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Question 1DC electrical theory, circuits, and Ohm's law
A 12 V battery is connected across a 6 Ω resistor. What current flows through the resistor?
- 72 A
- 2 A Correct answer.
- 18 A
- 0.5 A
Explanation
Ohm's law states that current equals voltage divided by resistance (I = V ÷ R). Dividing 12 V by 6 Ω gives 2 A. The resistor limits the current from the source to that value.
Question 2DC electrical theory, circuits, and Ohm's law
Which statement describes current in a series circuit?
- It is zero in the largest resistor.
- It is the sum of all branch currents.
- It is equal at every point. Correct answer.
- It divides in proportion to resistance.
Explanation
A series circuit offers only one path for electrons, so the same current passes through every component. It is the voltage, not the current, that divides among series elements.
Question 3DC electrical theory, circuits, and Ohm's law
How does voltage behave across parallel branches connected to a single source?
- It equals the source only in the first branch.
- It is the sum of all the branch drops.
- It is proportional to each branch's resistance.
- It is equal across all branches. Correct answer.
Explanation
Every branch connected directly across the same two nodes sees the same potential difference, so each parallel branch has the source voltage across it. Current, not voltage, divides among the branches.
Question 4DC electrical theory, circuits, and Ohm's law
A 12 V load draws 3 A. How much power does it consume?
- 36 W Correct answer.
- 0.25 W
- 15 W
- 4 W
Explanation
DC power equals voltage multiplied by current (P = V × I). Multiplying 12 V by 3 A yields 36 W.
Question 5DC electrical theory, circuits, and Ohm's law
Before using an ohmmeter on a circuit, a technician should ensure that the circuit is:
- de-energized and isolated Correct answer.
- energized at low voltage
- connected to a charger
- fitted with a larger fuse
Explanation
An ohmmeter applies its own small voltage to measure resistance, so any external source will corrupt the reading and may damage the meter. The circuit must be switched off and disconnected from all sources before testing.
Question 6DC electrical theory, circuits, and Ohm's law
A conductor is doubled in length while its gauge and temperature stay the same. Its resistance will:
- double Correct answer.
- remain unchanged
- increase fourfold
- halve
Explanation
Resistance is directly proportional to length, so doubling the length at the same gauge doubles the resistance. Gauge and temperature are held constant, so they contribute no change.
Question 7DC electrical theory, circuits, and Ohm's law
Which unit expresses electrical power?
- watt Correct answer.
- volt
- ohm
- coulomb
Explanation
The watt is the unit of power, equal to one joule per second. In DC circuits, power in watts equals volts multiplied by amps.
Question 8DC electrical theory, circuits, and Ohm's law
An ammeter is connected:
- across the source terminals
- in parallel with the load being measured
- in series with the load Correct answer.
- in parallel with a shunt resistor
Explanation
An ammeter must carry the current being measured, so it is wired in series with the load. Its own resistance is kept very low so it does not disturb the circuit.
Question 9DC electrical theory, circuits, and Ohm's law
A 24 V source drives 0.5 A through a resistor. What is the resistance?
- 0.02 Ω
- 12 Ω
- 48 Ω Correct answer.
- 24.5 Ω
Explanation
Rearranging Ohm's law gives R = V ÷ I. Dividing 24 V by 0.5 A yields 48 Ω.
Question 10DC electrical theory, circuits, and Ohm's law
Resistors of 10 Ω, 22 Ω, and 47 Ω are connected in series. What is the total resistance?
- 103 Ω
- 79 Ω Correct answer.
- 35 Ω
- 26 Ω
Explanation
In a series circuit, resistances add directly, so 10 + 22 + 47 = 79 Ω. The same current flows through all three, and the source voltage divides across them in proportion to their resistance.
Question 11DC electrical theory, circuits, and Ohm's law
A 6 Ω and a 3 Ω resistor are connected in parallel. What is the equivalent resistance?
- 2 Ω Correct answer.
- 9 Ω
- 4.5 Ω
- 18 Ω
Explanation
For two resistors in parallel, R = (R1 × R2) ÷ (R1 + R2). Here (6 × 3) ÷ (6 + 3) = 18 ÷ 9 = 2 Ω. The equivalent must be smaller than the smallest branch, which 2 Ω satisfies.
Question 12DC electrical theory, circuits, and Ohm's law
A 24 V source is applied across an 8 Ω resistor. What power is dissipated?
- 192 W
- 3 W
- 72 W Correct answer.
