大学入学共通テスト - Independent foundational practice study materials
大学入学共通テスト - Independent foundational practice study resources

An inelastic collision

大学入学共通テスト - Independent foundational practice · Put your knowledge to work in context.

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An inelastic collision

Two small carts move on an ideal horizontal track with negligible external horizontal force during a short collision. Cart A has mass2.0kg and initially moves to the right at3.0m/s. Cart B has mass1.0kg and is initially stationary. The carts latch together after contact. The setup does not claim that mechanical energy is conserved during the impact, and no spring or rebound is involved. Students must first choose the conserved quantity, then calculate the common velocity and compare the kinetic energies before and after. A disagreement arises because one student treats the energy difference as proof that momentum was lost. Use the stated system boundary and the distinct definitions of momentum and kinetic energy to resolve that disagreement.

1. Calculate the common final velocity.

Read the worked answer

Initial momentum is2.0×3.0=6.0kg·m/s to the right. Dividing by the combined mass3.0kg gives2.0m/s to the right.

2. How much kinetic energy is lost, and does that contradict momentum conservation?

Read the worked answer

Initial kinetic energy is9.0J and final kinetic energy is6.0J, a loss of3.0J. Momentum and kinetic energy are different quantities; deformation and internal energy can account for the energy change.