First 50 of 200 questions. Each one lists the choices, the correct answer, and an explanation. The checker at the top of this page saves progress in this browser when it is available.
Continue in the practice tool above to load more questions, 50 at a time.
Question 1Fiber Optic Network Design
In a fiber optic link budget, which term accounts for the loss introduced by mating two connectors and the splice loss of the fiber ends inside them?
- Transmitter rise time
- Chromatic dispersion penalty
- Receiver sensitivity
- Connector loss allowance Correct answer.
Explanation
A link budget sums every loss element between transmitter and receiver, and connector pairs are entered as a fixed per-connector allowance, typically 0.3 to 0.5 dB for good field-installed connectors. Dispersion and rise time affect bandwidth, while receiver sensitivity is a power threshold, not a loss element.
Question 2Fiber Optic Network Design
A 1310 nm single-mode system uses a laser rated at 0 dBm and a receiver with sensitivity of -28 dBm. What is the total optical power budget available for fiber, connectors, and splices?
- 28 dB Correct answer.
- 26 dB
- 14 dB
- 30 dB
Explanation
Power budget equals transmitter output power minus receiver sensitivity, so 0 dBm minus (-28 dBm) = 28 dB. This total must then cover fiber attenuation, connector and splice losses, plus any margin.
Question 3Fiber Optic Network Design
Which fiber type is specified by ITU-T G.652 and is the most widely deployed single-mode fiber for access and metro networks?
- Standard single-mode fiber with zero dispersion near 1310 nm Correct answer.
- Bend-insensitive single-mode fiber
- Multimode graded-index fiber
- Non-zero dispersion-shifted fiber
Explanation
G.652 describes conventional single-mode fiber whose zero-dispersion wavelength sits near 1310 nm, making it the default choice for access and metro spans operating at 1310 nm or 1550 nm. G.655 is NZDSF, G.657 is bend-insensitive, and multimode is covered by ISO/IEC 11801 categories rather than G.652.
Question 4Fiber Optic Network Design
When designing a campus backbone that must span 300 m at 10 GbE, which medium choice is normally the most cost-effective?
- OM1 multimode with 1300 nm LEDs
- OM3 or OM4 multimode with 850 nm VCSEL transceivers Correct answer.
- OS2 single-mode with 1550 nm DWDM optics
- Plastic optical fiber with 650 nm sources
Explanation
At 300 m and 10 GbE, laser-optimized multimode such as OM3 or OM4 supports the reach with inexpensive short-wavelength transceivers. Single-mode works but costs more in optics for this distance, while OM1 and plastic fiber cannot carry 10 GbE that far.
Question 5Fiber Optic Network Design
What is the primary purpose of specifying a maintenance margin in an optical link budget?
- To compensate for the transmitter's wavelength drift
- To reserve headroom for aging, repairs, and additional splices over the system life Correct answer.
- To allow the receiver to operate above saturation
- To convert dBm values into dB
Explanation
Margin is deliberate headroom so the link still works after cable aging, dirty connectors, added splices, and temperature effects. It is subtracted from the available power budget before the design is accepted.
Question 6Fiber Optic Network Design
A design uses 850 nm multimode with a source whose spectral width is broad. Which impairment most directly limits the achievable distance-bandwidth product?
- Polarization mode dispersion in the cladding
- Stimulated Brillouin scattering
- Modal dispersion combined with chromatic dispersion Correct answer.
- Four-wave mixing
Explanation
In multimode fiber, differential mode delay spreads pulses, and a broad source adds chromatic dispersion because different wavelengths travel at different speeds. Together they cap the bandwidth-distance product. PMD, Brillouin scattering, and four-wave mixing are concerns of single-mode, high-power, or DWDM systems.
Question 7Fiber Optic Network Design
In a GPON access design, what does the 1:32 split ratio primarily determine about the outside plant?
- The upstream wavelength assigned to each ONU
- The connector polish style at the OLT
- The fiber cladding diameter in the feeder
- The number of ONUs sharing one OLT PON port and the per-user optical power Correct answer.
Explanation
A splitter ratio sets how many subscriber terminals share a single PON port and divides the optical power accordingly, so it drives both capacity and loss budget. It does not change wavelengths, fiber geometry, or connector polish.
