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MARINA Chief Mate / Master Theoretical Exam study materials
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MARINA Chief Mate / Master Theoretical Exam practice questions

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Question 1Navigation

On a nautical chart, a light is described as 'Fl(3) WR 10s 24m 18M'. What does the '18M' indicate?

  1. The height of the light above chart datum in metres
  2. The nominal range of the light in nautical miles Correct answer.
  3. The distance of the light from the nearest port in nautical miles
  4. The period of the light in minutes

Explanation

In a chart light characteristic, the final figure followed by 'M' is the nominal range, the distance at which the light is visible in clear meteorological conditions. The height above datum is the figure followed by 'm' before it. Nominal range is stated in nautical miles.

Question 2Navigation

A vessel is steering 045° (T) and a prominent object bears 090° (T). What is the relative bearing of the object?

  1. 045° on the starboard bow
  2. 090° on the starboard beam Correct answer.
  3. 135° on the starboard quarter
  4. 045° on the port bow

Explanation

Relative bearing equals true bearing minus the vessel's heading: 090° − 045° = 045°, measured clockwise from the bow. A relative bearing of 090° places the object on the starboard beam. The relative bearing is not the same as the true bearing.

Question 3Navigation

What is the primary purpose of a gyrocompass in navigation?

  1. To determine the depth of water beneath the keel
  2. To measure the vessel's speed through the water
  3. To indicate true north by seeking the meridian independently of the earth's magnetic field Correct answer.
  4. To provide a magnetic heading corrected only by deviation

Explanation

A gyrocompass uses the earth's rotation and gravity to align its spin axis with the meridian, indicating true north without relying on magnetism. This makes it largely free of variation and deviation errors. Speed and depth are measured by other instruments.

Question 4Navigation

On an IALA Region A buoyage system, a vessel proceeding in the conventional direction of buoyage encounters a red can buoy. On which side should the vessel pass?

  1. Pass on the port side of the vessel Correct answer.
  2. Pass on the starboard side of the vessel
  3. Pass on either side, as the buoy marks a safe channel
  4. Pass on the side indicated by the buoy's topmark only

Explanation

In IALA Region A, red can buoys mark the port-hand side of the channel when proceeding in the conventional direction of buoyage. The vessel should therefore keep the red buoy on its port side. Green conical buoys mark the starboard-hand side.

Question 5Navigation

A vessel's log reads 120.0 at 0800 and 132.0 at 1200. What is the average speed through the water over that period?

  1. 3.0 knots Correct answer.
  2. 36.0 knots
  3. 12.0 knots
  4. 1.5 knots

Explanation

Distance run is 132.0 − 120.0 = 12.0 nautical miles over 4 hours. Speed equals distance divided by time: 12.0 ÷ 4 = 3.0 knots. This is the average speed through the water as recorded by the log.

Question 6Navigation

What does the term 'chart datum' normally represent on a nautical chart?

  1. The height of the highest astronomical tide at the charted location
  2. The level of mean sea level at the chart's central meridian
  3. The level below which water is assumed seldom to fall, to which soundings are reduced Correct answer.
  4. The elevation of the vessel's bridge above the waterline

Explanation

Chart datum is a low-water reference level chosen so that actual depths are usually greater than the charted soundings. Depths and drying heights are referenced to this datum. Heights of lights and elevations are also measured from it.

Question 7Navigation

In the context of passage planning, what is meant by the 'no-go area'?

  1. The area within a port's compulsory pilotage limits
  2. The portion of the chart where soundings are unreliable
  3. The region where radio communication is prohibited
  4. Water where a vessel's safe under-keel clearance or other constraints cannot be maintained Correct answer.

Explanation

No-go areas are defined during passage planning as water the vessel cannot safely enter given its draft, squat, tide and other margins. They are marked off to keep the planned track within safe water. They relate to the vessel's own constraints, not to pilotage or radio rules.

Question 8Navigation

A vessel is making good a course of 000° (T) at 10 knots. A current sets 090° (T) at 2 knots. What is the vessel's course steered through the water?

  1. Approximately 000° (T)
  2. Approximately 349° (T) Correct answer.
  3. Approximately 090° (T)
  4. Approximately 011° (T)

Explanation

The course to steer must counter the current. The current vector sets east at 2 knots, so the water course must be offset to the west of the desired track. Using the vector triangle, the angle is arcsin(2/10) ≈ 11.5°, giving a course of about 349° (T).

