Simplify: 12 + 6 ÷ 3 × 2 − 4
- 12 Correct answer.
- 16
- 8
- 10
Explanation
BODMAS requires division and multiplication to be done before addition and subtraction, working left to right. So 6 ÷ 3 = 2, then 2 × 2 = 4, giving 12 + 4 − 4 = 12.
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BODMAS requires division and multiplication to be done before addition and subtraction, working left to right. So 6 ÷ 3 = 2, then 2 × 2 = 4, giving 12 + 4 − 4 = 12.
Both numbers factor as 24 = 2³ × 3 and 36 = 2² × 3², so the HCF is 2² × 3 = 12. It is also the greatest number that divides both 24 and 36 exactly.
A percentage of a quantity is found by multiplying the quantity by the rate over 100. Here 400 × 15/100 = 400 × 0.15 = 60.
The average of a set of numbers is their sum divided by how many numbers there are. The sum is 2 + 4 + 6 + 8 + 10 = 30 and there are 5 numbers, so the average is 30 ÷ 5 = 6.
Simple interest is calculated as SI = (P × R × T)/100. Substituting gives (5000 × 10 × 2)/100 = 1000.
The square root is the number whose square is the given number. Since 42 × 42 = 1764, the square root is 42.
The total number of parts is 3 + 5 = 8, so one part equals 240 ÷ 8 = 30. The smaller share is 3 parts, that is 3 × 30 = 90.
Convert each fraction to a decimal to compare: 3/5 = 0.6, 5/8 = 0.625, 7/12 ≈ 0.583 and 2/3 ≈ 0.667. The largest decimal value is 0.667, so 2/3 is the greatest fraction.
Profit = 552 − 480 = 72, and profit per cent is always taken on the cost price. So profit % = (72/480) × 100 = 15%.
In one day A does 1/12 and B does 1/18 of the work, so together they do 1/12 + 1/18 = 5/36. The time taken is the reciprocal, 36/5 = 7 1/5 days.
Speed is distance divided by time, so the car travels 240 ÷ 4 = 60 km each hour. In 7 hours it covers 60 × 7 = 420 km.
Amount = 8000 × (1 + 10/100)² = 8000 × 1.21 = 9680. The compound interest is the amount minus the principal, that is 9680 − 8000 = 1680.
Let the son's age be x, so the father is 3x. After 12 years, 3x + 12 = 2(x + 12), which gives 3x + 12 = 2x + 24, hence x = 12.
Downstream the stream helps the boat, so the effective speed is 10 + 2 = 12 km/h. Time = distance ÷ speed = 24 ÷ 12 = 2 hours.
Collect the x terms on one side and the numbers on the other: 5x − 3x = 9 + 7, so 2x = 16. Dividing both sides by 2 gives x = 8.
Perimeter = 2(length + breadth), so 60 = 2(18 + b), giving 18 + b = 30 and b = 12 cm. Area = length × breadth = 18 × 12 = 216 cm².
Write each number in prime factor form: 12 = 2² × 3, 15 = 3 × 5 and 20 = 2² × 5. Taking the highest power of each prime gives 2² × 3 × 5 = 60.
Percentage increase is the increase divided by the original value, multiplied by 100. Here the increase is 300 − 250 = 50, so the increase is (50/250) × 100 = 20%.
In one hour the pipes fill 1/6 + 1/4 = 5/12 of the tank. The time to fill the tank is the reciprocal of this rate, 12/5 = 2.4 hours.
Initially milk = 3/4 × 40 = 30 litres and water = 10 litres. Adding water changes only the water, so we need 30 : (10 + w) = 3 : 2, giving 60 = 30 + 3w and w = 10 litres.
When two numbers are in the ratio a : b and their HCF is h, the numbers are ah and bh, here 30 and 42. Since HCF × LCM = product of the numbers, LCM = (30 × 42)/6 = 210.
After a 20% discount the price is 80% of the marked price, and after a further 10% discount it is 90% of that, i.e. 0.8 × 0.9 = 0.72 of the marked price. The equivalent single discount is therefore 100% − 72% = 28%.
In opposite directions the relative speed is 40 + 32 = 72 km/h = 72 × 5/18 = 20 m/s. The distance to be covered is the combined length 120 + 180 = 300 m, so the time is 300 ÷ 20 = 15 seconds.
