Odisha CHSE +2 Vocational Information Technology study materials
Odisha CHSE +2 Vocational Information Technology study resources

Odisha CHSE +2 Vocational Information Technology: Computer Fundamentals and Hardware

Odisha CHSE +2 Vocational Information Technology · Work through your exam, one topic at a time.

All guide sections

Computer Fundamentals and Hardware

This section tests the block diagram of a computer, the job of each unit, memory types and capacities, and number-system conversions - the short-answer and one-mark questions that open most papers.

Functional units

A computer has five blocks: input unit, output unit, memory unit, arithmetic logic unit (ALU) and control unit (CU). ALU + CU + registers = CPU. The CU fetches and decodes instructions and issues control signals; the ALU performs arithmetic and comparisons; registers are the fastest storage, inside the CPU; the system bus carries data, addresses and control signals.

Memory

  • Primary: RAM (volatile; SRAM = flip-flops, fast, used for cache; DRAM = capacitors, cheaper, main memory) and ROM (non-volatile: PROM, EPROM, EEPROM).
  • Secondary: magnetic (HDD), solid-state (SSD, pen drive), optical (CD 700 MB, DVD 4.7 GB).
  • 1 byte = 8 bits; 1 KB = 1024 B; 1 MB = 1024 KB; 1 GB = 1024 MB; 1 TB = 1024 GB.
  • Cache sits between CPU and RAM: small but fastest of the memory hierarchy.

Number systems

Binary (2), octal (8), decimal (10), hexadecimal (16); hex uses 0–9 and A–F.

Worked example

Convert 11011010₂ to hexadecimal and decimal. Hex: group in fours from the right → 1101 1010 → D A → DA₁₆. Decimal: place values 128+64+0+16+8+0+2+0 = 218. Check: D = 13 → 13×16 = 208, plus A = 10 → 218. ✔

Traps

  • Calling the CU the unit that does calculations - that is the ALU.
  • Saying ROM is volatile, or that RAM keeps data after shutdown.
  • Writing 1 MB = 1000 KB; this paper expects 1024.
  • Converting hex to binary via decimal instead of expanding each hex digit to four bits.