Question 9Navigation

When plotting a running fix from two bearings of the same object taken at different times, what additional information is essential?

  1. The vessel's course and distance run between the two observations Correct answer.
  2. The magnetic variation at the time of the second bearing
  3. The depth of water at the object's position
  4. The height of the observed object above sea level

Explanation

A running fix transfers the earlier position line forward using the vessel's course and distance run between observations. Without the advance, the two position lines cannot be combined into a fix. Object height and depth do not enter the running-fix construction.

Question 10Navigation

A vessel at anchor in a tidal stream is observed to swing through a full 360° over several hours. What is the most likely explanation?

  1. The tidal stream has reversed direction, causing the vessel to lie to the new stream Correct answer.
  2. The vessel is experiencing a steady current from one direction
  3. The vessel's gyrocompass has failed
  4. The anchor has dragged continuously in one direction

Explanation

When the tidal stream reverses at slack water, a vessel lying to the stream will swing round to lie to the new direction, producing a large change in heading. A steady current would keep the vessel on a roughly constant heading. Continuous dragging would show as a change of position, not a simple swing.

Question 11Navigation

In the IALA Maritime Buoyage System, what is the significance of a yellow special mark?

  1. It marks the safe water at the entrance to a channel
  2. It marks a special area or feature such as a spoil ground, pipeline or recreation zone Correct answer.
  3. It marks a new wreck with a cardinal indication
  4. It marks a hazard to be passed on the port side

Explanation

Special marks are yellow and indicate a special area or feature described on the chart, such as spoil grounds, pipelines, cables or recreation zones. They do not mark channel sides or hazards in the lateral sense. Their meaning is confirmed by the chart, not by a fixed passing side.

Question 12Navigation

A vessel's magnetic compass shows a heading of 090° (C). Deviation is 4° East and variation is 6° West. What is the true heading?

  1. 100° (T)
  2. 092° (T)
  3. 080° (T) Correct answer.
  4. 088° (T)

Explanation

Applying the rule 'deviation east, magnetic least; variation west, true least', the compass heading is reduced by the east deviation and then by the west variation. 090° − 4° = 086° (M), and 086° − 6° = 080° (T). Both corrections act in the same direction here.

Question 13Navigation

When using a radar to determine the risk of collision, what does a constant relative bearing with decreasing range indicate?

  1. The other vessel is stopped
  2. The other vessel is on a steady bearing and there is a risk of collision Correct answer.
  3. The other vessel is moving away from the observing vessel
  4. The other vessel is overtaking and will pass clear

Explanation

A steady relative bearing with decreasing range means the other vessel is maintaining a constant bearing relative to the observer, the classic indication of a risk of collision. The observing vessel should take avoiding action in good time. A changing bearing indicates the vessels will pass clear.

Question 14Navigation

What is the purpose of the parallel index technique in radar navigation?

  1. To monitor the vessel's cross-track distance from a planned track using a fixed range from a charted feature Correct answer.
  2. To measure the vessel's speed over the ground by comparing successive ranges
  3. To identify the aspect of a target vessel by its echo shape
  4. To determine the compass error by comparing radar and visual bearings

Explanation

In parallel indexing, a fixed range is set from a charted feature and the echo is kept on a line parallel to the planned track. The distance between the echo and the index line shows the cross-track error. It is a track-keeping aid, not a compass-error or aspect method.

Question 15Navigation

A vessel is on a course of 090° (T) at 12 knots. At 1000 a lighthouse bears 045° (T) at a range of 6 miles. At what time will the vessel be abeam of the lighthouse?

  1. 1017 Correct answer.
  2. 1045
  3. 1030
  4. 1035

Explanation

The bearing of 045° (T) is 45° on the bow from a course of 090° (T). The distance to the beam is 6 × cos 45° ≈ 4.24 miles. At 12 knots this takes about 21 minutes, so the vessel is abeam at approximately 1021, closest to 1017 among the options.

Question 16Navigation

Under the IALA system, what distinguishes a cardinal mark indicating 'east'?

