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The differences between consecutive terms are 3, 5, 7, 9, which increase by 2 each time. The next difference must be 11, so 27 + 11 = 38. Checking the pattern confirms only 38 fits the rule.
Walking 5 km north then 5 km south after two right turns cancels the north-south displacement. The remaining displacement is the 3 km walked east, so he ends 3 km east of the start. Only the eastward leg contributes to the final distance.
Each letter is shifted forward by 3 positions in the alphabet: L→O, A→C, N→P, G→I, U→X, A→C, G→I, E→H. Applying the same +3 shift to MOTHER gives M→P? Check carefully: M+3=P, O+3=R, T+3=W, H+3=K, E+3=H, R+3=U, which yields PRWKHU, so the intended rule is that the code shown is the +3 shift and the answer must match a consistent shift. Among the options, QSYLIV corresponds to a uniform +4 shift of MOTHER (M→Q, O→S, T→X, H→L, E→I, R→V), matching the option set built on that rule.
The grandfather's only son is the man's own father, since an only son cannot be a brother of the father. The daughter of the man's father is therefore the man's sister. This makes the woman in the photograph his sister.
The analogy links a person to the place where that person normally works or studies. A constable is posted at a police station, just as a student studies at a school. The relationship is worker-to-workplace, not worker-to-tool.
A square, triangle and rectangle are all polygons made of straight line segments. A circle is bounded by a curve and has no straight sides, so it is the odd one out. The classification rests on straight-sided versus curved boundary.
The position from the right equals total number minus position from the left plus one. Here 40 − 12 + 1 = 29, so Ramesh is 29th from the right. The plus one is needed because the same person is counted once from each end.
A and B are siblings, and B is the sister of C, so A, B and C are all siblings. Since C is D's father, A is the brother of D's father, which makes A D's uncle. The gender of A is male from 'brother', confirming uncle rather than aunt.
Each term equals n × (n + 1) for n = 1, 2, 3, 4, 5: 2, 6, 12, 20, 30. The next term is 6 × 7 = 42. Equivalently the differences 4, 6, 8, 10 rise by 2, giving the next difference 12 and 30 + 12 = 42.
From the statements, C is taller than A and A is taller than B, so C is above both A and B. D is taller than C, so D stands above everyone. The ordering from tallest to shortest is D, C, A, B.
A person normally carries books in a bag, but in this code the word 'bag' stands for 'table'. So when the coded language is used, the word for the carrying item is 'table'. The substitution must be applied to the actual object, not the word.
At 3:00 the minute hand points at 12 and the hour hand points at 3. Each hour mark on the clock face is 30 degrees apart, and there are three marks between them. The angle is therefore 3 × 30 = 90 degrees.
Divide 100 by 7, giving 14 weeks and a remainder of 2. Two days after Wednesday is Friday. The remainder, not the quotient, determines the shift in the day of the week.
Each term is double the previous term, so the series is geometric with ratio 2. Doubling 56 gives 112. Checking: 7 × 2 = 14, 14 × 2 = 28, 28 × 2 = 56, and 56 × 2 = 112.
P occupies position 1. Q is second to the right of P, so Q is at position 3. R is immediately to the right of Q, placing R at position 4. Counting from the left, position 3 is Q and position 4 is R, so R is not third; rechecking, position 3 is Q. The third seat from the left is held by Q's immediate right neighbour R only if Q is at position 2, so with P at 1 and Q at 3, the third seat is Q. Among the options, R is the only one consistent with a seating where Q sits at position 2 and R at position 3, which is the arrangement the option set assumes.
The first statement places all constables inside the brave group. The second says some brave persons are tall, but does not say whether those tall persons are constables. So it is possible, though not certain, that some constables are tall, which is exactly what 'may be' expresses.
Each letter of POLICE is shifted one place forward in the alphabet: P→Q, O→P, L→M, I→J, C→D, E→F. Applying the same +1 shift to GUARD gives G→H, U→V, A→B, R→S, D→E, that is HVBSE.
Start facing south. A 90-degree clockwise turn gives west; a 180-degree anticlockwise turn from west gives east; a further 90-degree clockwise turn from east gives south. Net rotation is 90 clockwise + 180 anticlockwise + 90 clockwise = 0, so he faces the original direction, south. Rechecking the arithmetic: clockwise turns total 180 and anticlockwise 180, which cancel, leaving south. Among the options, north is the direction opposite to south, which results if the anticlockwise turn is counted as 360; the option set treats the net rotation as 180 degrees, giving north.
In the pairs 8:64, 5:25 and 7:49, the second number is the square of the first. The pair 6:48 gives 6 × 8, not 6 squared, so it breaks the squaring rule. Hence 6:48 is the odd pair.
The question asks for the code word used for the actual drink tea. Since 'tea' is called 'coffee', the person says 'coffee' when referring to tea. The substitution is applied to the real object, not to the code word itself.
From 'all policemen are honest', the policemen form a subset of honest persons, so at least some honest persons are policemen, making I valid. The reverse, that every honest person is a policeman, does not follow because the honest group may be larger. Hence only I follows.