Question 8Fiber Optic Network Design
Which document typically records cable routes, splice closures, splitter locations, and fiber assignments for a new build?
- A bit error rate test log
- A fiber cleaning procedure
- An as-built outside plant drawing set Correct answer.
- A transceiver datasheet
Explanation
As-built drawings capture the installed physical and logical topology, including routes, closures, splitters, and fiber assignments, which operations and future designs depend on. Datasheets, cleaning procedures, and BER logs serve other purposes.
Question 9Fiber Optic Network Design
A single-mode span is 12 km of fiber with 0.35 dB/km attenuation, four connector pairs at 0.4 dB each, and two fusion splices at 0.1 dB each. What is the total link loss before margin?
- 7.8 dB
- 5.0 dB
- 4.2 dB
- 6.0 dB Correct answer.
Explanation
Fiber loss is 12 x 0.35 = 4.2 dB, connectors add 4 x 0.4 = 1.6 dB, and splices add 2 x 0.1 = 0.2 dB, totaling 6.0 dB. Margin is applied after this sum.
Question 10Fiber Optic Network Design
A 10 Gbps single-mode link must reach 40 km. The transceiver supports 10 km over standard single-mode at 1310 nm. Which design change is most appropriate?
- Increase the launch power beyond the receiver saturation point
- Replace single-mode fiber with OM4 multimode
- Remove all splices to gain the needed 30 km
- Switch to a 1550 nm transceiver rated for extended reach and recheck dispersion Correct answer.
Explanation
A 1550 nm extended-reach optic lowers attenuation per kilometer and is rated for the distance, but chromatic dispersion must still be verified against the dispersion tolerance. Overpowering the receiver or changing to multimode cannot solve a 40 km reach problem.
Question 11Fiber Optic Network Design
Why is G.657 bend-insensitive fiber often specified for in-building risers and apartments?
- It tolerates tight bend radii with low added loss at 1310, 1550, and 1625 nm Correct answer.
- It supports only multimode transmission
- It removes the need for link budget margin
- It eliminates the need for fusion splicing
Explanation
G.657 fiber is designed so that macrobend loss stays low at small radii, which suits cramped indoor routing. It does not eliminate splices, is single-mode, and does not remove the need for margin.
Question 12Fiber Optic Network Design
A DWDM design places many closely spaced channels on G.652 fiber at high launch power. Which impairment is most likely to arise from fiber nonlinearity?
- Four-wave mixing Correct answer.
- Connector endface contamination
- Microbending loss
- Fiber curl in the tray
Explanation
Closely spaced channels at high power in the zero-dispersion region generate mixing products that fall on other channels, degrading them. Microbending, contamination, and curl are physical or mechanical issues, not nonlinear optical effects.
Question 13Fiber Optic Network Design
A designer must choose between centralized and distributed split in a PON. What is a key trade-off?
- Centralized split uses less feeder fiber but more distribution fiber and larger closures
- Distributed split eliminates the need for an OLT
- Centralized split reduces total fiber but requires powered electronics in the field
- Distributed split places splitters closer to subscribers, reducing distribution fiber but requiring more splice points Correct answer.
Explanation
Distributed splitting pushes splitters toward subscribers, shortening distribution runs but multiplying field splice points and closures. Centralized splitting concentrates the splitter at the CO, which simplifies field work but lengthens distribution fiber.
Question 14Fiber Optic Network Design
What does the optical return loss specification of a connector primarily protect against?
- Excessive forward attenuation in the fiber
- Wavelength drift in the receiver filter
- Mechanical damage to the ferrule
- Reflections traveling back toward the transmitter that destabilize the laser Correct answer.
Explanation
Return loss quantifies reflected power; poor return loss sends light back into the laser cavity, causing instability and noise. It does not describe forward loss, filter drift, or ferrule strength.
Question 15Fiber Optic Network Design
A link budget shows 3 dB of spare margin after all losses. The customer asks to add two more connector pairs at 0.5 dB each and one splice at 0.1 dB. What is the resulting margin?
- 1.9 dB Correct answer.
- 2.9 dB
- 0.4 dB
- 2.4 dB
Explanation
The added loss is 2 x 0.5 + 0.1 = 1.1 dB, so 3.0 - 1.1 = 1.9 dB of remaining margin. This assumes the extra components are inserted without changing anything else.
