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750 Feet of 16 AWG and a Misleading Commissioning Reading

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750 Feet of 16 AWG and a Misleading Commissioning Reading

One notification circuit leaves a 24 V addressable panel and runs 750 ft to the far end of a single-story distribution center before reaching the last appliance. The circuit uses 16 AWG stranded conductors in a multi-conductor cable. It carries eight wall-mounted horn/strobes. The manufacturer's data sheet lists each appliance at 0.075 A at 24 V, rated for 16–33 V, with published output ratings down to 16 V. The panel's listed NAC output is 24 V nominal and is listed to deliver not less than 20.4 V with the battery at end-of-discharge. At commissioning, with the battery at 27.0 V, the electrician measures 22.6 V at the last device and declares the circuit acceptable. The engineer's basis of design specified no more than 10% voltage drop to the last appliance.

1. Perform the worst-case voltage drop calculation and decide whether the circuit is acceptable.

Read the worked answer

Loop resistance. 16 AWG copper is about 4.89 Ω per 1,000 ft. Both conductors over 750 ft: R = 2 × 750 × (4.89 ÷ 1000) = 7.34 Ω

Load. 8 × 0.075 A = 0.60 A

Drop. 0.60 × 7.34 = 4.4 V

Worst case is not 27.0 V at the battery. Design is calculated with the panel's minimum NAC output at end-of-battery-discharge - 20.4 V here: 20.4 − 4.4 = 16.0 V at the last appliance

That is exactly the bottom of the appliance's 16–33 V range: zero margin. At 16 V the horn's sound output and the strobe's intensity fall below their published 24 V ratings, so the measured 22.6 V is misleading - it was taken from a fully charged battery that is not the worst-case condition.

The circuit also fails the engineer's criterion: 10% of 24 V is 2.4 V, and the calculated drop is 4.4 V.

2. Propose remedies and rank them. Which option may you not choose on your own authority, and why?

Read the worked answer
  1. Upsize the conductors. 14 AWG (≈3.07 Ω/1,000 ft) → R = 4.6 Ω, drop 2.76 V, 17.6 V at end of discharge. 12 AWG (≈1.93) → R = 2.9 Ω, drop 1.74 V, 18.7 V. Simplest fix on a new installation; costs a repull.
  2. Add a circuit extender / booster supply near the load. Best when the panel is near its NAC rating or the run is long; each appliance then draws locally and the drop problem largely disappears.
  3. Split into two circuits from the panel, halving current per circuit - only if spare NAC capacity exists.
  4. Reduce candela or remove appliances - the option you cannot take alone. Candela is set by space size and coverage, and audibility by ambient noise. Reducing either is a design change that must go back to the engineer of record with a re-check of coverage and sound levels.

Final caution: appliance current is not constant across voltage on all products. Use the manufacturer's voltage-drop tables (current at lowest expected voltage) rather than a single 24 V figure.

3. What must be measured and documented at acceptance?

Read the worked answer
  • Measure voltage at the last appliance on each circuit, with all appliances on that circuit active, with the panel operating on battery (or with end-of-discharge simulated by disabling the charger).
  • Record the measurements circuit by circuit, not as a single 'circuit OK' entry.
  • Confirm the measured value is at or above the minimum in the appliance's published voltage-drop table and that the resulting candela and dBA still meet the design and code minimums.
  • Verify supervision: open the circuit and ground it, and confirm the correct trouble annunciates.
  • File the as-built voltage drop calculation and the field measurements in the record of completion. A commissioning reading taken at float voltage is not a substitute for either.