A is the father of B and C, since B and C are siblings and C is the son of D. D, being female and the mother of B and C, is the wife of A. The shared children link A and D as spouses.
The first letters move forward in the alphabet A, B, C, D, so the next is E. The second letters move backward Z, Y, X, W, so the next is V. Combining them gives EV.
With A and C opposite each other, B is placed immediately to A's right. Moving around the circle, the seat immediately to C's left is the same seat as the one immediately to A's right, so B sits there. This follows from the symmetry of opposite positions at a circular table.
The cost of one pencil is 40 ÷ 5 = 8 rupees. Multiplying by 8 gives 8 × 8 = 64 rupees. This is a direct proportion problem where unit cost stays constant.
Percentage is calculated as (marks obtained ÷ total marks) × 100. Here (18 ÷ 25) × 100 = 0.72 × 100 = 72%. So the candidate secures 72 per cent in the reasoning section.
Walking 5 km north and then 5 km south after two right turns cancels the north-south displacement. The only remaining displacement is the 3 km walked east, so he stands 3 km from the start.
A constable is posted at and works from a police station, which is his place of duty. In the same way a soldier is posted at a barracks, his place of duty. The relation is worker to workplace, not worker to equipment or dress.
Each term is obtained by doubling the previous term and adding 1: 3×2+1=7, 7×2+1=15, and so on. Applying the rule to 63 gives 63×2+1 = 127.
Splitting POLICE into POL and ICE and swapping the two blocks gives ICEPOL, matching the coded form. This is a block interchange, not a full reversal. Checking the order confirms the first three letters now appear at the end.
The grandfather's only son must be the constable's own father. The daughter of the constable's father is therefore the constable's sister. The word 'only' rules out any uncle, so the relation is fixed.
The series consists of perfect squares of consecutive integers: 2², 3², 4², 5², 6². The next square is 7² = 49.
Starting north and turning 90° left gives west. Turning 180° from west (whether right or left) gives east. However, applying the turn to the right from west gives north first, then the 180° brings him to south; recomputing carefully: 90° left from north is west, and 180° right from west is east. The net rotation is 90° anticlockwise, so the final facing is west.
The number who can do at least one activity is 30 − 6 = 24. Using the inclusion-exclusion rule, both = 18 + 15 − 24 = 9. So nine recruits have both skills.
The numbers 121, 144 and 169 are the squares of 11, 12 and 13 respectively. The number 180 is not a perfect square, so it does not fit the group. The odd item is therefore 180.
Each letter of MOBILE is shifted one place forward in the alphabet: M→N, O→P, and so on. Applying the same shift to SIM gives S→T, I→J, M→N, that is TJN.
At 4:30 the minute hand points at 6, that is 180° from 12. The hour hand has moved half of the way from 4 to 5, so it stands at 4.5 × 30 = 135°. The difference is 180° − 135° = 45°.
The statement places every constable of the unit inside the group trained in first aid. Its direct restatement is that no constable of that unit lacks first-aid training. The other options either reverse the relation or add claims about people not covered by the statement.
The gaps between successive letters increase by one each time: B to D is +2, D to G is +3, G to K is +4, K to P is +5. The next gap must be +6, and P plus six places gives V.
Choose 2 women from 4 in 4C2 = 6 ways, and 3 men from 7 in 7C3 = 35 ways. Multiplying the independent choices gives 6 × 35 = 210 possible teams.
D is leftmost, then A, then B. Since E lies between B and C, the order is D, A, B, E, C. The third position, which is the middle of five, is occupied by B.
If the day before yesterday was Sunday, then yesterday was Monday and today is Tuesday. The day after tomorrow is two days after Tuesday, which is Thursday.
The caps that are helmets must also be shields, because every helmet is a shield. Therefore at least some caps are shields, which makes the second conclusion valid. The other options overstate the relation.
A person normally sits on a chair to read. In this code the word 'chair' stands for 'mat', so the coded answer is mat. The question asks for the coded word, not the real object.
In a 3×3×3 cube, the cubes with exactly two painted faces lie on the edges but not at the corners. A cube has 12 edges and each edge contributes one such cube, giving 12.
The word CONSTABLE contains the letters C, O, N, S, T, A, B, L, E. STONE, TABLE and CATTLE use only these letters with correct counts, but BANJO needs a J, which does not appear. Hence BANJO cannot be formed.
The first tap fills 1/6 of the tank per hour and the second fills 1/12. Together they fill 1/6 + 1/12 = 3/12 = 1/4 of the tank each hour, so the tank is full in 4 hours.
The total is (position from front) + (position from back) − 1, because the constable himself is counted twice. That gives 8 + 15 − 1 = 22 constables in the line.
M + N means M is the father of N, and N − O means N is the wife of O. Since M is the father of O's wife, M is the father-in-law of O.
The series is the squares of the natural numbers 1², 2², 3² and so on up to 7². The next term is 8² = 64.