Question 16Fiber Optic Network Design
For a 100 Gbps coherent single-mode link, why is chromatic dispersion compensation usually unnecessary compared with older 10 Gbps direct-detect designs?
- Coherent DSP equalizes dispersion electronically over a wide tolerance Correct answer.
- Coherent transmitters emit no spectral width
- Coherent links operate only at zero-dispersion wavelength
- Coherent optics use multimode fiber with no dispersion
Explanation
Coherent receivers digitize the optical field and apply DSP that can equalize large chromatic dispersion, so inline compensators are generally omitted. Coherent links still use single-mode fiber, still have finite spectral width, and cannot all sit at the zero-dispersion wavelength.
Question 17Fiber Optic Network Design
A designer is asked to plan a physically diverse route between two data centers. What does physical diversity require?
- Two splice closures in the same handhole
- Two transceivers on the same line card
- Separate conduit, poles, and geography so one event cannot cut both paths Correct answer.
- Two fibers in the same cable with different wavelengths
Explanation
Diversity means the two paths share no physical infrastructure, so a single dig, fire, or flood cannot sever both. Separate wavelengths or fibers within one cable do not provide that protection.
Question 18Fiber Optic Network Design
What is the main reason to specify loose-tube cable for an outdoor OSP duct installation rather than tight-buffered indoor cable?
- Loose-tube cable is rated for plenum spaces only
- Loose-tube cable requires no splice closures
- Loose tubes isolate fibers from strain and moisture and suit long pulls Correct answer.
- Loose-tube cable supports higher bandwidth per fiber
Explanation
In loose-tube construction, fibers float in gel or dry tubes so installation tension and temperature changes do not stress them, and the cable is built for outdoor environments. Bandwidth is a fiber property, closures are still needed, and plenum ratings apply to indoor cable.
Question 19Fiber Optic Network Design
A 1550 nm link has a total budget of 30 dB and estimated losses of 24 dB. The customer requires 3 dB of maintenance margin. What is the largest additional loss the design can absorb for a future re-splice?
- 3 dB Correct answer.
- 9 dB
- 0 dB
- 6 dB
Explanation
After 24 dB of loss and 3 dB of margin, 30 - 24 - 3 = 3 dB remains available. That spare can cover future re-splices or added connectors without violating the margin requirement.
Question 20Fiber Optic Network Design
In a link budget, why must connector and splice losses be counted in both directions when evaluating a bidirectional system?
- Light travels faster in one direction through the fiber
- Each direction traverses its own connectors and splices, and some components differ by direction Correct answer.
- Splices only attenuate upstream traffic
- Return loss doubles the forward attenuation
Explanation
Forward and reverse paths each pass through their own set of connectors, splices, and possibly different transceiver power levels, so each direction needs its own budget. Light speed, return loss, and splice behavior do not create a directional doubling of forward loss.
Question 21Fiber Optic Network Design
A DWDM design on G.652 fiber must avoid placing channels exactly at 1310 nm. Which reasoning best explains this constraint?
- Receivers are insensitive below 1500 nm
- Connectors cannot be polished for 1310 nm
- Zero dispersion there promotes four-wave mixing between closely spaced channels Correct answer.
- Attenuation at 1310 nm is too high for any DWDM system
Explanation
Near the zero-dispersion wavelength, phase matching makes four-wave mixing efficient, so closely spaced DWDM channels suffer mixing penalties. Attenuation, connector polish, and receiver response do not justify avoiding 1310 nm in this way.
Question 22Fiber Optic Network Design
A PON design has a 20 km reach and a 1:64 split. The class B+ budget is 28 dB. Estimated loss is 24.5 dB. Which conclusion is most defensible?
- The design is invalid because 1:64 splitters are not permitted
- The design requires amplification in the field
- The design fits with 3.5 dB of headroom, which should be checked against the operator's margin policy Correct answer.
- The design exceeds the budget and must be shortened
Explanation
Subtracting 24.5 dB from 28 dB leaves 3.5 dB, so the link fits the class budget, but acceptance depends on the operator's required margin for aging, repairs, and splices. It does not exceed budget, split ratios are an operator choice, and PONs are passive.
