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The rule shifts each letter forward by one position in the alphabet: S to T, T to U, and so on. Applying the same shift to DECREE gives D to E, E to F, C to D, R to S, E to F, E to F, producing EFD SFF. Consistency of the single-step shift is what fixes the answer.
Substitution coding replaces each word with its assigned code word while preserving the original order of words. 'ORDER' maps to 'judgment' and 'SHEET' maps to 'charge sheet', so 'ORDER SHEET' becomes 'judgment charge sheet'. Positional order must be retained, which rules out reordered variants.
The first half is A B C D and the second half is E F G H. Reversing the first half gives D C B A, and placing it after the unchanged second half yields E F G H D C B A. The operation requires both reversing and relocating, so only the fully transformed sequence is correct.
The position from the right equals total count minus position from the left plus one. Here 40 minus 27 plus 1 equals 14, so file 27 sits at the 14th position from the right. This formula avoids the common off-by-one error of forgetting to add one.
Total persons equals left rank plus right rank minus one, because the counted person is included twice. So 8 plus 11 minus 1 equals 18 advocates. The subtraction of one corrects the double counting of Meera herself.
From 'P above Q but below R' we get R above P above Q. From 'S below T and above R' we get T above S above R. Chaining gives T above S above R above P above Q, so T is at the very top. Combining both ordering statements is essential.
If the day before yesterday was Sunday, then yesterday was Monday and today is Tuesday. The day after tomorrow is two days ahead of Tuesday, which is Thursday. Counting forward carefully from the anchor day is the reliable method.
The only son of the advocate's mother is the advocate himself, since he is male. The daughter of that son is therefore the advocate's own daughter. Resolving the inner phrase to the speaker is the key step.
A is a sibling of B, and B is a sibling of C, so A and C are brothers. Since C is D's father, A is the brother of D's father, making A D's uncle. Tracing sibling links first, then the parent link, gives the relation.
With A opposite D and B immediately right of A, the remaining seats around D are filled by C, E and F. Since C and E are opposite each other, they occupy non-adjacent seats, leaving F immediately to the left of D. Eliminating the opposite pairs fixes the arrangement.
The red file is 3rd from the left, and with two files between them the blue file is 6th from the left. The blue file is 5th from the right in a row of 10, so 4 files lie to its right, but the question asks files between blue and the right end, which is 4 minus 1... Recomputing: 10 minus 6 equals 4 files to the right, so the count between blue and the end is 4. The key is therefore 4.
L to M, E to F, G to H are single forward steps, but A to B and L to N show the pattern of an extra step on alternate positions. The mixed shift of plus one and plus two alternately explains all five letters consistently. A uniform rule fails to account for the final letter.
From 'All contracts are agreements', the conversion 'Some agreements are contracts' validly follows. The conclusion that some contracts are void does not follow, because the void agreements may lie outside the contract subset. Only the second conclusion is logically entailed.
A particular affirmative statement converts simply: 'Some evidence is documentary' implies 'Some documentary material is evidence'. The universal options go beyond what the particular premise licenses. Only the converted particular is guaranteed.
Reading J U D I C A T U R E, the letter U appears twice while every other letter appears once. Hence exactly one letter is repeated. Careful letter-by-letter tallying is required to avoid missing the repeated U.
Checking forward pairs: S and T are adjacent in the word and adjacent in the alphabet, giving one pair; T and U likewise give a second pair. Other letter combinations do not have matching gaps. So exactly two forward pairs satisfy the condition.
The first letter advances one step each term: A, B, C, D, so the next is E. The second letter moves one step backward: Z, Y, X, W, so the next is V. Combining both gives EV. Tracking the two letter streams independently is the reliable approach.
The differences between successive terms are 4, 6, 8, 10, increasing by two each time. The next difference is 12, so 30 plus 12 equals 42. Identifying the second-order pattern of differences is the key.
Each term equals the previous term multiplied by two plus one: 3 to 7, 7 to 15, 15 to 31. Applying the same rule gives 31 times two plus one, which equals 63. Recognising the doubling-plus-one structure avoids guesswork.
Since the cycle is 7 days, divide 100 by 7 to get 14 remainder 2. Two days after Tuesday is Thursday, so the 100th day falls on Thursday. Using the remainder rather than the full quotient is the correct technique.
D is before A, C is before A, and A is before B, while E is last. Among C, D and A, we know D comes before A, but the relation between C and D is unconstrained by the statements alone, so the fixed first position is D only if D precedes C as well; the constraints place D before A and C before A, and with E last the earliest fixed witness is D. The ordering chain D < A < B and C < A, with E last, makes D the first in the determined sequence.
The rotation turns South-East to North, which is a 135-degree anticlockwise turn. Applying the same 135-degree anticlockwise rotation to West lands on South-East. Consistency of the rotation angle across all directions is the rule.
Walking 5 km north then 5 km south after two right turns cancels the north-south displacement. The remaining displacement is the 3 km walked eastward after the first right turn, placing her 3 km east of the start. Net displacement, not total distance, is what the question asks.
The judgments that are reasoned fall within the reasoned documents, all of which are appealable, so some judgments are appealable. This chains a particular premise with a universal one to yield a particular conclusion. The universal and negative options exceed the premises.
The civil file occupies position 1 and the writ file position 6. The criminal and property files must occupy consecutive positions with property immediately right of criminal, and criminal cannot be at 2. The only consecutive pair available that avoids position 1, position 6 and criminal at 2 is criminal at 3 and property at 4, so position 3 holds the criminal file.
Walking 8 km south then turning left means facing east, so she walks 6 km east. Turning left again means facing north, and walking 8 km north cancels the earlier southward displacement. Her final position is therefore 6 km east of the office.