  1. Two cones base-to-base and black over yellow colouring
  2. A single green cone topmark and green colouring
  3. Two cones point-to-point and yellow over black over yellow colouring Correct answer.
  4. A single red sphere topmark and red and white colouring

Explanation

An east cardinal mark has two cones base-to-base as its topmark and is coloured black over yellow over black, with a white light showing three flashes. The topmark points indicate the side on which safe water lies. The other combinations describe different cardinal or lateral marks.

Question 17Navigation

When transferring a position from a chart with one horizontal datum to a chart with a different horizontal datum, what correction is required?

  1. Apply the magnetic variation of the new chart
  2. Apply the tidal height difference between the two charts
  3. Apply the difference in chart scale between the two charts
  4. Apply the datum shift shown in the chart's note to convert the position to the new datum Correct answer.

Explanation

Different horizontal datums, such as WGS 84 and a local datum, produce a systematic offset in latitude and longitude. Charts carry a note giving the shift, which must be applied when transferring positions. Scale and tidal differences do not correct a horizontal datum offset.

Question 18Navigation

A vessel is proceeding along a narrow channel. What does a vertical sextant angle of a charted object allow the navigator to determine?

  1. The distance off the object, using its charted height and the sextant angle Correct answer.
  2. The set and drift of the tidal stream
  3. The vessel's speed over the ground
  4. The bearing of the object relative to the vessel's heading

Explanation

The vertical sextant angle subtended by a charted object of known height gives the distance off by simple trigonometry. The distance equals the height divided by the tangent of the angle, with a correction for the observer's height of eye. It does not give bearing or speed.

Question 19Navigation

What is the primary function of an Automatic Identification System (AIS) in navigation?

  1. To exchange vessel identity, position, course and speed data between equipped vessels and shore stations Correct answer.
  2. To measure the vessel's heading by sensing the earth's magnetic field
  3. To provide an accurate echo-sounding profile of the seabed
  4. To determine the vessel's position by satellite ranging

Explanation

AIS broadcasts and receives dynamic and static data such as identity, position, course over ground and speed over ground. It improves situational awareness and is used for collision avoidance and traffic monitoring. It does not measure depth, heading or position independently.

Question 20Navigation

A vessel's echo sounder reads 20 metres. If the transducer is 1 metre below the waterline and the charted depth is 18 metres, what is the under-keel clearance assuming the vessel's draft is 6 metres?

  1. About 15 metres Correct answer.
  2. About 12 metres
  3. About 19 metres
  4. About 13 metres

Explanation

The sounder measures depth below the transducer, so the true depth of water is 20 + 1 = 21 metres. Under-keel clearance is the depth of water minus the draft: 21 − 6 = 15 metres. The charted depth is not used directly in this calculation.

Question 21Navigation

In a passage plan, why is a 'wheel-over point' marked on the chart before a major course alteration?

  1. To indicate where the vessel should reduce speed for a traffic separation scheme
  2. To indicate where to begin the turn so the vessel settles on the new track at the intended position Correct answer.
  3. To mark the position where the pilot will board the vessel
  4. To show the location of the nearest safe anchorage

Explanation

A wheel-over point is the position at which the helm is put over so that the vessel's advance and transfer bring it onto the new track at the intended waypoint. It accounts for the vessel's turning characteristics and speed. It is not a pilot station or anchorage marker.

Question 22Navigation

A vessel's chronometer reads UTC 12:00:00. The vessel is at longitude 060° W. What is the local mean time?

  1. 04:00:00
  2. 12:00:00
  3. 16:00:00
  4. 08:00:00 Correct answer.

Explanation

Longitude 060° W corresponds to 4 hours of time difference, since 15° equals one hour. West longitude means local time is behind UTC, so local mean time is 12:00 − 4:00 = 08:00. East longitude would add the difference instead.

Question 23Navigation

A vessel is on a course of 000° (T) at 10 knots. At 1200 a light bears 030° (T) at a range of 8 miles. At what time will the light be abeam?

  1. 1255
  2. 1300
  3. 1230
  4. 1241 Correct answer.

Explanation

The light is 30° on the bow. The distance to the beam is 8 × cos 30° ≈ 6.93 miles. At 10 knots this takes about 0.693 hours, or roughly 41.6 minutes, so the light is abeam at about 1242, closest to 1241 among the options.

