Iran Nezam Mechanical Design Exam study materials
Iran Nezam Mechanical Design Exam study resources

Iran Nezam Mechanical Design Exam: Thermodynamics, Heat Transfer, and Energy Systems

Iran Nezam Mechanical Design Exam · Work through your exam, one topic at a time.

All guide sections

Thermodynamics, Heat Transfer, and Energy Systems

The energy block tests first and second law reasoning, power and refrigeration cycles, and the three heat transfer modes. Nezam items are usually one-step: an efficiency, a heat rate, a wall conductance, or a heat exchanger size.

Core rules

  • First law for steady flow: q − w = Δh + Δke + Δpe. For a Rankine cycle, w_net = w_turbine − w_pump, and η = w_net/q_in.
  • Carnot limit: η = 1 − T_L/T_H, always with absolute temperatures. COP_max for refrigeration = T_L/(T_H − T_L).
  • Conduction: Q = kAΔT/L, with R = L/kA. Convection: Q = hAΔT, R = 1/hA. Resistances in series add.
  • Heat exchangers: Q = UA·LMTD, with LMTD = (ΔT₁ − ΔT₂)/ln(ΔT₁/ΔT₂) for counterflow.
  • Combustion and boilers: heat rate in kJ/kWh = 3600/η; every 1% of efficiency is worth real fuel.

Worked example

Counterflow exchanger: hot stream 90 → 60 °C, cold stream 30 → 50 °C. ΔT₁ = 90 − 50 = 40 K, ΔT₂ = 60 − 30 = 30 K. LMTD = (40 − 30)/ln(40/30) = 10/0.2877 = 34.8 K. If UA = 2000 W/K, then Q = 2000 × 34.8 = 69.6 kW, which can be checked against the hot-stream capacity rate.

Traps

  • Using °C in Carnot or entropy expressions where kelvin is mandatory.
  • Applying the arithmetic mean temperature difference instead of the LMTD when the ratio exceeds about 2.
  • Confusing kW of cooling with COP; COP = Q_evap/W_compressor, both in the same units.