- 0.33 W
Explanation
Power can be found with P = V² ÷ R. Here 24² = 576, and 576 ÷ 8 = 72 W. The same result comes from finding the current (3 A) and multiplying it by voltage.
Question 13DC electrical theory, circuits, and Ohm's law
A 10 A load current flows through conductors whose total resistance is 0.05 Ω. What is the voltage drop in the conductors?
- 0.5 V Correct answer.
- 0.05 V
- 5 V
- 2 V
Explanation
Voltage drop in conductors follows Ohm's law: V = I × R. Multiplying 10 A by 0.05 Ω gives 0.5 V.
Question 14DC electrical theory, circuits, and Ohm's law
Two currents, 5 A and 3 A, enter a junction. One current of 6 A leaves the junction. What current must leave through the other conductor?
- 14 A
- 8 A
- 2 A Correct answer.
- 4 A
Explanation
Kirchhoff's current law requires current entering a junction to equal current leaving it. The total entering is 5 + 3 = 8 A, so the second outgoing conductor must carry 8 − 6 = 2 A.
Question 15DC electrical theory, circuits, and Ohm's law
A 12 V source feeds a 4 kΩ and an 8 kΩ resistor in series. What voltage appears across the 8 kΩ resistor?
- 8 V Correct answer.
- 12 V
- 4 V
- 6 V
Explanation
In a series circuit the same current flows through both resistors, so voltage divides in proportion to resistance. The 8 kΩ resistor is two-thirds of the 12 kΩ total, so it drops two-thirds of 12 V, or 8 V.
Question 16DC electrical theory, circuits, and Ohm's law
Four 6 V batteries are connected in series. What is the total bank voltage?
- 12 V
- 24 V Correct answer.
- 6 V
- 1.5 V
Explanation
Series connections add voltage, while capacity in amp-hours stays the same. Four 6 V batteries in series produce 4 × 6 = 24 V.
Question 17DC electrical theory, circuits, and Ohm's law
A 12 V load draws 10 A for 5 hours. How much energy is consumed?
- 50 Wh
- 60 Wh
- 600 Wh Correct answer.
- 1200 Wh
Explanation
Energy in watt-hours equals volts times amps times hours. At 12 V and 10 A the load draws 120 W, and 120 W for 5 hours is 600 Wh.
Question 18DC electrical theory, circuits, and Ohm's law
A conductor is replaced by one with a larger cross-sectional area (smaller gauge number) of the same length and material. Its resistance will:
- decrease Correct answer.
- increase
- double
- stay the same
Explanation
Resistance varies inversely with cross-sectional area. A larger cross-section provides more paths for current, so resistance decreases for the same length and material.
Question 19DC electrical theory, circuits, and Ohm's law
A 4 A current flows through a 3 Ω resistor. What power is dissipated?
- 7 W
- 12 W
- 192 W
- 48 W Correct answer.
Explanation
Power dissipated by a resistor can be calculated as P = I² × R. Here 4² = 16 and 16 × 3 = 48 W. Checking with voltage: 4 A × 3 Ω = 12 V, and 12 V × 4 A = 48 W.
Question 20DC electrical theory, circuits, and Ohm's law
A total current of 6 A splits between a 3 Ω and a 6 Ω resistor in parallel. What current flows through the 3 Ω resistor?
- 4 A Correct answer.
- 3 A
- 6 A
- 2 A
Explanation
Parallel branches share the same voltage, which here is 6 A × 2 Ω = 12 V. The current through the 3 Ω branch is therefore 12 V ÷ 3 Ω = 4 A, leaving 2 A for the 6 Ω branch.
Question 21DC electrical theory, circuits, and Ohm's law
A 12 V source feeds two 6 Ω resistors in parallel, and that combination is in series with a 3 Ω resistor. What current flows through each 6 Ω resistor?
- 1 A Correct answer.
- 4 A
- 2 A
- 0.5 A
Explanation
The two 6 Ω resistors in parallel give 3 Ω, which adds to the series 3 Ω for a 6 Ω total. Source current is 12 V ÷ 6 Ω = 2 A, and that 2 A divides equally between the two equal parallel branches, giving 1 A in each.
Question 22DC electrical theory, circuits, and Ohm's law
A 12 Ω resistor and an unknown resistor are connected in parallel, giving an equivalent resistance of 4 Ω. What is the unknown resistance?
- 3 Ω
- 8 Ω
- 4 Ω
- 6 Ω Correct answer.
Explanation
For parallel resistors, 1/Rtotal = 1/R1 + 1/R2. With 4 Ω equivalent and 12 Ω known, 1/R2 = 1/4 − 1/12 = 2/12, so R2 = 6 Ω. The equivalent must be smaller than the smallest branch, which fits.