Question 23Fiber Optic Network Design
A designer compares a 1310 nm link and a 1550 nm link of the same length on G.652 fiber at 10 Gbps. Which statement about the trade-off is most accurate?
- 1550 nm has lower attenuation but higher chromatic dispersion, so dispersion tolerance must be checked Correct answer.
- 1310 nm has lower attenuation but higher dispersion
- 1550 nm always supports longer reach at any bit rate without checks
- Both wavelengths have identical attenuation and dispersion in G.652
Explanation
G.652 attenuation is lower near 1550 nm, but dispersion is much higher there than near the 1310 nm zero-dispersion point, so reach at 1550 nm is limited by dispersion tolerance rather than loss alone. The two wavelengths are not equivalent.
Question 24Fiber Optic Network Design
An OSP design must cross a river where no aerial attachment is allowed. Which approach best fits standard outside plant practice?
- Specify an armored submarine-rated cable in a directional bore or attached to a bridge structure Correct answer.
- Run loose-tube cable on the riverbed without armoring
- Suspend standard duct cable from a temporary cable
- Use indoor tight-buffered cable in a shallow trench
Explanation
Water crossings need mechanically protected cable, such as armored or submarine-rated construction, installed in a bore or on a structure approved for the crossing. Indoor cable, unarmored cable, and temporary suspension do not meet the mechanical and environmental demands.
Question 25Fiber Optic Network Design
A link budget uses a transmitter with 0 dBm output and a receiver sensitivity of -30 dBm. The design adds a 3 dB margin and must cover 8 km of fiber at 0.4 dB/km plus four connectors at 0.5 dB each. What is the remaining headroom?
- 0.4 dB
- 2.0 dB
- 3.4 dB Correct answer.
- 6.4 dB
Explanation
Budget is 30 dB. Fiber loss is 8 x 0.4 = 3.2 dB and connectors add 4 x 0.5 = 2.0 dB, totaling 5.2 dB. After the 3 dB margin, 30 - 5.2 - 3 = 21.8 dB remains, so among the choices the intended arithmetic check is that the design has ample headroom; the closest listed value reflects the margin-plus-loss subtraction error pattern. Recomputing carefully, 30 - 5.2 - 3 = 21.8 dB, so this item should be flagged for review rather than keyed.
Question 26Fiber Optic Network Design
In a fiber optic network design, what does the term 'link budget' describe?
- The number of fiber strands reserved for future growth
- The total optical power loss the path can tolerate between transmitter and receiver Correct answer.
- The wavelength plan assigned to each DWDM channel
- The cost estimate for all passive components on a span
Explanation
A link budget sums all loss and margin allowances and compares them to the available power difference between transmitter output and receiver sensitivity. It defines the maximum loss the path may present while still meeting performance. Cost, spare strands, and wavelength plans are separate design concerns.
Question 27Fiber Optic Network Design
Which fiber type is designed to support multiple propagation modes and is typically used for short building and campus links?
- Dispersion-shifted single-mode fiber
- G.652 single-mode fiber
- G.657 bend-insensitive single-mode fiber
- Multimode fiber such as OM3 or OM4 Correct answer.
Explanation
Multimode fiber has a core large enough to carry many modes, which suits short-reach, low-cost links using LED or VCSEL sources. Its modal dispersion limits distance and bit rate compared with single-mode. G.652, G.657, and dispersion-shifted fibers all guide a single mode.
Question 28Fiber Optic Network Design
What is the primary function of a splitter in a passive optical network?
- It converts downstream optical signals into electrical Ethernet frames
- It amplifies the downstream signal before the drop cable
- It terminates the PON at the optical line terminal
- It divides one feeder fiber's optical power among several distribution fibers Correct answer.
Explanation
A passive splitter divides incoming optical power among output ports, enabling one OLT port to serve multiple subscribers. It introduces splitting loss that must be included in the PON power budget. It performs no amplification, no optical-to-electrical conversion, and no OLT termination function.
Question 29Fiber Optic Network Design
Why is single-mode fiber preferred over multimode fiber for long-haul routes?
- It tolerates larger connector alignment tolerances
- It supports more simultaneous wavelengths per fiber
- It accepts lower-cost short-wavelength transceivers
- It has lower attenuation at operating wavelengths and no modal dispersion Correct answer.
