Registered Civil Engineer (Port & Waterway) study materials
Registered Civil Engineer (Port & Waterway) study resources

Registered Civil Engineer (Port & Waterway): Engineering Economics and Professional Practice

Registered Civil Engineer (Port & Waterway) · Work through your exam, one topic at a time.

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Engineering Economics and Professional Practice

Economics and practice questions test whether you can discount correctly, compare alternatives on a consistent basis, and recognise the professional and contractual obligations attached to a design.

Project appraisal

  • NPV = Σ (Ct − Co)/(1+r)^t, including capital, operating, maintenance and residual value; keep the discount rate consistent with the cash flows (real with real, nominal with nominal, pre- or post-tax throughout).
  • IRR is the rate at which NPV = 0; it misleads when comparing projects of different scale or with non-conventional cash flows, where NPV ranking is safer.
  • Benefit–cost ratio = PV of benefits / PV of costs; between mutually exclusive options use the incremental BCR, not the ratio of each option alone.
  • Life-cycle cost includes maintenance dredging, fender and pavement renewal, and downtime cost - not just capital cost.

Port economics

  • Berth provision cost and vessel waiting cost trade off; the optimal number of berths minimises their sum, which is why occupancy targets sit well below 100%.
  • Economic analysis uses shadow prices and national benefits; financial analysis uses actual tariffs and cash flow. Do not mix the two.

Professional practice

  • Duty of care runs to the client and to third parties; design responsibility does not transfer with construction inspection unless the contract says so.
  • Contract forms (FIDIC, NEC) allocate ground-condition and weather risk explicitly; the designer must know who carries the risk created by the specification.
  • Confidentiality, conflict-of-interest disclosure, and competence limits: a signed design implies the standard of a competent engineer, not perfection.

Worked example

At 6%, v5 = 1/1.06⁵ = 0.747, and ten five-yearly maintenance payments of 4 M have PV = 4 × 2.80 = 11.2 M. Option A: 80 + 11.2 = 91.2 M. Option B: 60 + 11.2 + 15/1.06²⁵ = 60 + 11.2 + 3.5 = 74.7 M. B is cheaper by 16.5 M, but the year-25 repair is a single large risk, so the defensible conclusion adds a sensitivity test on the repair cost and on the discount rate.

Traps

  • Discounting nominal cash flows at a real rate, or comparing options at different rates.
  • Ranking mutually exclusive projects by IRR rather than incremental NPV.
  • Omitting maintenance and downtime from the comparison.