Question 23DC electrical theory, circuits, and Ohm's law
A 24 V circuit carries 15 A through conductors with a total resistance of 0.04 Ω. What percentage of the source voltage is lost in the conductors?
- 4.0%
- 0.6%
- 2.5% Correct answer.
- 1.5%
Explanation
Conductor drop is I × R = 15 A × 0.04 Ω = 0.6 V. As a fraction of 24 V, that is 0.6 ÷ 24 = 0.025, or 2.5 percent.
Question 24DC electrical theory, circuits, and Ohm's law
A battery reads 12.8 V at rest and 11.8 V while delivering 40 A. What is its internal resistance?
- 0.40 Ω
- 0.25 Ω
- 0.025 Ω Correct answer.
- 0.32 Ω
Explanation
Internal resistance causes the terminal voltage to sag by I × Rint under load. The sag is 12.8 − 11.8 = 1.0 V at 40 A, so Rint = 1.0 ÷ 40 = 0.025 Ω.
Question 25DC electrical theory, circuits, and Ohm's law
Two 12 V, 100 Ah batteries are connected in parallel to supply a 20 A load. Approximately how long can they run, ignoring Peukert effect and efficiency losses?
- 40 h
- 5 h
- 10 h Correct answer.
- 20 h
Explanation
Parallel batteries add capacity while voltage stays at 12 V, so the bank provides about 200 Ah. At a 20 A draw, runtime is roughly 200 ÷ 20 = 10 hours. Real runtime is usually shorter because of Peukert effect and conversion losses.
Question 26DC electrical theory, circuits, and Ohm's law
In a resistive circuit held at constant temperature, which statement describes how current behaves according to Ohm's law?
- Current falls as voltage rises and rises as resistance rises.
- Current rises as voltage rises and rises as resistance rises.
- Current stays constant when voltage changes but resistance is fixed.
- Current rises as voltage rises and falls as resistance rises. Correct answer.
Explanation
Ohm's law is written I = E / R, so current is directly proportional to the applied voltage and inversely proportional to resistance. Raising voltage at fixed resistance pushes more current, while raising resistance at fixed voltage chokes it back. The relationship holds for a resistive circuit whose temperature is essentially constant.
Question 27DC electrical theory, circuits, and Ohm's law
In a single closed series loop containing a source and several loads, how does the sum of the load voltage drops compare with the source voltage?
- It is always smaller than the source voltage.
- It is always larger than the source voltage.
- It equals the source voltage. Correct answer.
- It equals the source voltage only when all the loads have equal resistance.
Explanation
Kirchhoff's voltage law states that around any closed loop the algebraic sum of all voltages is zero. In practice that means the voltage drops across the loads must add up exactly to the voltage supplied by the source. The rule holds regardless of the number or resistance values of the loads.
Question 28DC electrical theory, circuits, and Ohm's law
A copper conductor is operating at a higher temperature than when it was measured cold. What happens to its resistance?
- It increases as temperature rises. Correct answer.
- It remains exactly the same at any temperature.
- It drops to zero at elevated temperature.
- It falls steadily as temperature rises.
Explanation
Copper has a positive temperature coefficient, meaning its resistance increases as it warms. This is why conductor ampacity tables are based on a specific assumed operating temperature. The effect is modest over normal working ranges but is real and predictable.
Question 29DC electrical theory, circuits, and Ohm's law
A 12 V deck light is rated at 24 W. What current does it draw when operated at its rated voltage?
- 2 A Correct answer.
- 288 A
- 12 A
- 0.5 A
Explanation
Electrical power in a DC circuit equals voltage multiplied by current, P = E x I. Rearranging gives I = P / E = 24 W / 12 V = 2 A. This current is what the branch conductor and overcurrent device must be sized to carry.
Question 30DC electrical theory, circuits, and Ohm's law
Two 6 ohm resistors are connected in parallel. How does the equivalent resistance compare with the resistance of either resistor alone?
- It is exactly equal to either single resistor.
- It is higher than either single resistor.
- It is exactly twice either single resistor.
- It is lower than either single resistor. Correct answer.
Explanation
Parallel paths add conductance, so 1/Rt = 1/R1 + 1/R2, and the combined resistance is always lower than the smallest branch. Here the equivalent is 3 ohms, half of one resistor. Adding any further parallel branch lowers the total again.
Question 31DC electrical theory, circuits, and Ohm's law
A 10 ohm, a 22 ohm, and a 47 ohm resistor are connected in series across a battery. Which resistor dissipates the greatest power?