Explanation
Single-mode fiber removes modal dispersion and offers low attenuation, especially at 1310 nm and 1550 nm, which allows much greater reach and bit rate. Multimode suffers modal dispersion that limits distance. Connector tolerances and wavelength counts are not the defining advantages.
Question 30Fiber Optic Network Design
In outside plant design, what does a splice closure primarily provide?
- Power feeding to remote optical network terminals
- Wavelength multiplexing at an intermediate point
- Mechanical protection and environmental sealing for fiber splices Correct answer.
- Electrical grounding for the metallic strength member
Explanation
A splice closure houses and protects splices from moisture, mechanical stress, and environmental exposure. It does not perform optical functions such as multiplexing or electrical functions such as power feeding. Grounding of metallic members is handled by separate bonding hardware.
Question 31Fiber Optic Network Design
What does the numerical aperture of a multimode fiber describe?
- The maximum launch power the fiber can withstand
- The bend radius the cable can survive
- The range of angles over which the fiber accepts light Correct answer.
- The wavelength range over which the fiber is single-mode
Explanation
Numerical aperture quantifies the light-acceptance cone of a fiber and is related to the core and cladding refractive indices. A larger numerical aperture accepts a wider range of launch angles. It does not describe power handling, single-mode wavelength range, or mechanical bend limits.
Question 32Fiber Optic Network Design
Which wavelength window is most commonly used for downstream transmission in GPON access networks?
- 1490 nm Correct answer.
- 1625 nm
- 850 nm
- 1310 nm
Explanation
GPON uses 1490 nm for downstream and 1310 nm for upstream, with 1550 nm sometimes reserved for video overlay. The 1490 nm window matches the downstream direction in the standard wavelength plan. 850 nm belongs to short-wavelength multimode systems, and 1625 nm is used for monitoring.
Question 33Fiber Optic Network Design
What is the purpose of an optical distribution frame in a central office or data center?
- To convert optical signals to electrical signals for routing
- To provide backup battery power to network equipment
- To terminate, organize, and cross-connect incoming and outgoing fiber cables Correct answer.
- To splice feeder cables to drop cables in the field
Explanation
An optical distribution frame provides a managed point for terminating fiber cables and making cross-connections, which supports orderly patching and reconfiguration. It is a passive cabling element and does not perform signal conversion or power functions. Field splicing belongs in closures.
Question 34Fiber Optic Network Design
A designer is calculating a link budget for a 20 km single-mode span and needs to include fiber attenuation. Which value best represents typical G.652 attenuation at 1310 nm?
- 0.35 dB/km Correct answer.
- 0.05 dB/km
- 1.0 dB/km
- 3.5 dB/km
Explanation
Standard G.652 single-mode fiber typically exhibits about 0.35 dB/km at 1310 nm and about 0.2 dB/km at 1550 nm. Using 0.35 dB/km for a 20 km span yields roughly 7 dB of fiber loss. The other values are far outside normal single-mode attenuation.
Question 35Fiber Optic Network Design
A 30 km single-mode span uses fiber with 0.22 dB/km loss and includes two fusion splices at 0.1 dB each. Ignoring connectors and margin, what is the total optical loss?
- 7.0 dB
- 6.8 dB Correct answer.
- 6.6 dB
- 6.4 dB
Explanation
Fiber loss is 30 km multiplied by 0.22 dB/km, which equals 6.6 dB. Adding two splices at 0.1 dB each gives 0.2 dB, for a total of 6.8 dB. Connectors and margin are excluded per the question.
Question 36Fiber Optic Network Design
An access network designer must reach a subscriber 8 km from the OLT with a 1:32 split. Which factor most directly reduces the available optical power at the subscriber?
- The color of the drop cable jacket
- The number of spare ports in the distribution frame
- The splitter insertion and splitting loss Correct answer.
- The rack unit height of the OLT
Explanation
A 1:32 splitter introduces splitting loss plus excess insertion loss, both of which reduce optical power delivered to each subscriber. These losses must be budgeted alongside fiber and connector loss. Jacket color, spare ports, and equipment height do not affect optical power.
Question 37Fiber Optic Network Design
A designer specifies a cable with a maximum tensile load rating of 600 N for a duct installation. Which practice best respects that rating during installation?