Question 24Navigation

When using a single position line obtained from a celestial observation, what is the standard way to obtain a fix?

  1. Plot the position line alone and accept the nearest point to the dead reckoning position
  2. Plot the position line and use the vessel's log reading to fix the position along it
  3. Combine it with a transferred position line or with a second observation taken at a different time or azimuth Correct answer.
  4. Use the position line together with the vessel's compass heading only

Explanation

A single position line only constrains the vessel to a line of position, so a fix requires a second intersecting line. This may be another celestial body observed at a different azimuth or a transferred line from an earlier observation. The dead reckoning position is used to choose the most probable point, not as a true fix.

Question 25Navigation

Two vessels are in a crossing situation, and the give-way vessel is unable to take avoiding action alone. What does the stand-on vessel's obligation require?

  1. It must stop immediately and wait for the give-way vessel to pass
  2. It must maintain course and speed until a collision is unavoidable
  3. It must always alter course to port to pass astern of the give-way vessel
  4. It may take action as soon as it becomes apparent that the give-way vessel is not taking appropriate action Correct answer.

Explanation

The stand-on vessel must keep its course and speed initially, but may take action as soon as it becomes apparent that the give-way vessel is not taking appropriate action. If necessary it must act to avoid collision. It should not wait until collision is unavoidable.

Question 26Navigation

On a Mercator chart, the length of a minute of latitude measured at the latitude of the vessel is used for measuring distance because the scale of latitude on this projection:

  1. increases with latitude in the same proportion as the scale of longitude Correct answer.
  2. decreases towards the poles while longitude scale increases
  3. is equal to the scale of longitude only at the equator and at 45° latitude
  4. remains constant over the whole chart at every latitude

Explanation

On a Mercator chart the meridians are drawn as parallel straight lines, so the longitude scale is constant, but the latitude scale expands towards the poles by the secant of the latitude. Because both scales expand together, a minute of latitude measured at the vessel's own latitude represents one nautical mile. Measuring distance from the latitude scale near the top or bottom of the chart therefore introduces error.

Question 27Navigation

A vessel steering 045° (T) observes a steady light bearing 090° (T) with the range slowly decreasing. Which statement correctly describes the situation?

  1. The light is being left on the port quarter and no risk of collision exists
  2. The bearing is steady and a risk of collision exists, so avoiding action is required Correct answer.
  3. The bearing is broadening and the vessel will pass ahead of the light
  4. The bearing is constant because the light is a fixed aid and cannot be used for collision assessment

Explanation

A constant relative bearing with decreasing range means the two vessels (or vessel and fixed object) are on converging courses and will collide if neither alters. The other vessel would appear on a steady bearing at the same relative angle throughout the approach. Action should be taken in ample time and be large enough to be readily apparent.

Question 28Navigation

In the IALA Maritime Buoyage System, a preferred channel mark at a bifurcation is identified by which combination?

  1. Red and white vertical stripes with a spherical topmark
  2. Blue and yellow vertical stripes with a single yellow cone pointing up
  3. Yellow and black chequered pattern with an 'X' topmark
  4. Red and green horizontal bands with a can or conical topmark matching the preferred side Correct answer.

Explanation

A bifurcation mark has red and green horizontal bands; the colour of the upper band, and the shape of the topmark (can for preferred port channel, cone for preferred starboard channel in Region A), shows which side carries the preferred channel. The mark may be passed on either side, but the preferred channel is the one indicated by the topmark and upper band colour.

Question 29Navigation

The charted tidal stream atlas shows a spring rate of 2.4 knots at a position for the hour required. If the range of the day is 60% of the mean spring range, what stream rate should be used?

  1. 2.4 knots
  2. 3.6 knots
  3. 1.4 knots Correct answer.
  4. 0.6 knots

Explanation

Stream rates in a tidal atlas are tabulated for mean springs, and the rate for a smaller range is obtained by applying the spring/neap factor. A range of 60% of mean springs gives 0.6 × 2.4 = 1.44 knots, rounded to about 1.4 knots. The factor should be taken from the range ratio in the atlas rather than assumed.

Question 30Navigation

A vessel's gyrocompass reads 137° and the gyro error is known to be 2° low. What is the true heading?

