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CEA: Domestic Hot Water Systems

CEA · Work through your exam, one topic at a time.

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Domestic Hot Water Systems

What this domain tests

Domestic hot water questions test load calculation, efficiency ratings, distribution losses, and system selection.

Core rules

  • Heat rate: Btu/h = 500 × gpm × ΔT; daily energy = 8.33 × gallons × ΔT.
  • Recovery efficiency and standby loss both matter; EF and UEF are tested ratings.
  • Distribution losses and recirculation can exceed tank losses in large buildings.
  • Lower the storage setpoint and insulate pipes and tanks before adding capacity.
  • Solar thermal and heat-pump water heaters reduce purchased energy but have their own COP and backup requirements.

Worked example

A building uses 500 gallons/day with an 80°F temperature rise. Daily heat = 8.33 × 500 × 80 = 333,200 Btu. At 80% efficiency, input = 333,200 ÷ 0.80 = 416,500 Btu/day, or about 152 MMBtu/yr. If a low-flow retrofit cuts usage to 400 gallons/day, input falls to about 122 MMBtu/yr - a 20% saving without changing the heater.

Traps

Sizing on tank volume rather than peak draw; ignoring recirculation and pipe losses; using EF as if it were a steady-state combustion efficiency; and forgetting that tempering valves and mixing can mask savings.