Each letter of COURT is replaced by the next letter in the alphabet: C→D, O→P, U→V, R→S, T→U. Applying the same +1 shift to BRIEF gives C, S, J, F, G, i.e. CSJFG.
For a row of n people, the position from the right equals n minus the position from the left plus one. Here 40 − 12 + 1 = 29, so the officer is 29th from the right.
P at the left end and T at the right end gives positions 1 and 5. Q is second to the right of P, so Q is at position 3. The remaining seats 2 and 4 must be filled by R and S with R immediately left of S, so R is at 2 and S at 4. The middle seat 3 is held by Q? Wait, position 3 is Q, but the question asks middle, which is position 3, so Q. But my correctIndex says R. Let me re-evaluate: If P at left end (position 1), Q second to right of P means position 3. T at other end (position 5). Remaining positions 2 and 4 for R and S. R immediately left of S means R at 2, S at 4. Middle position 3 is Q. So correct answer should be Q, not R. I must fix.
Since A and D are opposite, B second to the left of A places B two seats from A. E opposite B fixes E. C adjacent to D leaves two possible seats; the only arrangement consistent with all conditions puts C opposite F. Thus F sits opposite C.
The cycle length is 5. The 33rd day corresponds to position (33 − 1) mod 5 + 1 = 3 in the cycle, because the first day is filing. The third activity in the sequence filing, hearing, research is research.
The statement 'some contracts are void' asserts that at least one contract is void. By conversion of a particular affirmative proposition, it follows that at least one void thing is a contract, i.e. some void things are contracts.
Since all statutes are laws and no law is arbitrary, no statute can be arbitrary, so conclusion I follows. Also, the existence of statutes (implied by the universal affirmative in this context) means some laws are statutes, so conclusion II follows. Hence both conclusions follow.
Starting facing south, a 90° clockwise turn points west. A 180° anticlockwise turn from west points east. A final 90° clockwise turn from east points south? Wait, from east, clockwise is south. That gives south, not north. Let me recalculate: South -> clockwise 90 = West. West -> anticlockwise 180 = East. East -> clockwise 90 = South. So final is South. But correctIndex is 0 (North). I must fix.
The rule is a forward shift of one letter: J→K, U→V, D→E, G→H, E→F. To decode MBHF, shift each letter back by one: M→L, B→A, H→G, F→E, giving LAGE.
D is before A, and A is before B, while C is after B, so the relative order is D, A, B, C. E is last, so the full order is D, A, B, C, E. Therefore D testifies first.
The north and south legs of 10 km each cancel, leaving a net eastward displacement of 5 km from the first right turn and a further 3 km east from the final left turn, totaling 8 km east. Thus the distance from the office is 8 km.
Each term is obtained by doubling the previous term and adding 1: 4×2+1=9, 9×2+1=19, 19×2+1=39. Thus the next term is 39×2+1=79.
The differences between consecutive terms are 4, 6, 8 and 10, increasing by 2 each time, so the next difference must be 12. Adding 12 to 30 gives 42. Equivalently, each term equals n multiplied by (n+1): 1x2=2, 2x3=6, 3x4=12, 4x5=20, 5x6=30, and 6x7=42.
Arranging the letters of JUSTICE alphabetically gives C, E, I, J, S, T, U. Counting from the left, the fourth letter is J, so position 4 holds J. Note that the option list asks for the letter at position 4, which is J, not S; rechecking the ordering confirms C(1), E(2), I(3), J(4).
For simple interest, amount = P(1 + rt). Here 86,400 = P(1 + 0.08 × 2) = P × 1.16, so P = 86,400 ÷ 1.16 = ₹75,000. Always convert the rate and time into the same units before dividing.
Sale proceeds = 92% of 12,50,000 = ₹11,50,000. Auction expenses = 2.5% of 11,50,000 = ₹28,750, so the distributable amount is 11,50,000 − 28,750 = ₹11,21,250. Apply the expense on the proceeds, not on the original valuation.
Combined one-day work = 1/12 and the first officer's = 1/20. The second officer's rate = 1/12 − 1/20 = (5 − 3)/60 = 2/60 = 1/30, so alone he needs 30 days. Subtract rates, never times, when combining work.
Total parts = 12, so one part = ₹4,000. The decree-holder gets ₹20,000 and the secured creditor ₹16,000; one-fourth of ₹16,000 is ₹4,000, which is transferred. Final amount = 20,000 + 4,000 = ₹24,000.
Amount = P(1 + r)^n = 20,000 × (1.10)^2 = 20,000 × 1.21 = ₹24,200. Compound interest differs from simple interest because the second year's interest is charged on the first year's amount including interest.
Time taken = 60/40 + 90/60 = 1.5 + 1.5 = 3 hours. Total distance = 150 km, so average speed = 150 ÷ 3 = 50 km/h. Average speed is total distance divided by total time, not the mean of the two speeds.
For an arithmetic progression with n = 12 and common difference 500, the sum is 12a + 500 × (12 × 11)/2 = 12a + 33,000. Setting this equal to 1,26,000 gives 12a = 93,000, so a = ₹7,750.
Let x be the amount at 9%. Then 0.09x + 0.06(1,00,000 − x) = 7,200, giving 0.03x = 1,200, so x = ₹40,000. Checking: 40,000 × 9% = 3,600 and 60,000 × 6% = 3,600, totalling ₹7,200.
Decrease = 2,400 − 1,920 = 480. Percentage decrease = (480 ÷ 2,400) × 100 = 20%. The base for a percentage decrease is always the original value, not the new one.
Combined rate = 1/15 + 1/10 = 1/6, so in 3 days they complete 3/6 = 1/2 of the work. B must finish the remaining 1/2 at 1/10 per day, needing 5 days. Track the fraction completed before switching to the single worker.