  1. 137°
  2. 139° Correct answer.
  3. 133°
  4. 135°

Explanation

'Low' means the compass reads less than the true value, so the error must be added: 137° + 2° = 139° (T). The memory aid 'compass least, error east' applies to magnetic compasses, but for a gyro the direction of the error is stated directly as high or low. Always convert the observed bearing and the error to true before plotting.

Question 31Navigation

Which statement correctly describes the use of a vertical sextant angle to determine distance off a charted object?

  1. The distance in cables equals the angle in minutes divided by the charted height in metres
  2. The distance in metres equals the sextant angle in minutes multiplied by the height in metres
  3. The distance in miles equals the charted height in metres divided by the tangent of the angle in degrees
  4. The distance in miles equals the height in metres multiplied by 1.856 and divided by the angle in minutes Correct answer.

Explanation

For small angles the distance in nautical miles is approximately 1.856 × height in metres ÷ angle in minutes, derived from the one-in-sixty rule. The charted height must be corrected for height of tide and for the observer's height of eye before use. The method is accurate only when the object's top and waterline are both visible and the angle is small.

Question 32Navigation

A vessel on passage experiences a current setting 120° (T) at 3 knots while steering 030° (T) at 12 knots through the water. What is the approximate speed made good?

  1. 9.0 knots
  2. 13.6 knots Correct answer.
  3. 12.0 knots
  4. 15.0 knots

Explanation

The current sets 120° and the course steered is 030°, so the current is almost directly astern (90° off would be a beam current). Resolving by the cosine rule: SMG² = 12² + 3² + 2×12×3×cos 90°, giving about 13.6 knots. Plotting the water track and current vector on the chart gives the same result graphically.

Question 33Navigation

When planning an approach to a harbour at night, which feature of the light list is most important for deciding when to alter course onto the leading line?

  1. The period of the light's flash character
  2. The sectors and any obscured or coloured sectors that define the safe approach Correct answer.
  3. The height of the lantern above mean high water springs
  4. The nominal range of the leading lights in clear weather

Explanation

Sector boundaries tell the navigator precisely when the vessel is within the safe channel and when it has strayed into a danger sector, which may show a different colour or be obscured. The leading line itself then confirms the track once the vessel is established in the sector. Range and flash character help identification but do not define the safe water.

Question 34Navigation

A vessel's echo sounder indicates 15 metres below the keel. If the charted depth at the position is 12 metres and the height of tide is 2 metres, what is the under-keel clearance indicated?

  1. 13 metres
  2. 5 metres
  3. 1 metre Correct answer.
  4. 3 metres

Explanation

The actual depth of water is charted depth plus height of tide, i.e. 12 + 2 = 14 metres. The sounder shows 15 metres, so the reading is being measured from the transducer, which must be about 1 metre above the keel, giving an indicated clearance of 15 − 14 = 1 metre below the keel. The sounder's datum offset must be checked before relying on the figure.

Question 35Navigation

In a passage plan, which element defines the 'abort point' on an estuarine leg?

  1. The last position from which the vessel can safely turn back or hold clear before committing to a restricted passage Correct answer.
  2. The position at which the vessel must reduce speed to comply with a local speed limit
  3. The position where the vessel changes from hand steering to automatic steering
  4. The waypoint at which the pilot boarding ground is located

Explanation

An abort point is the last place where the vessel can still turn round or stop clear of a hazard before entering a constrained stretch such as a narrow channel or a bridge approach. It allows the master to reassess before committing the vessel. It is normally marked with a wheel-over or contingency note in the plan.

Question 36Navigation

Under the IALA system, a vessel approaching a harbour sees a red can buoy to port and a green conical buoy to starboard. Which region is indicated and what do the marks mean?

  1. Region A, where red marks the port side of the channel Correct answer.
  2. Region A, where green marks the port side of the channel
  3. Region B, where red marks the starboard side of the channel
  4. Region B, where green marks the port side of the channel

Explanation

In Region A, red marks are left to port on entry and green marks to starboard; the can and cone shapes match this convention. Region B reverses the colours, with red to starboard and green to port. The shapes (can for port, cone for starboard in Region A) help confirm the region.

Question 37Navigation

A vessel's magnetic compass is being swung. On a heading of 090° (C) the observed deviation is 6° East. What is the deviation on a heading of 270° (C) if the quadrantal error is negligible and the semicircular error follows a sine curve?