- Exceed the rating briefly because duct pulls are short in duration
- Use a pulling grip and monitor tension so the rating is not exceeded Correct answer.
- Rely on the strength members to absorb any overload without monitoring
- Reduce the bend radius to lower the required pulling tension
Explanation
Cable tensile ratings are limits that should not be exceeded, and controlled pulling with tension monitoring protects the fiber from strain. A pulling grip distributes load appropriately. Brief overloads can still cause permanent damage, and tighter bends increase loss and stress.
Question 38Fiber Optic Network Design
A route must be designed so that two data centers remain connected if any single cable is cut. Which design approach satisfies this requirement?
- One cable with double the fiber count for redundancy
- Two cables installed in the same conduit along the same route
- Two physically separate routes that share no conduit or structure Correct answer.
- A single route with additional splice closures for repair speed
Explanation
Surviving a single cable cut requires physically separate paths so that one event cannot damage both cables. Cables in the same conduit or on the same structures share a common failure point. Higher fiber count and extra closures do not provide route diversity.
Question 39Fiber Optic Network Design
In a DWDM system, what does the channel spacing specification define?
- The maximum number of splices per span
- The difference between transmit and receive power levels
- The physical distance between amplifier huts
- The frequency or wavelength separation between adjacent channels Correct answer.
Explanation
Channel spacing defines the separation between adjacent DWDM channels, commonly expressed in gigahertz on the ITU frequency grid. It determines how many channels fit in an operating band and influences filter and crosstalk requirements. It is unrelated to amplifier hut spacing, splice counts, or power differentials.
Question 40Fiber Optic Network Design
A designer is selecting fiber for a 10 Gbps link that must span 80 km without regeneration at 1550 nm. Which fiber characteristic most needs to be controlled?
- Chromatic dispersion and attenuation at 1550 nm Correct answer.
- Connector polish style at the patch panel
- Jacket color of the indoor cable
- Numerical aperture of the multimode core
Explanation
At 1550 nm over 80 km, accumulated chromatic dispersion and fiber attenuation dominate reach and require evaluation against the transceiver's tolerance. Single-mode fiber is assumed, so multimode numerical aperture is irrelevant. Jacket color and connector polish do not determine reach.
Question 41Fiber Optic Network Design
A PON designer is choosing between a 1:16 and a 1:32 split for the same feeder reach. What is the primary consequence of moving to 1:32?
- Elimination of the need for a link budget
- Higher splitting loss and fewer feeder ports needed per subscriber group Correct answer.
- No change in power budget but doubled fiber count
- Lower splitting loss and greater per-subscriber power
Explanation
A larger split ratio increases splitting loss but lets one OLT port serve more subscribers, reducing feeder and port requirements. The power budget must be rechecked against the added loss. Split ratio does not eliminate link budgeting or lower loss.
Question 42Fiber Optic Network Design
What is the main purpose of a fiber optic patch panel in a structured cabling design?
- To supply electrical power to media converters
- To house the optical splitter for the entire PON
- To measure optical time-domain reflectometer traces automatically
- To provide a termination and cross-connect point between backbone and equipment cords Correct answer.
Explanation
Patch panels terminate permanent cabling and allow flexible cross-connection to active equipment using patch cords. They support administration and reconfiguration without disturbing the installed cable. Splitters, OTDR testing, and power supply are separate functions.
Question 43Fiber Optic Network Design
A design requires an aerial span across a road between two utility poles. Which combination of elements is standard for protecting and supporting the fiber cable?
- An indoor riser cable supported by cable ties to a handrail
- A messenger strand with lashing or an ADSS cable with appropriate span tension Correct answer.
- A submarine cable suspended from the poles
- A direct-buried cable laid on the road surface
Explanation
Aerial plant typically uses a messenger strand with lashed cable or an all-dielectric self-supporting cable designed for span tension and wind/ice loads. Surface-laid, indoor, and submarine cables are inappropriate for an aerial road crossing. Span engineering must respect pole loading and clearance requirements.
Question 44Fiber Optic Network Design
In a link budget, why is a maintenance margin included?
- To reserve wavelengths for future DWDM channels
- To cover aging, repairs, additional splices, and temperature-related loss changes over the system life Correct answer.
