WBBSE Madhyamik Physical Science study materials
WBBSE Madhyamik Physical Science study resources

WBBSE Madhyamik Physical Science case studies

WBBSE Madhyamik Physical Science · Put your knowledge to work in context.

Madhyamik Physical Science is the Class X science paper of the West Bengal Board of Secondary Education (WBBSE) Madhyamik Pariksha, the first public board examination most students in the state sit. It is a single subject combining physics and chemistry: measurement and motion, force, work and energy, heat, sound, light, electricity and electromagnetism, plus matter and gas laws, atomic structure and bonding, metals, non-metals, electrolysis and organic chemistry. The WBBSE Madhyamik Physical Science case studies are 5 cases and about 1,965 words.

1

Corridor Measurement, Speed Claim and Pendulum Timing

During a school sports day, a student measures the length of a corridor with a metre scale whose first 2.0 cm has been worn away. She places the 2.0 cm mark at one end of the corridor and reads 86.4 cm at the other end.

404 words, about 2 min
2

Ramp Loading, Friction and Efficiency Trade-off

Workers are loading 50 kg sacks onto a truck using a wooden ramp 4.0 m long that is raised 1.2 m at the truck end. One worker pushes a sack up the ramp with a steady force of 180 N parallel to the ramp; he takes 6.0 s for one sack.

400 words, about 2 min
3

Ice-Water Calorimetry and Final State

100 g of ice at 0 °C is added to 300 g of water at 60 °C contained in a 200 g aluminium calorimeter. The specific heat capacity of water is 4.2 J g⁻¹ °C⁻¹, that of aluminium is 0.90 J g⁻¹ °C⁻¹, and the latent heat of fusion of ice is 336 J g⁻¹.

389 words, about 2 min
4

Household Circuit Overload and Broken Earthing

A room is wired to a 220 V supply through a 10 A fuse. The room contains a 1500 W electric heater, a 1000 W iron, and five 60 W lamps.

411 words, about 2 min
5

Impure Calcium Carbonate, Limiting Reagent and Gas Volume

In a school laboratory, 10.0 g of an impure calcium carbonate sample containing 80% CaCO3 by mass is treated with 100 mL of 2.0 M hydrochloric acid. The reaction is CaCO3 + 2HCl → CaCl2 + H2O + CO2.

361 words, about 2 min