a line and a plane by taking cos θ = |a·n|/(|a||n|), where a is the line direction and n is the plane normal.

The dot product gives the angle between the line and the normal, not between the line and the plane; these angles are complementary.

What to do instead

Use sin θ = |a·n|/(|a||n|) for the line-plane angle, or compute the line-normal angle φ and take θ=90°−φ. Also keep direction ratios and direction cosines distinct: cosines are normalized by the vector's length.

Mistake 9

Solves an LPP by testing only intersections of pairs of constraint lines, without checking which intersections lie in the feasible region or including axis intercepts.

The corner-point method requires all vertices of the feasible polygon, including intercepts on the axes; some line intersections are outside the feasible region.

What to do instead

Draw the feasible region, shade it, and list every vertex: axis intercepts and feasible line intersections. Evaluate the objective at each vertex. If the region is unbounded, check whether the objective can improve indefinitely; do not ignore non-negativity constraints.

Mistake 10

Uses P(A∩B)=P(A)P(B) for mutually exclusive events, or P(A∪B)=P(A)+P(B) for independent events.

Mutually exclusive means A∩B=∅; independent means P(A∩B)=P(A)P(B). The words are confused, and the formulas are memorized without their conditions.

What to do instead

Write definitions first. Mutually exclusive: P(A∩B)=0, so P(A∪B)=P(A)+P(B). Independent: P(A∩B)=P(A)P(B), so P(A∪B)=P(A)+P(B)−P(A)P(B). For conditional probability use P(A|B)=P(A∩B)/P(B) with P(B)>0.