Route, Time and Daily Allowance for Eighteen Summons
You are a process server at the Mandal Court, Bhongir. On 18 September 2024 you must serve 18 summons in four villages. The route is: Court to Village A 12 km, A to B 9 km, B to C 15 km, and C back to Court 18 km. You travel by motorcycle at an average speed of 30 km/h. At each address, a successful service takes 20 minutes; an unsuccessful attempt takes 10 minutes. On that day, 12 defendants are available and 6 are not. You leave the court at 9:30 a.m. and must report back by 5:00 p.m. Your daily allowance is Rs. 150 for the first 20 km and Rs. 6 for every additional kilometre. You also get Rs. 25 for each successful service. There is a 30-minute lunch break if time permits. The route has no other stops.
1. Calculate total distance, travel time, service time including lunch, and expected return time. Can you meet the 5:00 p.m. deadline?
Read the worked answer
Total distance = 12 + 9 + 15 + 18 = 54 km. Travel time = 54 / 30 = 1.8 hours = 108 minutes. Service time = (12 x 20) + (6 x 10) = 240 + 60 = 300 minutes. Add 30 minutes for lunch = 438 minutes in all. 438 minutes = 7 hours 18 minutes. Starting at 9:30 a.m., the expected return is 9:30 + 7:18 = 4:48 p.m. This is before 5:00 p.m., so the deadline is met with 12 minutes to spare. Without lunch, the return would be 4:18 p.m.
2. Calculate the daily allowance and total remuneration for the day.
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Daily allowance: Rs. 150 for the first 20 km. Additional distance = 54 - 20 = 34 km. Additional allowance = 34 x Rs. 6 = Rs. 204. Total daily allowance = Rs. 150 + Rs. 204 = Rs. 354. Successful service remuneration = 12 x Rs. 25 = Rs. 300. The 6 unsuccessful attempts do not earn the Rs. 25 per-service amount. Total remuneration for the day = Rs. 354 + Rs. 300 = Rs. 654. This assumes the allowance and incentive are both payable and that no other deduction applies.
3. A bridge is closed and you must take an 11 km detour. If you also take the lunch break, do you still meet the deadline? What should you do?
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New distance = 54 + 11 = 65 km. Travel time = 65 / 30 = 2.1667 hours = 130 minutes. Total time = 130 + 300 + 30 = 460 minutes = 7 hours 40 minutes. Starting at 9:30 a.m., the return would be 5:10 p.m., which is 10 minutes late. The deadline is not met. To meet it, you could skip the lunch break: 130 + 300 = 430 minutes = 7 hours 10 minutes, giving a return at 4:40 p.m. If that is not possible, you should inform the court of the delay and the reason, rather than making a false endorsement. You should also record the detour and the actual times in your diary and return.