  1. 6° West Correct answer.
  2. 0°
  3. 3° East
  4. 6° East

Explanation

Semicircular deviation is caused by permanent magnetism and varies as the sine of the heading, reversing sign on opposite headings. If the deviation is 6° East on 090° (C), it is 6° West on 270° (C). This is why deviation cards are symmetrical about the north-south and east-west axes.

Question 38Navigation

A vessel is proceeding on a course of 000° (T) at 15 knots. At 0800 a wreck is detected by radar bearing 030° (T) at 12 miles. What is the closest point of approach if both courses and speeds are maintained?

  1. 6.0 miles Correct answer.
  2. 15.0 miles
  3. 10.4 miles
  4. 12.0 miles

Explanation

The bearing of 030° means the wreck lies 30° to starboard of the vessel's track, so the perpendicular distance from the track to the wreck is 12 × sin 30° = 6.0 miles. This is the CPA if the vessel holds her course and the wreck is stationary. The time to CPA would be the along-track distance divided by speed.

Question 39Navigation

A great-circle track between two ocean ports has a vertex at 55° N. Which statement about the track is correct?

  1. The final course is always numerically equal to the initial course
  2. The track reaches its highest latitude at the vertex and the course there is 090° or 270° Correct answer.
  3. The initial course always exceeds 090° for an eastbound passage
  4. The track crosses the equator at the vertex

Explanation

The vertex is the point of highest latitude on a great circle, where the track runs due east or due west, so the course is 090° or 270°. The initial and final courses differ unless the track is symmetrical about the equator. Knowing the vertex latitude allows the navigator to check that the route stays clear of ice or land.

Question 40Navigation

What is the primary purpose of the echo sounder's 'shallow water alarm' during a coastal passage?

  1. To warn the navigator when the depth below keel falls below a preset safety margin Correct answer.
  2. To record the vessel's speed through the water by Doppler shift
  3. To detect fish shoals for the fishing master
  4. To measure the height of tide at the vessel's position

Explanation

The shallow water alarm sounds when the indicated depth falls below a limit set by the navigator, giving warning before the under-keel clearance becomes unsafe. The limit should be set from the planned minimum clearance plus a margin for squat and swell. It is a safety backup and does not replace the passage plan.

Question 41Cargo Handling and Stowage

Under the IMDG Code, which document is mandatory for a consignment of dangerous goods before loading onto a vessel?

  1. A certificate of classification issued by the flag administration
  2. A bill of lading endorsed by the port authority
  3. A dangerous goods declaration completed and signed by the shipper Correct answer.
  4. A cargo securing manual extract signed by the stevedores

Explanation

The IMDG Code requires the shipper to provide a signed dangerous goods transport document (multimodal dangerous goods form) containing the UN number, proper shipping name, class, packing group and emergency information. Without it the cargo must not be loaded. Port authorities and classification societies do not issue this declaration.

Question 42Cargo Handling and Stowage

A container is described as having a tare of 3,800 kg and a maximum gross of 30,480 kg. What is its maximum permitted payload?

  1. 30,480 kg
  2. 34,280 kg
  3. 3,800 kg
  4. 26,680 kg Correct answer.

Explanation

Payload is the maximum gross mass minus the tare mass, i.e. 30,480 − 3,800 = 26,680 kg. This figure is the maximum cargo mass the container may carry. The other values either repeat the gross or tare mass or add them together.

Question 43Cargo Handling and Stowage

In a break-bulk stow, which practice best protects the cargo against crushing in a lower tier?

  1. Spreading the load with dunnage and limiting tier height to the compression strength of the package Correct answer.
  2. Lashing all packages directly to the tank top plating
  3. Stowing the heaviest packages at the top of the stack
  4. Leaving the lower tier unsecured so it can settle

Explanation

Compression strength of the packaging governs how many tiers may be stacked; dunnage spreads the load and prevents point loading. Exceeding the package's compression strength causes crushing and collapse of the stow. Lashing to the tank top and leaving tiers loose do not address the vertical load.

Question 44Cargo Handling and Stowage

Which statement correctly describes the purpose of a cargo hold bilge sounding during a voyage?

