Pumps, Motors, and Process Instrumentation
This domain covers pump hydraulics, motor operation, and the instrumentation used to monitor and control treatment processes. The exam tests your ability to calculate pump power, interpret pump curves, and troubleshoot instrumentation.
Pump Fundamentals
- Centrifugal pumps are the most common in water treatment. They operate on a curve relating flow, head, efficiency, and power. The best efficiency point (BEP) is where efficiency is highest.
- Positive displacement pumps deliver a fixed volume per stroke or revolution; they are used for chemical feed.
- Cavitation occurs when local pressure drops below vapor pressure, causing bubbles that collapse and damage impellers. Net positive suction head (NPSH) must be adequate: NPSH available > NPSH required.
- System head curve combined with pump curve determines operating point.
Pump Power Calculations
- Water horsepower (whp) = (Q × H × 8.34) / 33,000, where Q is gpm and H is feet. Alternatively, whp = (Q × H) / 3960 for Q in gpm and H in feet.
- Brake horsepower (bhp) = whp / pump efficiency.
- Motor horsepower = bhp / motor efficiency.
Motors and Electrical
- Motor speed for AC induction motors: synchronous speed = (120 × frequency) / number of poles. Slip reduces actual speed.
- Variable frequency drives (VFDs) control motor speed to match demand, saving energy. Affinity laws: flow ∝ speed, head ∝ speed², power ∝ speed³.
- Motor protection includes overload relays, thermal protection, and phase monitors.
Instrumentation
- Flow meters: magnetic, ultrasonic, orifice, venturi, turbine. Each has accuracy and installation requirements.
- Level sensors: ultrasonic, pressure, float, radar.
- Turbidimeters: nephelometric (NTU) measure scattered light; keep lenses clean and calibrate.
- pH and chlorine analyzers require regular calibration and maintenance.
- SCADA integrates sensors and controls; alarms should be set for critical parameters.
Worked Example
A pump delivers 500 gpm against 100 ft of head. The pump efficiency is 75% and motor efficiency is 90%. Calculate the motor horsepower required.
- whp = (500 × 100) / 3960 = 12.63 hp.
- bhp = 12.63 / 0.75 = 16.84 hp.
- Motor hp = 16.84 / 0.90 = 18.71 hp.
- A 20 hp motor would be selected (next standard size).
Common Traps
- Using the wrong constant in horsepower formulas (3960 vs. 33,000).
- Forgetting to divide by both pump and motor efficiency.
- Confusing NPSH available with NPSH required; available must exceed required.
- Applying affinity laws incorrectly: power changes with cube of speed.
- Neglecting calibration of turbidimeters and pH analyzers, leading to false readings.