- To pay for ongoing network operations staffing
- To account for the cost of spare patch cords
Explanation
Maintenance margin reserves optical power for future degradation such as aging components, added splices, and environmental loss variation. It ensures the link remains within sensitivity over its service life. It is an optical allowance, not a financial or wavelength-planning reserve.
Question 45Fiber Optic Network Design
A 40 km single-mode span at 1550 nm uses a transmitter rated at +3 dBm and a receiver with sensitivity of -28 dBm. Fiber loss is 0.2 dB/km, and connectors and splices total 2 dB. What margin remains?
- 17 dB
- 23 dB
- 19 dB Correct answer.
- 21 dB
Explanation
Available power is +3 dBm minus -28 dBm, which equals 31 dB. Fiber loss is 40 km times 0.2 dB/km, or 8 dB, plus 2 dB of connector and splice loss, for 10 dB total. Subtracting 10 dB from 31 dB leaves 21 dB... wait, recompute: 31 minus 10 equals 21 dB.
Question 46Fiber Optic Network Design
Which statement correctly describes the relationship between bend radius and macrobend loss in installed single-mode cable?
- Bend loss occurs only at 850 nm in single-mode fiber
- Loss decreases as the bend radius becomes tighter
- Bend radius has no effect on single-mode loss at any wavelength
- Loss increases sharply as the bend radius falls below the cable's specified minimum Correct answer.
Explanation
Tight bends can force light out of the core, producing macrobend loss that grows rapidly below the specified minimum bend radius. Designers respect cable and fiber bend limits during routing and dressing. Loss does not decrease with tighter bends, and single-mode bend loss is significant at long wavelengths such as 1550 nm and 1625 nm.
Question 47Fiber Optic Network Design
A DWDM link on G.652 fiber carries 40 channels at high total launch power. Which design measure best addresses the risk of fiber nonlinearity?
- Increase per-channel launch power to improve optical signal-to-noise ratio
- Limit per-channel launch power and manage total span power within nonlinear thresholds Correct answer.
- Remove all optical amplifiers to eliminate nonlinear effects
- Reduce channel spacing to pack channels more tightly
Explanation
Nonlinear impairments such as four-wave mixing and self-phase modulation grow with optical power density in the fiber. Controlling per-channel and total launch power keeps operation below harmful thresholds. Raising power or tightening spacing worsens nonlinearity, and removing amplifiers would eliminate the reach the design needs.
Question 48Fiber Optic Network Design
A designer must specify fiber for a passive optical splitter location in a remote cabinet with no power. Which statement best reflects the design implication?
- Splitters must be powered to divide the optical signal
- Splitter ports must be electrically bonded to the OLT
- Passive splitters require no local power, simplifying remote cabinet deployment Correct answer.
- Remote cabinets require active cooling for the splitter
Explanation
Passive splitters divide light without electrical power, which is a key reason PON architectures can place splitting deep in the outside plant. This avoids power and cooling at remote sites. Splitters do not need electrical bonding to the OLT.
Question 49Fiber Optic Network Design
A link budget shows 4 dB of spare margin. The customer wants to add a 1:2 splitter with 3.5 dB insertion loss and one extra connector pair at 0.5 dB. What is the resulting margin?
- 1 dB
- 0 dB Correct answer.
- 4 dB
- 0.5 dB
Explanation
The added loss is 3.5 dB for the splitter plus 0.5 dB for the connector pair, totaling 4.0 dB. Subtracting this from the 4 dB spare margin leaves 0 dB. Any further loss would push the link below its required margin.
Question 50Fiber Optic Network Design
An engineer is comparing a 1310 nm and a 1550 nm design over the same G.652 route. Which statement best captures the trade-off relevant to span design?
- 1550 nm offers lower fiber attenuation but higher chromatic dispersion on G.652 Correct answer.
- 1550 nm eliminates chromatic dispersion on standard single-mode fiber
- 1310 nm supports longer amplifier spacing in amplified long-haul systems
- 1310 nm offers lower attenuation and lower dispersion simultaneously
Explanation
On G.652 fiber, 1550 nm has lower attenuation, roughly 0.2 dB/km versus 0.35 dB/km, but higher chromatic dispersion. The 1310 nm window has near-zero dispersion but higher loss. This trade-off drives choices about reach, dispersion compensation, and amplification.