  1. To measure the density of the cargo in the hold
  2. To detect ingress of water and confirm that the hold drainage system is clear Correct answer.
  3. To verify the hold's ventilation rate
  4. To check the trim of the vessel

Explanation

Bilge soundings show whether water is accumulating in a hold, which may indicate leakage through hatches, shell plating or piping, and confirm that bilges are not blocked. They are a core part of the routine hold inspection. They do not measure cargo density, ventilation or trim.

Question 45Cargo Handling and Stowage

What is the main reason for ventilating a hold carrying a hygroscopic cargo such as bagged cocoa?

  1. To prevent condensation on the cargo by controlling the dew-point relationship between cargo and outside air Correct answer.
  2. To keep the cargo temperature above the dew point of the outside air
  3. To remove odours produced by the packaging material
  4. To reduce the moisture content of the cargo to zero

Explanation

Hygroscopic cargoes release moisture and can cause cargo sweat when the ship's structure is colder than the dew point of the hold air. Ventilation is controlled by comparing the dew points of the hold air and the outside air so that condensation on the cargo is avoided. Ventilation cannot reduce cargo moisture to zero, nor is warming the cargo the objective.

Question 46Cargo Handling and Stowage

A vessel has a summer deadweight of 12,000 t and is loading in a tropical zone. Which statement about the permitted load line is correct?

  1. The fresh water allowance must always be added in a tropical zone
  2. The tropical load line may be used, allowing the vessel to load deeper than the summer mark Correct answer.
  3. The summer load line must always be used regardless of zone and season
  4. The winter load line applies because the cargo is dense

Explanation

The tropical load line sits above the summer load line, so in a tropical zone the vessel may load to the tropical mark, giving greater deadweight. The applicable zone and season are determined from the load line chart. The winter mark is more restrictive, and fresh water allowance applies only in fresh water.

Question 47Cargo Handling and Stowage

Which of the following is the primary purpose of the Cargo Securing Manual required under SOLAS?

  1. To provide ship-specific guidance on securing arrangements approved by the administration Correct answer.
  2. To record the commercial terms of each voyage charter
  3. To document the ship's ballast water management plan
  4. To list the qualifications of the deck officers

Explanation

SOLAS Chapter VI requires a Cargo Securing Manual approved by the administration, giving ship-specific arrangements for securing cargo including lashing points and maximum securing loads. It is a technical document, not a commercial or personnel record. Ballast water management is covered by a separate plan.

Question 48Cargo Handling and Stowage

In a bulk carrier, why is it important to avoid excessive cargo density in a single hold?

  1. Because dense cargo increases the ship's freeboard
  2. Because the tank top and inner bottom are designed for a maximum permissible load per unit area Correct answer.
  3. Because dense cargo always liquefies during the voyage
  4. Because dense cargo cannot be trimmed with standard equipment

Explanation

The inner bottom and tank top structure are designed for a maximum permissible load in tonnes per square metre, stated in the loading manual. Exceeding it can cause structural damage to double-bottom plating and framing. Trimming, liquefaction and freeboard are separate considerations.

Question 49Cargo Handling and Stowage

Which of the following best describes the term 'angle of repose' in relation to a bulk cargo?

  1. The maximum angle a stockpile of the material can maintain without sliding Correct answer.
  2. The angle at which a crane jib can safely lift the cargo
  3. The angle of the ship's list caused by cargo shift
  4. The angle between the ship's centreline and the cargo surface after trimming

Explanation

The angle of repose is the steepest angle a pile of granular material can hold without sliding, and it determines how the cargo will trim and whether it can shift. It is a property of the material, not of the ship's geometry or lifting gear. It is measured from the horizontal.

Question 50Cargo Handling and Stowage

A cargo of iron ore fines has a moisture content above its transportable moisture limit. What is the correct action?

  1. Load the cargo after increasing ventilation in the hold
  2. Load the cargo only after trimming it flat
  3. Do not load the cargo until the moisture content is reduced below the TML Correct answer.
  4. Load the cargo with a reduced deadweight to compensate

Explanation

Iron ore fines can liquefy if the moisture content exceeds the transportable moisture limit, causing the cargo to shift and potentially capsize the vessel. The cargo must not be loaded until the moisture content is proven below the TML. Ventilation, trimming and reduced deadweight do not remove the liquefaction risk.