- All three dissipate equal power.
- The 10 ohm resistor.
- The 47 ohm resistor. Correct answer.
- The 22 ohm resistor.
Explanation
In a series circuit the same current flows through every element, so power dissipated is P = I squared x R. With current held constant, the largest resistance develops the greatest voltage drop and the greatest heating. Therefore the 47 ohm unit runs hottest.
Question 32DC electrical theory, circuits, and Ohm's law
A 12 V load draws a steady 3 A for 2 minutes. How much charge passes through the circuit in that time?
- 360 C Correct answer.
- 240 C
- 6 C
- 1080 C
Explanation
Charge in coulombs equals current in amperes multiplied by time in seconds, Q = I x t. Converting 2 minutes to 120 seconds gives Q = 3 A x 120 s = 360 C. Failing to convert minutes to seconds is the usual source of error.
Question 33DC electrical theory, circuits, and Ohm's law
A source has a fixed internal resistance of 0.4 ohm. What load resistance draws the maximum power from that source?
- Zero resistance, which is a direct short.
- 0.4 ohm. Correct answer.
- 0.1 ohm.
- Infinite resistance, which is an open circuit.
Explanation
The maximum power transfer theorem states that a source delivers its greatest power to a load whose resistance equals the source's internal resistance. Here that means a 0.4 ohm load. At that point the terminal voltage is half the source EMF.
Question 34DC electrical theory, circuits, and Ohm's law
A 12 V source supplies a 30 ohm resistor and a 60 ohm resistor connected in parallel. What total power is delivered by the source?
- 0.6 W
- 7.2 W Correct answer.
- 4.8 W
- 2.4 W
Explanation
Each branch sees the full 12 V, so branch power is E squared divided by R. The 30 ohm branch takes 144 / 30 = 4.8 W and the 60 ohm branch takes 144 / 60 = 2.4 W, giving 7.2 W total. The same answer follows from the 20 ohm equivalent resistance: 144 / 20 = 7.2 W.
Question 35Batteries, battery charging systems, and battery installation
Two 12-volt, 100 amp-hour batteries are connected in series. What are the resulting bank voltage and capacity?
- 24 volts and 200 amp-hours
- 12 volts and 200 amp-hours
- 12 volts and 100 amp-hours
- 24 volts and 100 amp-hours Correct answer.
Explanation
A series connection adds the voltages of the batteries while the amp-hour capacity stays the same, because the same current flows through both. Two 12-volt, 100 Ah batteries in series therefore give 24 volts and 100 Ah.
Question 36Batteries, battery charging systems, and battery installation
Two 12-volt, 100 amp-hour batteries are connected in parallel. What are the resulting bank voltage and capacity?
- 24 volts and 200 amp-hours
- 12 volts and 100 amp-hours
- 24 volts and 100 amp-hours
- 12 volts and 200 amp-hours Correct answer.
Explanation
In parallel, the positive terminals are joined and the negative terminals are joined, so voltage stays at 12 volts while the capacities add. The bank becomes 12 volts and 200 Ah.
Question 37Batteries, battery charging systems, and battery installation
Which battery chemistry may be equalized with a controlled overcharge?
- Flooded lead-acid Correct answer.
- Lithium iron phosphate
- Gel
- AGM
Explanation
Equalization is a deliberate overcharge that mixes electrolyte and helps remove sulfation, and it is suitable only for flooded lead-acid batteries. Sealed batteries such as gel and AGM can be damaged by the higher voltage and gas generation.
Question 38Batteries, battery charging systems, and battery installation
How must battery terminals be treated in a proper marine installation?
- Insulated against short circuits Correct answer.
- Labeled with the battery type
- Coated with anti-corrosion spray
- Left exposed for cooling
Explanation
ABYC requires battery terminals to be protected so that a dropped tool or other metal object cannot bridge them and cause a short, fire, or explosion. Insulated covers or boots provide this protection.
Question 39Batteries, battery charging systems, and battery installation
What is the basic requirement for securing a battery in a boat?
- To prevent movement and shifting Correct answer.
- With removable straps left unfastened
- Only on vessels over 26 feet
- Only when installed in the engine room
Explanation
Batteries must be fastened down so wave impact, heel, or collision cannot move them or spill electrolyte. The hold-down must be installed and tight, not merely present.
Question 40Batteries, battery charging systems, and battery installation
What is the normal sequence of stages in a three-stage battery charger?
- Float, bulk, absorption
- Bulk, absorption, float Correct answer.