Let the cost price be 100, so the marked price is 140. After a 25% discount the selling price is 140 × 0.75 = 105, which is 5 more than the cost price. Hence there is a profit of 5%.
The volume of a cylinder is πr²h. Substituting, volume = (22/7) × 7 × 7 × 10 = 22 × 7 × 10 = 1540 cm³.
Under BODMAS, division and multiplication are carried out before addition and subtraction: 18 ÷ 3 = 6 and 4 × 5 = 20, so the expression becomes 16 + 20 − 6 = 30.
Writing each number in prime factor form: 36 = 2² × 3², 60 = 2² × 3 × 5 and 84 = 2² × 3 × 7. The highest common factor is therefore 2² × 3 = 12.
Since 15 × 15 × 15 = 3375, the cube root of 3375 equals 15.
The first ten natural numbers are 1 to 10, whose sum is (10 × 11)/2 = 55. The average is 55 ÷ 10 = 5.5.
Simple interest = (P × R × T)/100 = (4500 × 8 × 3)/100 = ₹1,080.
A number is divisible by 9 when the sum of its digits is a multiple of 9. For 4527 the digit sum is 4 + 5 + 2 + 7 = 18, which is divisible by 9.
Multiplying both sides of x/4 = 7 by 4 gives x = 28. Therefore x + 5 = 28 + 5 = 33.
The differences between consecutive terms are 4, 6, 8 and 10. The next difference should be 12, so the next term is 30 + 12 = 42.
Taking the number as 100, a 20% increase gives 120, and a 20% decrease on 120 gives 96. Since 96 is 4 less than 100, the net result is a 4% decrease.
Selling price = cost price × (100 − loss%)/100, so 720 = CP × 90/100, giving CP = 720 × 100/90 = ₹800.
The total number of parts is 2 + 3 + 5 = 10, so one part is ₹1,200 ÷ 10 = ₹120. B's share is 3 parts, that is 3 × 120 = ₹360.
The work requires 15 × 20 = 300 man-days. To finish it in 12 days the number of men needed is 300 ÷ 12 = 25.
The sum of the five numbers is 5 × 27 = 135. Removing 35 leaves 100, and the average of the remaining four numbers is 100 ÷ 4 = 25.
Speed = distance ÷ time = 150/9 m/s. Converting to km/h by multiplying by 18/5 gives (150/9) × (18/5) = 60 km/h.
The mixture contains 40 litres of milk and 20 litres of water. For a 1 : 1 ratio the water must also be 40 litres, so 40 − 20 = 20 litres of water must be added.
Let the daughter's age be x years; then the mother's age is x + 24. So x + (x + 24) = 48, giving 2x = 24 and x = 12 years.
Area of a triangle = ½ × base × height = ½ × 18 × 15 = 135 cm².
Profit shares are proportional to capital × time. For A, 5,000 × 12 = 60,000; for B, 8,000 × 6 = 48,000. The ratio is 60,000 : 48,000 = 5 : 4.
The bells ring together again after the LCM of 6, 8 and 10 minutes, which is 120 minutes = 2 hours. Adding 2 hours to 8 a.m. gives 10 a.m.
First find 2/5 of 200, which is 80. Then take 3/4 of 80, which is 60.
SI = (10,000 × 10 × 2)/100 = ₹2,000, while CI = 10,000 × (1.1² − 1) = ₹2,100. The difference is ₹100, which for two years equals P(r/100)².
The net filling rate per hour is 1/12 + 1/15 − 1/20 = (5 + 4 − 3)/60 = 6/60 = 1/10. The tank therefore fills in 10 hours.
The car takes 2 hours for the first 60 km and 1 hour for the next 60 km, so total time is 3 hours for 120 km. Average speed = 120 ÷ 3 = 40 km/h; the simple mean of the two speeds is not valid because the times differ.
Volume of a sphere = (4/3)πr³ = (4/3) × π × 27 = 36π cm³.
Becoming 4 times in 10 years means the interest equals 3 times the principal in 10 years, so one principal's worth of interest takes 10/3 years. To become 7 times, the interest must be 6 times the principal, taking 6 × 10/3 = 20 years.