Karnataka II PUC Electronics (KSEAB) study materials
Karnataka II PUC Electronics (KSEAB) study resources

Karnataka II PUC Electronics (KSEAB): Communication Systems

Karnataka II PUC Electronics (KSEAB) · Work through your exam, one topic at a time.

All guide sections

Communication Systems

What this domain tests

Need for modulation, AM and FM generation and detection, bandwidth and power calculations, and propagation and transmission media. Modulation index and power-distribution numericals appear regularly.

Core rules

  • Modulation is needed to radiate efficiently with practical antennas (λ/4 monopole), to multiplex many signals and to move the signal away from low-frequency noise.
  • AM produces carrier plus upper and lower sidebands. Modulation index m = Vm/Vc; bandwidth = 2fm; total power Pt = Pc(1 + m²/2); sideband power = Pc·m²/2.
  • AM efficiency = m²/(2 + m²), which peaks at 33.3 % when m = 1. Overmodulation (m > 1) causes envelope distortion and must be avoided.
  • FM keeps amplitude constant and varies frequency; modulation index mf = Δf/fm; Carson bandwidth ≈ 2(Δf + fm). FM has better noise immunity at the cost of wider bandwidth.
  • Propagation: ground wave below about 2 MHz, sky wave 3–30 MHz by ionospheric refraction, space wave above 30 MHz line of sight. Optical fibre works by total internal reflection.

Worked example

An AM transmitter radiates 100 W carrier with m = 0.5. Sideband power = Pc·m²/2 = 100 × 0.125 = 12.5 W, so Pt = 112.5 W. Efficiency = 12.5/112.5 = 11.1 %, and the bandwidth for a 5 kHz tone is 2 × 5 = 10 kHz. Raising m to 1 would give efficiency 33.3 % and Pt = 150 W.

Traps that cost marks

  • Using bandwidth = fm instead of 2fm for AM.
  • Believing AM efficiency can approach 100 %.
  • Forgetting that sideband power depends on m², not on m.
  • Stating that FM carries information in amplitude changes.