- Bulk, float, absorption
- Absorption, bulk, float
Explanation
The charger first delivers bulk current to raise voltage, then holds absorption voltage to finish the charge, and finally drops to float to maintain the battery. This sequence shortens charging time and reduces overcharging.
Question 41Batteries, battery charging systems, and battery installation
As a general rule, how close must overcurrent protection be to the battery source on a DC conductor?
- 40 inches
- 7 inches Correct answer.
- 18 inches
- 24 inches
Explanation
ABYC E-11 requires overcurrent protection within 7 inches of the source of power on the ungrounded conductor. The distance may be extended to 40 inches only when the conductor is enclosed in a sheath or conduit.
Question 42Batteries, battery charging systems, and battery installation
What does a battery's cold-cranking amp rating describe?
- Reserve capacity in minutes at 80°F with a 25-amp load
- Amp-hour capacity delivered over a 20-hour discharge
- Cranking current measured at 32°F for 60 seconds
- Cold-cranking current at 0°F for 30 seconds Correct answer.
Explanation
CCA is the current a battery can deliver at 0°F for 30 seconds while staying above a specified voltage. It indicates cold-weather starting ability rather than deep-cycle capacity.
Question 43Batteries, battery charging systems, and battery installation
What maximum voltage drop does ABYC specify for critical DC circuits such as navigation equipment?
- 3 percent Correct answer.
- 5 percent
- 10 percent
- 1 percent
Explanation
ABYC limits voltage drop to 3 percent on critical circuits and 10 percent on non-critical circuits. Excessive drop can cause electronics to malfunction and motors to overheat.
Question 44Batteries, battery charging systems, and battery installation
What can happen if the battery selector switch is turned to OFF while the engine is running?
- The charging system shuts down safely without damage
- A load dump can damage the alternator diodes Correct answer.
- The battery absorbs the spike without damage
- The engine stops immediately with no side effects
Explanation
Opening the battery circuit while the alternator is charging leaves the alternator without a load, producing a voltage spike. This load dump can destroy the alternator diodes and the regulator.
Question 45Batteries, battery charging systems, and battery installation
What is the main disadvantage of a diode battery isolator?
- No measurable voltage drop under load
- Works only with lithium batteries
- A 0.7-volt drop that can undercharge Correct answer.
- Boosts charging voltage by 0.7 volt
Explanation
A diode isolator loses about 0.7 volt across its semiconductors, so the battery receives less charging voltage and may never reach full charge. Modern combiners avoid this loss.
Question 46Batteries, battery charging systems, and battery installation
How should charging voltage change as battery temperature drops?
- Lower voltage
- Higher voltage Correct answer.
- Charging must stop
- The same voltage
Explanation
A cold battery has higher internal resistance and needs a higher charging voltage to accept current. A temperature sensor allows the charger or regulator to compensate.
Question 47Batteries, battery charging systems, and battery installation
A battery charger is installed in a compartment containing a gasoline engine. What feature is required?
- Explosion proof
- Ignition protected Correct answer.
- Double insulated
- Water-cooled
Explanation
Gasoline vapors can collect in an engine compartment, and a spark from charger contacts could ignite them. ABYC A-31 requires chargers installed in such spaces to be ignition protected.
Question 48Batteries, battery charging systems, and battery installation
What current must the main battery disconnect switch be rated to carry continuously?
- Charger output only
- The fuse rating of the protected branch circuit
- Peak cranking current only
- Continuous alternator and load current Correct answer.
Explanation
The main switch must carry the full continuous current of the alternator and all DC loads without overheating. Engine cranking current is normally handled by a separate starting circuit or a suitably rated switch.
Question 49Batteries, battery charging systems, and battery installation
Compared with flooded lead-acid batteries, gel batteries generally require what charging setpoint?
- A higher absorption voltage
- Monthly equalization
- A lower absorption voltage Correct answer.
- No float stage
Explanation
Gel electrolyte is less tolerant of high voltage, so gel batteries use lower absorption and float setpoints than flooded batteries. Equalization is not appropriate for gel batteries.
Question 50Batteries, battery charging systems, and battery installation
Overcurrent protection may be located up to 40 inches from the battery when the conductor is in what condition?
- Enclosed in a sheath or conduit Correct answer.
- Sized larger than 4/0
- Connected to a fused switch
- Routed through the engine room
Explanation
The 7-inch rule may be extended to 40 inches when the conductor is protected by a sheath or conduit, which reduces the chance of a short before the fuse. The fuse must still protect the conductor.