DSST Fundamentals of College Algebra flashcards
DSST Fundamentals of College Algebra · Build recall with a focused review session.
33 cards. Read the term and the definition here. The deck at the top of this page is optional.
- Imaginary unit i
- The number i is defined by i² = −1. For any positive real a, √(−a) = i√a. Powers of i cycle every four: i, −1, −i, 1.
- Complex number form
- A complex number is written a + bi, where a is the real part and b is the imaginary part (both real numbers). Equality holds iff real parts and imaginary parts match.
- Complex conjugate
- The conjugate of a + bi is a − bi. Their product is a² + b², a real number. Conjugates are used to divide complex numbers and to rationalize denominators.
- Modulus of complex number
- For z = a + bi, the modulus is |z| = √(a² + b²). It equals the distance from the origin to the point (a, b) in the complex plane.
- Multiplying complex numbers
- Use FOIL: (a+bi)(c+di) = ac + adi + bci + bdi². Replace i² with −1 to get (ac − bd) + (ad + bc)i.
- Dividing complex numbers
- Multiply numerator and denominator by the conjugate of the denominator: (a+bi)/(c+di) = [(a+bi)(c−di)]/(c²+d²). The result is in standard form.
- Powers of i
- For integer n > 0, iⁿ depends on n mod 4: remainder 1 gives i, 2 gives −1, 3 gives −i, 0 gives 1. Example: i²⁵ = i¹ = i.
- Adding complex numbers
- Add real parts and imaginary parts separately: (a+bi) + (c+di) = (a+c) + (b+d)i. Subtraction works the same way with signs.
- Order of operations
- Evaluate expressions in this order: grouping symbols, exponents, multiplication and division left to right, then addition and subtraction left to right.
- Exponent rules
- For a ≠ 0: aᵐ·aⁿ = aᵐ⁺ⁿ; aᵐ/aⁿ = aᵐ⁻ⁿ; (aᵐ)ⁿ = aᵐⁿ; (ab)ⁿ = aⁿbⁿ; a⁰ = 1; a⁻ⁿ = 1/aⁿ.
- Quadratic formula
- The solutions of ax² + bx + c = 0 (a ≠ 0) are x = [−b ± √(b² − 4ac)]/(2a). This formula works for all quadratic equations.
- Discriminant
- For ax² + bx + c = 0, the discriminant is D = b² − 4ac. If D > 0, two distinct real roots; D = 0, one real double root; D < 0, two complex conjugate roots.
- Difference of squares
- a² − b² factors as (a − b)(a + b). This pattern is used to simplify expressions and solve equations quickly.
- Sum and difference of cubes
- a³ + b³ = (a + b)(a² − ab + b²); a³ − b³ = (a − b)(a² + ab + b²). These factorizations are useful in polynomial equations.
- Remainder theorem
- When a polynomial P(x) is divided by x − r, the remainder is P(r). If P(r) = 0, then x − r is a factor of P(x).
- Logarithm rules
- For positive M, N and base b > 0, b ≠ 1: log_b(MN) = log_b M + log_b N; log_b(M/N) = log_b M − log_b N; log_b(Mᵖ) = p log_b M.
- Rationalizing denominators
- To eliminate a radical from a denominator, multiply numerator and denominator by the radical or by the conjugate of the denominator, then simplify.
- Linear equation solution
- An equation ax + b = 0 with a ≠ 0 has exactly one solution x = −b/a. If a = 0 and b ≠ 0, there is no solution; if a = 0 and b = 0, every number is a solution.
- Absolute value equation
- For c ≥ 0, |u| = c is equivalent to u = c or u = −c. If c < 0, the equation has no solution because absolute value is never negative.
- Absolute value inequality
- For c > 0: |u| < c means −c < u < c; |u| > c means u < −c or u > c. These translate to compound inequalities without absolute value.
- Inequality sign reversal
- Adding or subtracting the same number on both sides of an inequality preserves its direction. Multiplying or dividing both sides by a negative number reverses the inequality sign.
- Extraneous solutions
- When solving rational or radical equations, operations like squaring or multiplying by an expression can introduce solutions that do not satisfy the original equation. Always check answers in the original.
- Sum and product of roots
- For ax² + bx + c = 0 with roots r and s, r + s = −b/a and r·s = c/a. These relationships help check solutions and form equations from roots.
- Solving exponential equations
- If possible, express both sides with the same base and equate exponents. Otherwise, take the logarithm of both sides and solve for the variable.
- Interval notation
- A solution set can be written with intervals: (a, b) excludes endpoints; [a, b] includes them; (a, ∞) means x > a; (−∞, b] means x ≤ b.
- Function definition
- A function f from a set X to a set Y assigns to each element x in X exactly one element y in Y. The vertical line test identifies functions from their graphs.
- Domain of a function
- The domain is the set of all input values x for which the function is defined. Exclude values that make a denominator zero or an even root negative.
- Even and odd functions
- f is even if f(−x) = f(x) for all x in its domain; its graph is symmetric about the y-axis. f is odd if f(−x) = −f(x); its graph is symmetric about the origin.
- Function composition
- The composition (f ∘ g)(x) = f(g(x)) is defined when x is in the domain of g and g(x) is in the domain of f. Composition is not generally commutative.
- Inverse function
- If f is one-to-one, its inverse f⁻¹ satisfies f(f⁻¹(x)) = x and f⁻¹(f(x)) = x. The graph of f⁻¹ is the reflection of the graph of f across the line y = x.
- Horizontal line test
- A function is one-to-one (and therefore has an inverse function) if and only if no horizontal line intersects its graph more than once.
- Vertex of a parabola
- For f(x) = ax² + bx + c (a ≠ 0), the vertex occurs at x = −b/(2a). The parabola opens upward if a > 0 and downward if a < 0.
- Graph transformations
- For y = a f(x − h) + k: h shifts horizontally (right if h > 0), k shifts vertically, a stretches or compresses vertically, and negative a reflects across the x-axis.